A 60-gram sample of radioactive isotope is measured after two half-lives have passed. What pair of percentages describe the sample after two-half lives? A.) 50% unchanged and 50% stable B.) 25% unchanged and 75% stable C.) 12.5% unchanged and 87.5% stable D.) 75% unchanged and 25% stable

Answers

Answer 1
Answer:

Answer: B.) 25% unchanged and 75% stable

Explanation:

Now, to calculate the initial amount of radioactive isotope

a=(a_o)/(2^n)

where,

a = amount of reactant left after n-half lives = 60 g

a_o = Initial amount of the reactant = ?

n = number of half lives= 2

Putting values in above equation, we get:

60=(a^0)/(2^2)

a_0=240g

Thus percentage of sample unchanged=(60)/(240)* 100\%=25\%

The percentage of sample decayed or has become stable=(180)/(240)* 100\%= 75\%

Answer 2
Answer:

Answer:

B. 25% unchanged and 75% stable

Explanation:

Edge 2021


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