physics Test 2 In a double slit experiment, if the separation between the two slits is 0.050 mm and the distance from the slits to a screen is 2.5 m, find the spacing between the first-order and second-order bright fringes when coherent light of wavelength 600 nm illuminates the slits.

Answers

Answer 1
Answer:

Answer:0.015 m

Explanation:

Given

distance between two slits(d)=0.050 mm

Distance between slit and screen=2.5 m

Wavelength(\lambda )=600 nm

and distance between First order and second order=(D\lambda )/(2d)

=(2.5* 600* 10^(-9))/(2* 5* 10^(-5))

=15* 10^(-3)

=0.015 m


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An equilibrium constant is not changed by a change in pressure
a. True
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Answers

Answer:True

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Hi There! :)


An equilibrium constant is not changed by a change in pressurea. True
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False! :P

How could two waves on a rope interfere so that the rope did not move at all.

Answers

2 waves will overlap  

Heliocentric means… sun-centered. moon-centered. Earth-centered. galaxy-centered.

Answers

Heliocentric means aun-centered

Answer:

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Explanation:

What is the charge of the nucleus

Answers

Protons are positive, electrons are negative, and neutrons are neutral. In the nucleus, there are protons and neutrons, so the charge of a nucleus is positive

Europa, a satellite of Jupiter, is believed to have an ocean of liquid water (with the possibility of life) beneath its icy surface. Europa is 3130 km in diameter and has a mass of 4.78×10²² kg. In the future, we will surely want to send astronauts to investigate Europa.In planning such a future mission, what is the fastest that such an astronaut could walk on the surface of Europa if her legs are 0.960 m long?

Answers

Answer:

1.12 m/s

Explanation:

We are given that

Diameter of Europa=d=3130 Km

Radius of Europa =r=(d)/(2)=\fra{3130}{2}=1565 Km=1565* 10^3 m

1 km=10^3 m

Mass of Europa,m=4.78* 10^(22) kg

We have to find the velocity of astronaut on the surface of Europa if her legs are 0.960 m long.

d=0.960 m

Acceleration due to gravity on the surface of Europa

g=(GM)/(r^2)

Where G=6.67* 10^(-11)Nm^2/kg^2

Substitute the values

a=(6.67* 10^(-11)* 4.78* 10^(22))/((1565* 10^3)^2)

g=1.3 m/s^2

v=√(gd)=√(1.3* 0.960)=1.12 m/s

The swimming pool at perris hill plunge is 50 feet long and 25 feet wide. if the bottom of the pool is slanted so that the water depth is 3 feet at the shallow end and 15 feet at the deep end, what is the angle of elevation at the bottom of the pool?

Answers

The swimming pool at perris hill plunge is 50 feet long and 25 feet wide. if the bottom of the pool is slanted so that the water depth is 3 feet at the shallow end and 15 feet at the deep end,the angle of elevation at the bottom of the pool is calculated by Over a 50 foot (surface) length, there is a 12 foot (vertical) drop. tan A = 12/50 = 0.24 A = 13.5 degrees