Is a bimolecular reaction necessarily second-order? Is a second-order reaction necessarily bimolecular? Answer, with explanations and clarifications.

Answers

Answer 1

Answer: A bimolecular reaction is always a second-order reaction, but a second-order reaction is not always a bimolecular reaction.

The most important thing to take note of is that molecularity of a reaction is a concept applicable to only elementary reactions, meaning non-complex. In a way, elementary reactions are basic and achieved in one step. Complex reactions involve intermediate steps before achieving the desired reaction.

Molecularity is equal to the sum of the coefficients of the reactants, so two reactants give a second-order bimolecular reaction. However, second-order reactions can involve more than two reactants especially in complex reactions.

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Add 3 x 10^9 +5.3 x 10^10

Answers

Add 3 x 10^9 +5.3 x 10^10

3 x 10^9
+5.3 x 10^10
------------------
5.6 x 10^10

Answer:

3*10⁹ + 5.3*10¹⁰ = 5.6*10¹⁰

Explanation:

The values are given as exponents:

3*10⁹ and 5.3*10¹⁰

As per the rules:

-Before adding two numbers, all exponents must be the same

-The addition takes place between the numerical portion of the numbers

- The final value is rounded off to the least places in the decimal portion of the given numbers

Therefore, the two numbers to be added are:

$3*10^(9)+53*10^(9)=56*10^(9)$

Rounded off the final value to 1 decimal place gives:

5.6*10¹⁰

What type of reaction will occur when lead nitrate is mixed with the potassium iodide solution?

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Pb(NO3)2 + 2KI ---> PbI2↓ + 2KNO3

the precipitation reaction

What is quantitative and qualitative

Answers

Quantitative is a description in numbers , and qualitative is a description with words

Which hybrid orbitals would be formed if one s orbital and three p orbitals combined? sp sp2 sp3 sp4

Answers

Answer: Four $sp^3$ hybridized orbitals will formed when one s-orbital and three p-orbitals combines.

Explanation:

When ever one s-orbital combines with three p-orbitals it gives four $sp^3$ hybridized orbitals.
In which there is 25% of s character and 75% of p character.
The shape of the $sp^3$ hybridized orbitals is Tetrahedral. As shown in image attached.

sp3
it's just adding the number of s and p together
example of sp3 hybridization = CH4
with 1 s orbital of H and 3 p orbital of C

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