Scientists use results from new experiments to

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Answer 1

Answer:

Answer:

The scientists use results from the new experiments to change the existing explanations of how nature functions. The world is changing continuously. There are outcomes, which have been obtained from the scientific studies performed earlier, which may no longer be accurate at present because of certain factors that may not have been discovered or present in those times. Other scientific findings may also be further acknowledged as true from the outcomes of the new experiments.

Answer 2

Answer:

Final answer:

Scientists use results from new experiments to validate or refute existing theories and to explore new scientific territory. This is done by gathering and analyzing data from these experiments, ultimately leading to more informed and detailed theories.

Explanation:

Scientists use results from new experiments to both confirm existing theories and explore new territories of knowledge. Conducting an experiment helps scientists gather data and observations. These results then provide evidence that either supports or refutes a hypothesis, leading to more advanced and precise scientific theories. For example, when Albert Einstein proposed his theory of relativity, further experiments such as the Eddington experiment during a solar eclipse provided data evidence that supported his theory.

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Where does the energy from the nuclear reaction go?

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The energy fro the nuclear reaction go on to split other nearby atoms

I hope that's help !

Use electron transfer or electron shift to identify what is oxidized and what is reduced in each reaction :a) 2Na(s) + Br2(l) ----> 2NaBr(s)
b) H2(g) + Cl2(g) ----> 2HCl(g)
c) 2Li(s) + F2(g) ----> 2LiF(s)
d) S(s) + Cl2(g) ----> SCl2(g)
e)N2(g) + 2O2(g) ----> 2NO2(g)
f) Mg(s) +Cu(NO3)2(aq) = Mg(NO3)2(aq) + Cu(s)

For each reaction above, identify the reducing agent and the oxidizing agent

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Answer :

Oxidation-reduction reaction : It is a type of reaction in which oxidation and reduction reaction occur simultaneously.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In the oxidation reaction, the oxidation state of an element increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In the reduction reaction, the oxidation state of an element decreases.

(a) The balanced chemical reactions is,

$2Na(s)+Br_2(l)\rightarrow 2NaBr(s)$

Half reactions of oxidation and reduction are :

Oxidation : $Na\rightarrow Na^(1+)+1e^-$

Reduction : $Br_2+2e^-\rightarrow 2Br^(1-)$

From this we conclude that, 'Na' is oxidized and $'Br_2'$ is reduced in this reaction. The reducing agent is, 'Na' and oxidizing agent is, $'Br_2'$ .

(b) The balanced chemical reactions is,

$H_2(g)+Cl_2(g)\rightarrow 2HCl(g)$

Half reactions of oxidation and reduction are :

Oxidation : $H_2\rightarrow H^(1+)+1e^-$

Reduction : $Cl_2+2e^-\rightarrow 2Cl^(1-)$

From this we conclude that, $'H_2'$ is oxidized and $'Cl_2'$ is reduced in this reaction. The reducing agent is, $'H_2'$ and oxidizing agent is, $'Cl_2'$ .

(c) The balanced chemical reactions is,

$2Li(s)+F_2(g)\rightarrow 2LiF(s)$

Half reactions of oxidation and reduction are :

Oxidation : $Li\rightarrow Li^(1+)+1e^-$

Reduction : $F_2+2e^-\rightarrow 2F^(1-)$

From this we conclude that, 'Li' is oxidized and $'F_2'$ is reduced in this reaction. The reducing agent is, 'Li' and oxidizing agent is, $'F_2'$ .

(d) The balanced chemical reactions is,

$S(s)+Cl_2(g)\rightarrow SCl_2(g)$

Half reactions of oxidation and reduction are :

Oxidation : $S\rightarrow S^(2+)+2e^-$

Reduction : $Cl_2+2e^-\rightarrow 2Cl^(1-)$

From this we conclude that, 'S' is oxidized and $'Cl_2'$ is reduced in this reaction. The reducing agent is, 'S' and oxidizing agent is, $'Cl_2'$ .

(e) The balanced chemical reactions is,

$N_2(g)+2O_2(g)\rightarrow 2NO_2(g)$

Half reactions of oxidation and reduction are :

Oxidation : $N_2\rightarrow N^(4+)+4e^-$

Reduction : $O_2+4e^-\rightarrow 2O^(2-)$

From this we conclude that, $'N_2'$ is oxidized and $'O_2'$ is reduced in this reaction. The reducing agent is, $'N_2'$ and oxidizing agent is, $'O_2'$ .

(f) The balanced chemical reactions is,

$Mg(s)+Cu(NO_3)_2(aq)\rightarrow Mg(NO_3)_2(aq)+Cu(s)$

Half reactions of oxidation and reduction are :

Oxidation : $Mg\rightarrow Mg^(2+)+2e^-$

Reduction : $Cu^(2+)+2e^-\rightarrow Cu$

From this we conclude that, $'Mg'$ is oxidized and $'Cu'$ is reduced in this reaction. The reducing agent is, 'Mg' and oxidizing agent is, 'Cu'.

a) Na is oxidised Br is reduced
b) H is oxidised Cl is reduced
c) Li is oxidised F is reduced
d)S is oxidised Cl is reduced
e) N is oxidised O is reduced
f) Mg is oxidised and N is reduced

Remember: Oxidation= loss and Reduction= gains

Semantics is the study of:

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relationships between words and how we construct meaning.

Hydrogen bonding is a type of(1) strong covalent bond
(2) weak ionic bond
(3) strong intermolecular force
(4) weak intermolecular force

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Option 3. strong intermolecular force

Certain substances such as H2O, HF, NH3 from hydrogen bonds, and the formation of which affects properties (mp,bp,solubility) of substance. Other compounds containing OH and NH2 groups also form hydrogen bond. Molecules of many organic compounds such as alcohols, acids, amines, and amino acids contain these groups, and thus hydrogen bonding plays an important role in biological science.

At the same temperature and pressure, 1.0 liter of CO(g) and 1.0 liter of CO2(g) haveA. equal masses and the same number of molecules
B. different masses and a different number of molecules
C. equal volumes and the same number of molecules
D. different volumes and a different number of molecules

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Answer is C - equal volumes and the same number of molecules.

Explanation;

Let's assume that CO and CO₂ are ideal gases. Then we can use ideal gas law, PV = nRT

Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol⁻¹ K⁻¹) and T is temperature in Kelvin.

The temperature and the pressure of the both gases are same. Volume is also same as 1.0 L. R is a constant. So according to the formula, both gases have same number of moles. According to the Avogadro's constant, 1 mole has 6.022 x 10²³ particles.

number of molecules = Avogadro's constant x number of moles.

Hence, under the same conditions both gases have same number of molecules.

C is the correct answer. All gases have the same volume under the same conditions.. This is just their nature. And one liter of a gas has the same number of molecules of another gas

A piece of sodium metal can be described as

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A piece of sodium metal can be described as a soft silvery white metal that is highly reactive and can sometimes cause explosions. This is the reason why it doesn't occur naturally as an isolated metal. Instead, different sodium containing compounds undergo different processes to isolate the sodium metal.

Answer:

D. a pure substance and an element.

Explanation:

IM JUST HIM

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