What adds to get 12 and multiply to 45

Answers

Answer 1

Answer: the answer is 3 and 15

Answer 2

Answer: 3! Because:

3 + 3 + 3 + 3 = 12
and
3 x 15 = 45

Related Questions

Solve by elimination8x+9y=-55-8x+y=65
The product of 2.5 and a number t
Eric has saved $18,300 toward a down payment on a house. He makes a salary of $59,750 a year. What is the maximum he could afford to borrow to buy a house?a) $90,500 b) $101,200 c) $119,500 d) $137,800
X + x - 5 greater than equal to 33
Questions that are circled with work please

Help help help need to bring my f up in math

Answers

( 4,20)is the correct answer

Answer:

(4,20)

Step-by-step explanation:

The table shows the ordered pair (4, 16), meaning that (4, 20) wouldn't fit.

I need these answers ASAP

Answers

Answer:

irratrrational Numbers

whole

real

Step-by-step explanation:

Tickets to a school dance cost $4 and the projected attendance is 300 people. For every $0.10 increase in ticket price, the dance committee projects that attendance will decrease by 5.Using formula R(4+.10t) (300-5t) where t is ticket price.

Determine the dance committee's greatest possible revenue. (Please show work as in #'s)

What ticket price will produce the greatest revenue? (Please show work as in #'s)

Answers

money made (R) = tickets sold * price of ticket
the number of $0.10 increases we make will be called t. so:
price of ticket = $4 + $0.10t
tickets sold = 300 - 5t
R = (4 + .10t)(300 - 5t)
R = 1200 + 10t - .5t^2
R = -1/2t^2 + 10t + 1200
to find the maximum, we have to find the roots of this function.
0 = -1/2t^2 + 10t + 1200
0 = -t^2 + 20t + 2400
0 = t^2 - 20t - 2400
quadratic formula
t = 20 +- sqrt((-20)^2 - 4(1)(-2400)) all over 2(1)
t = 20+-sqrt(400+9600) all over 2
t = 20+-sqrt(10000) all over 2
t = 20+-100 all over 2
t = -80/2 or t=120/2
t = -40 or 60
now find the average of these roots. this will find the "middle" of the parabola, which is where the vertex (maximum) will be.
-40 + 60 all over 2
20/2
10
the vertex is at t=10. plug this into the formula:
R = -1/2t^2 + 10t + 1200
R = -1/2(10)^2 + 10(10) + 1200
R = 50 + 100 + 1200
R = 1350
therefore, the number of 10 cent price increases should be 10, because that will lead to total profits of $1350, the maximum possible. the ticket price will be $5.

Choose the correct simplification of x to the 3rd power over y to the 5th power all raised to the 2nd power.x to the 5th power over y to the 7th power
x over y to the 3rd power
x to the 6th power over y to the 10th power
x6y10

Answers

Answer:

Option 3 - x to the 6th power over y to the 10th power

Step-by-step explanation:

Given : Expression x to the 3rd power over y to the 5th power all raised to the 2nd power.

To find : Choose the correct simplification of the expression?

Solution :

Writing the expression in value form,

x to the 3rd power = $x^3$

y to the 5th power= $y^5$

x to the 3rd power over y to the 5th power all raised to the 2nd power =

$((x^3)/(y^5))^2$

Now applying identity,

$((x)/(y))^a=(x^a)/(y^a)$

$=((x^3)/(y^5))^2$

$=((x^3)^2)/((y^5)^2)$

Using identity, $(x^a)^b=x^(a.b)$

$=(x^(3.2))/(y^(5.2))$

$=(x^(6))/(y^(10))$

In word form, x to the 6th power over y to the 10th power.

Therefore, Option 3 is correct.

$\left( \cfrac{x^3}{y^5} \right)^2=\cfrac{(x^3)^2}{(y^5)^2}=\cfrac{x^(3*2)}{y^(5*2)}=\cfrac{x^(6)}{y^(10)}$

Assuming that there are 10 digits used as telephone number and the area code is a fixed 3 digit number. How many different telephone numbers could be created?

Answers

9,999,999,999,987 Of course, if 'numbers' with leading digits e.g. 0 000 087 654 321, and all zeros, are not counted as valid 'numbers' then there are 13 less possibilities. i.e. There are only 9,999,999,999,987 possibilities.

What is the answer to 8t-3=9

Answers

8t-3=9
Add 3 to both sides
8t=12
Divide 12 by 8
Final Answer: t=1.5

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