Can someone help? anyone who's taking like geometry?

Answers

Answer 1

Answer: The triangles are similar so corresponding sides will be in ratio. The first triangle has sides of 2, 4, and 6. The second triangle has a largest side of 24. You are asked to find the perimeter of the second triangle.
The largest side of the first triangle is 6 and the largest side of the second triangle is 24. This is a ratio of 6:24 which can be reduced to 1:4.
Each side of the second triangle is 4 times as large as the corresponding side of the first triangle.
Now we can calculate the other 2 sides.
2 x 4 = 8
4 x 4 = 16
The three sides are 8, 16 and 24
Perimeter of this triangle is 8 + 16 + 24 = 48

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1. Each of 9 friends chooses her favorite positive integera. The median of the chosen number is 91, what is the smallest the average of the 9 chosen numbers could be?

b. The median of the chosen number is 91, is there an limit to how large the aerge of the chosen numbers can be? If so, what is the largest the average can be?

c. The average of the chosen number is 91, what is the smallest the median of the 9 chosen numbers could be?

d. The average of the chosen numbers is 91. What is the largest the median of the chosen numbers could be?

Answers

Answer:

a) 1

b) There is no limit to which the largest number can be because we are only given information about the median.

c) 1

d) 90

Final answer:

The smallest average is 49 and the largest average is 91. The smallest median is 91 and the largest median is also 91.

Explanation:

a. Since the median is 91, at least 5 friends must choose numbers greater than or equal to 91, and at most 4 friends can choose numbers less than 91. To minimize the average, let's assume the four friends choose the smallest possible numbers less than 91 (1, 2, 3, and 4). The remaining five friends can then choose 91, 91, 91, 91, and 91. The average of the nine chosen numbers is (1 + 2 + 3 + 4 + 91 + 91 + 91 + 91 + 91)/9 = 49.

b. There is no limit to how large the average of the chosen numbers can be. The nine friends can all choose the same number, such as 91, which would make the average 91.

c. Since the average is 91, let's assume the eight friends choose the smallest possible numbers less than 91 (1, 2, 3, ..., 8). The remaining friend can then choose a number greater than or equal to 91. To minimize the median, the friend can choose the smallest possible number greater than or equal to 91, which is 91. So, the smallest median would be 91.

d. Since the average is 91, let's assume the eight friends choose the largest possible numbers less than 91 (84, 85, ..., 91). The remaining friend can then choose a number greater than or equal to 91. To maximize the median, the friend can choose the largest possible number greater than or equal to 91, which is 91. So, the largest median would also be 91.

Learn more about median and average of chosen numbers here:

brainly.com/question/33899535

#SPJ2

5.567 round hundredths

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5.57 because 5 is the tenths 6 is hundredths 7 is thousandths

556.7, I am really good at decimals and fractions, just mainly math, science, literature, and some Economics

Plot the data points on the graph below. Make sure you use the corresponding color dot for the point according to the following: 1st point - yellow dot, 2nd point - blue dot, 3rd point - green dot, 4th point - red dot, 5th point - pink dot, 6th point - purple dot. x values y values 1 18 2 9 3 6 6 3 9 2 18 1 (Inverse relationship, k = 18)

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Hello,

Please, see the attached graph.

Thanks.

Answer: :)

Step by Step: :)

I need the answers for the seven angels

Answers

Answer:

<1=83

<2=97

<3= 83 (given)

<4=97

<5=83

<6=97

<7=83

<8=97

Step-by-step explanation:

They give you the angle for 3 which is 83, so from there all you have to do is find the equivalent angles which are angle 1,5,7. Then for angles 2,4,6,8 you subtract 83 from 180 and you get 97.

CAN SOMEBODY PLEASE HELP ME I AM SO CONFUSEDD

Answers

The formula for the surface area of a cylinder is 2πrh+2πr². R is the radius and h is the height.

2πrh+2πr²
2(3.14)(1.3)(4.8)+2(3.14)(1.3)²
39.19+10.61
=49.8

I hope this helped.

The arithmetic mean (A) of two numbers (a and b) is given by the formula A=a b2, and their geometric mean (G) is given by G=ab−−√. Their harmonic mean (H) is given by the formula G=AH−−−√. Which formula correctly gives H in terms of a and b?

Answers

Answer:

$H = (2ab)/(a+b)$

Step-by-step explanation:

As per the given statement:

The arithmetic mean (A) of two numbers (a and b) is given by the formula:

$A = (a+b)/(2)$ .....[1]

and

their geometric mean (G) is given by :

$G = √(ab)$ .....[2]

Their harmonic mean (H) is given by the formula:

$G = √(AH)$

Squaring both sides we get;

$G^2 = AH$

Substitute the given values we have;

$(√(ab))^2 =(a+b)/(2) \cdot H$

⇒ $ab = (a+b)/(2) \cdot H$

Multiply by 2 both sides we have;

$2ab = a+b \cdot H$

Divide both sides by a+b we have;

$(2ab)/(a+b) =H$

$H = (2ab)/(a+b)$

Therefore, the formula correctly gives H in terms of a and b is, $H = (2ab)/(a+b)$

$G=√(AH) \n G^2=(√(AH))^2 \nG^2=AH \nH=(G^2)/(A) \n \n A=(a+b)/(2) \hbox{ and } G=√(ab) \n \Downarrow \nH=(G^2)/(A)=((√(ab))^2)/((a+b)/(2))=(ab)/((a+b)/(2))=ab * (2)/(a+b)=(2ab)/(a+b) \n \n\boxed{H=(2ab)/(a+b)}$