MATHEMATICS HIGH SCHOOL

Which ordered pairs lie on the graph of the exponential function f(x)=−3^2x+5 ? Select each correct answer. (−2, 76) (3,−724) (0, 4) (1,−4)

Answers

Answer 1

Answer:

Answer:

(0,4) (1,-4)

Step-by-step explanation:

Answer 2

Answer:

Plugging in values, we get that (1,-4) works.

$f(1)=-3^(2*1)+5=-3^2+5=-9+5=-4$

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Half of a number decreased by 8 is -3

Answers

Answer: 10

Step-by-step explanation: work your way backwords. first add 8 to get 5. Then half is 1/2, so you then multiplt by 2. hope this helped! sorry for short explanation

What is the first step in writing f(x) = 6x2 + 5 – 42x in vertex form?Factor 6 out of each term.
Factor 6 out of the first two terms.
Write the function in standard form.
Write the trinomial as a binomial squared

Answers

f(x) = 6x² + 5 - 42x

first step in writing the f(x) in vertex form? WRITE THE FUNCTION IN STANDARD FORM.

f(x) = 6x² - 42x + 5

Exponents must be in decreasing order.

Answer:

Option 3rd is correct

Write the function in standard form.

Step-by-step explanation:

The standard form of the quadratic equation is given by:

$y=Ax^2+Bx+C$

As per the statement:

Given the function:

$f(x) = 6x^2+5-42x$

We have to find the first step writing f(x) vertex form.

Firstly, write the given function in standard form

by definition we have;

$f(x) = 6x^2-42x+5$

Therefore, the first step writing f(x) vertex form is, Write the function in standard form.

What's the square root of 68?

Answers

$√(68)=√(4\cdot17)=\sqrt4\cdot√(17)=2√(17)\n\n√(68)\approx8.25$

Which statement implies that A and B are independent events?A. P(B|A) = P(B A)

B. P(B|A) = P(B)
P(A)
C. P(B|A) = P(A)

D. P(B|A) = P(B)

Answers

The events $A,B$ are independent if and only if $P(A\cap B)=P(A)\cdot P(B)$ . Under this condition, we have conditional probabilities

$P(A\mid B)=(P(A\cap B))/(P(B))=(P(A)\cdot P(B))/(P(B))=P(A)$

$P(B\mid A)=P(B)$

so the answer is D.

Answer:

The answer is D.

Step-by-step explanation:

When creating a scatterplot, if the points are too close together to see the relationship, how could you adjust your graph?A.
decrease your scale values
B.
increase your scale values
C.
plot more points
D.
plot fewer points

Answers

The correct answer for this question is this one: "B. increase your scale values"

When creating a scatterplot, if the points are too close together to see the relationship, You adjust your graph by increasing your scale values
Hope this helps answer your question and have a nice day ahead.

Answer:

Option: B is correct.

B) Increase your scale values.

Step-by-step explanation:

When creating a scatterplot, if the points are too close together to see the relationship,then we must increase the scale value of our graph .

" Because by doing so the point will seem to be farther and we could see the clear relationship between the points and hence it will not create any confusion regarding the visual of the points and hence easily the inference could be drawn"

Hence, option: B is true.

(B) Increase the scale value)

To the nearest hundredth of a second, how much time does it take a car to travel 50 feet from a stop at a constant acceleration of 3. 2 ft/s²? Use d=1/2at², where d represents distance, a represents acceleration, and t represents time in seconds. (pic above)

Answers

$d=(1)/(2)at^2\n\nWe\ have:\n\nd=50\ ft,\ a=3.2(ft)/(s^2)\n\nSubstitute:\n\n(1)/(2)\left(3.2(ft)/(s^2)\right)t^2=50\ ft\n\n1.6(ft)/(s^2)t=50\ ft\qquad\text{divide both sides by}\ 1.6(ft)/(s^2)\n\nt^2=50\ ft\cdot(1)/(1.6)(s^2)/(ft)\n\nt^2=(50)/(1.6)s^2\n\nt^2=(500)/(16)s^2\to t=\sqrt{(500)/(16)s^2}\n\nt=(√(500))/(√(16))s\n\nt=(√(100\cdot5))/(4)s\n\nt=(√(100)\cdot\sqrt5)/(4)s\n\nt=(10\sqrt5)/(4)s\approx5.59\ s$

$Answer:\ \boxed{5.59\ s}$

Final answer:

Using the given equation and values, we can calculate that it would take approximately 5.59 seconds for a car to travel 50 feet from a stop with a constant acceleration of 3.2 ft/s².

Explanation:

To solve this physics problem, we'll need to use the equation d=1/2at². Here, 'd' represents distance, 'a' represents acceleration, and 't' represents time. Here, we are given 'd' as 50 feet and 'a' as 3.2 ft/s². Now we just need to isolate 't' and solve for time.

Start with the given equation: d=1/2at².
Substitute the given values: 50=1/2*3.2*t².
Remove the fraction by multiplying all terms by 2: 100=3.2*t².
Divide both sides by 3.2 to isolate t²: t²=31.25.
Take the square root of both sides to solve for 't': t=√31.25.
So, t ≈ 5.59 s (rounded to the nearest hundredth).

To summarize, a car traveling 50 feet from a stop with a constant acceleration of 3.2 ft/s² would take approximately 5.59 seconds. Always remember to isolate the unknown in your equation and solve step-by-step for these types of problems.