Which is a correct set of values of m for one of the subshells of n = 2? –1, 0, 1 –1, –2, 0, 1, 2 –1, –2, –3, 0, 1, 2, 3 –1, –2, –3, –4, 0, 1, 2, 3, 4

Answers

Answer 1

Answer: For the principal quantum number, n, its corresponding sets of magnetic quantum, m, values depend on the angular quantum values, l. For n=2, the values of l are from 0 to (n-1), which are 0 and 1. For each value of l, the m value that corresponds to it is given by m = -l, ..., 0, ..., +l. This gives a set of m values equial to m = -1, 0, 1.

Answer 2

Answer:

Answer:

Explanation:

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Critical thinking requires that

An ideal gas _____. does not exist
perfectly obeys all gas laws
only exists at very low temperatures
only exists at very high pressures

Answers

THE ANSWERS ARE A AND B!!!!

HOPE I HELPED

Answer:

does not exist

perfectly obeys all gas laws

Explanation:

Ideal gases is a simplification of real gases that is made to study them more easily. Then a hypothetical or theoretical, that is to say, imaginary gas is considered ideal gases. Despite not representing a gas that really exists, the ideal gas is a tool to facilitate a large number of mathematical calculations

The ideal gas behavior is at low pressures and high temperatures.

The ideal gas equation is based condensing Boyle's law, Gay-Lussac's, Charles's and Avogadro's law:

P * V = n * R * T

where:

P = pressure
V = volume
n = number of moles
R = universal gas constant
T = temperature

In this way an ideal gas perfectly obeys all gas laws.

Calculate the density of argon gas at a pressure of 753 mmHg and a temperature of 35 °C

Answers

The density of Argon gas at a pressure of 753 mmHg and a temperature of 35 °C is equal to 1.59 g/L.

What is the ideal gas equation?

The state of a quantity of gas is calculated by its pressure, volume, and temperature. The ideal gas law can be explained as the product of the volume and pressure of gas is equal to the multiplication of the universal gas constant and absolute temperature.

The mathematical equation for an ideal gas can be written as follows:

PV = nRT

PV =(m/M) RT

PM/RT = m/V

d = PM/RT

Where n is the moles of gas, T is the temperature of the gas, V is the volume of the gas, and R is the gas constant.

Given, the temperature of argon gas, T = 35 °C = 35 +273 = 308 K

The pressure of the argon gas, P = 753 mmHg = 1.01 atm

The molar mass of the Argon gas, M = 40 g/mol

Substitute V, R, P, and T in the ideal gas equation, we get:

The density of Argon gas, d = PM/RT

d= 1.01 ×40/(0.082 × 308)

d = 1.59 g/L

Therefore, the density of Ar gas is 1.59 g/L.

Learn more about ideal gas equation, here:

brainly.com/question/3637553

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PV=nRT
PV= (m/M)RT
PM=(m/v)RT
PM =dRT
d= (PM) ÷(RT)

substitute the the given data to the above equation. d-density, p-pressure, M- molar mass of argon gas, T- temperature. and R is a constant. make sure to substitute its value too.. :)

Which is a molecule?
A. Ne
B. NaCL
C. Trail Mix
D. graphene

Answers

B) NaCl is a molecule.

An evaporation-crystallization process is used to obtain solid potassium sulfate from an aqueous solution of this salt. The fresh feed to the process contains 19.6 wt% K₂SO₄. The wet filter cake consists of solid K₂SO₄ crystals and a 40.0 wt% K₂SO₄ solution, in a ratio 10.0 kg crystal/kg solution. The filtrate, also a 40.0 wt% K₂SO₄ solution, is recycled to join the fresh feed. Of the water fed to the evaporator, 45.0% by weight is evaporated. The evaporator has a maximum capacity of 175. kg water evaporated/s. a) Assume the process is operating at maximum capacity. Draw and label a flowchart and do the degreeof-freedom analysis for the overall system, the recycle-fresh feed mixing point, the evaporator, and the crystallizer.
b) Calculate the maximum production rate of solid K₂SO₄, the rate at which fresh feed must be supplied to achieve this production rate, and the recycle ratio kg/h recycled stream to kg/h fresh feed stream.

Answers

Answer:

From the degree of freedom analysis, the degree of freedom of the system and its components are equal to zero hence the system is well defined

Explanation:

To appraise the evaporation-crystallisation process, we go over the system to check if it is well defined from the available information as follows

45% by weight of inlet water is evaporated hence where inlet consists of 19.6% by weight of K₂SO₄ we have, Molar mass of K₂SO₄ = 174.259g/mol. Thus for every mole of K₂SO₄, we have 174.259×100/19.6 = 889.1g of solution is fed per mole of K₂SO₄,

Also the stream of concentrate leaving the evaporator contains

889.1 – 174.259 = 714.7 grams of water, and if 45% by weight of water is evaporated we have

45% of 889.1 is evaporated leaving a solution of weight = 889.1 × 55/100 = 489grams of solution which contains

100×174.259÷489 or 35.6% by weight of K₂SO₄ concentrate leaving the evaporator and moving on to the evaporator

However, 175. kg of water is evaporated/s hence from the previous calculation, quantity of water per mole of K₂SO₄ evaporated = 0.45×889.1= 400.1g which in comparison with actual quantity gives mass flow into

0.4001/175 = 0.003 or 437.39 to 1 hence the mass flow rate is 889.1g×437.39 = 388884g/s or 388.9Kg/s

a. Degrees of freedom analysis for the overall system

We have the following 4 unknowns in the overall system viz

m1, m3, m4 and m5

where m1 = maximum mass flow rate into the system

m3 = mass rate of evaporated water

m4 = maximum mass of solid K₂SO₄ crystals produced from the crystallizers

m5 = recycle ratio

While we have

1) Information, maximum capacity of evaporation from where we can calculate the maximum rate of feed supply

2) information, including chemical formula, to determine the maximum production rate

3) Information to calculate the water evaporated from fraction of water which is evaporated to that which is supplied

4) information to calculate the recycle ratio

Hence degrees of freedom = 4 – 4 =0

b. Degree of freedom analysis for the recycle-fresh feed mixing point

For the recycle-fresh feed mixing point we have m1 and m5, two unknowns

Where m1 is maximum feed rate and m5 is the mass of filtrate and we are given the compound molecular formula and the maximum flow rate from where we can calculate both m1 and m5

Hence the degrees of freedom = 0

c. Degree of freedom analysis for the evaporator

For the evaporator we have three unknowns m1,m2 and m3 and the available information are

1. The maximum water processing capacity of the evaporators and

2. The percentage quantity of water evaporated

Which is 2 hence we have 2 – 2 = 0 degrees of freedom

and

d. Degree of freedom analysis for the crystallizer the unknowns are m2, m4, m5

For the crystallizer the unknowns are m2, m4, m5The information available are

1. the ratio of crystals per kilogram of solution

2. The concentration of the recycled K₂SO₄ solution

3. Information of the maximum capacity of the evaporator so as to calculate the mass of concentrates leaving the evaporator and moving towards the crystallizer

Hence, we have 3 -3 = 0 degrees of freedom

From the degree of freedom analysis, the degree of freedom of the system and its components are zero hence the system is well defined

Since a element has a pH number of 7, meaning it is ______. That element can be classified as neither a ____ or a _____. Also, is this a balanced equation?

C4 + O2 -----> 4CO + O2

Answers

If a number has a pH of 7, it is neutral, therefore, one blank is neutral.

1. Neutral

Therefore, the element is not an acid or a base.

2. Acid, Base

That is NOT a balanced equation because:

c=4 o=2
c=4 o = 6

Not balanced, o has 6 and one side it has 4. It contradicts the Law of conversation of mass.

- - Since a element has a pH number of 7, meaning it is neutral. That element can be classified as neither a acid or a base.
- - No this is not balanced.
- - This is because its no balanced considering the o has 6 sides and 4 has one.
- - Because of this it is not true based on the com (conversion of mass) This law was made by Antoine Lavoisier and using his law I was able to know that it was not a balanced equation.

What evidence caused Thomson to change Dalton's solid sphere model into the plum pudding model?

Answers

He found that the cathode ray elements have even negligible mass as compared to atoms. So he found that electrons are actually subatomic particles of an atom. That is why he suggested the plum pudding model.
Explanation:
He discerned that atoms contain charged particles, that he was known as electrons.
In chemist theoryThe indivisibility of associate, degree atom was proved wrong: associate degree atom is often any divided into protons, neutrons and electrons. but associate degree atom is that the smallest particle that takes part in chemical reactions. in step with a chemist, the atoms of the same part are similar all told respects.

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