Which base is the strongest for the given [H+]? 10-9 10-11 10-10 10-12

Answers

Answer 1

Answer:

Answer:

[H⁺] = 10⁻¹²

It could be the strongest base.

Explanation:

The base is considered to be of highest strength if it has least hydrogen ion concentration or high hydroxide ion concentration.

Generally a stronger base gives more hydroxide ion concentration.

the relation between hydrogen ion and hydroxide ion concentration is

[H⁺][OH⁻]= 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ / [H⁺]

a) [H⁺] = 10⁻⁹

[OH-] = 10⁻⁵

b) [H⁺] = 10⁻¹¹

[OH-] = 10⁻³

c) [H⁺] = 10⁻¹⁰

[OH-] = 10⁻⁴

d) [H⁺] = 10⁻¹²

[OH-] = 10⁻²

This the highest concentration of hydroxide ion in the given choices so it could be the strongest base.

Answer 2

Answer: The answer is 10-12. The strongest base has the lowest concentration of H+
Hope this helped

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If 20.0 mL of Ca(OH)2 with an unknown concentration is neutralized by 37.5 mL of 0.124 M HCl, what is the concentration of the Ca(OH)2 solution? Show all of the work needed to solve this problem. Ca(OH)2 + 2 HCl yields 2 H2 O + CaCl2

Answers

You first need to write the balanced chemical reaction for what is going on.
Ca(OH)₂+2HCl→2H₂O+CaCl₂

After you make the balanced chemical reaction, First you find the moles of HCl used. To do this multiply 0.0375L by 0.124M to get 0.00465mol HCl. Then you multiply 0.00465mol HCl by (1mol Ca(OH)₂)/(2mol HCl) to get 0.002325mol Ca(OH)₂. Finally to find concentration of Ca(OH)₂ used you divide 0.002325mol by 0.020L to get 0.116M Ca(OH)₂.
Therefore the concentration of the unknown solution of Ca(OH)₂ was 0.116M.

I hope this helps. Let me know if anything is unclear.

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Answers

B. product
Think about it like this: a company produces products, not coefficients.

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Answers

Kelvin is a unit for temperature. The temperature of the car motor oil must have been measured and described. At 0 degree Celsius or freezing point of water, there is 273 Kelvin. At the boiling point of water, it reads 373 Kelvin. This is the standard used by scientists in solving in equations. However, Celsius and Fahrenheit are common to daily basis.

Calculate the pH of a 0.30 M NaF solution. The Ka value for HF is 7.2*10^-4

Answers

This problem uses the relationship between Kb and the the dissociation constants which is expressed as Kw = KaKb. Calculations are as follows:

Kb = KaKb
1.00 x 10^-14 = 7.2 x 10^-4(x)
x = 1.39 x 10^-11

We now need to calculate the [OH¯] using the Kb expression:

1.39 x 10^-11 = x^2 / (0.30 - x)

The denominator can be neglected. Thus, x is 3.73 x 10^-6.

pOH = -log 3.73 x 10^-6 = 5.43
pH = 14-5.43 = 8.57

Answer:

pH=8.32

Explanation:

The relevant equilibrium for this problem is

F⁻ + H₂O ↔ HF + OH⁻

With a constant Kb of

Kb= $([HF][OH^(-)])/([F^(-)])$