What is the volume of the following rectangular prism?
Answers
Answer: The required volume of the given rectangular prism is
Step-by-step explanation: We are given to find the volume of the rectangular prism shown in the figure.
We know that
the VOLUME of a rectangular prism with base area b sq. units and height h units is given by
For the given rectangular prism, we have
Therefore, the VOLUME of the given rectangular prism is
Thus, the required volume of the given rectangular prism is
How:
7 1/3 times 2 is 14 2/3
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Plz help, I need answers to these questions ASAP, would appreciate a short step-by-step explanation with each! WILL MARK BRAINLIEST!!!You’ve been given $500.00 for your fencing. So first we are going to make as big of a rectangular field as we can with the money that we have for the fencing to surround it. The cost of premium fencing (only the best for your farm, of course) is $11.41 per metre. So with that, and the following equations:A=l*wP=2l+2wWhere A is the area, P is the perimeter, l is the length, and w is the width of a rectangle, we can find the maximum area that we can have for this field.Perimeter of fence:Area of farm:Let’s say we have access to planting 2 different crops, Watermelons and Grapes. We can find the revenue of a crop by the equation:R = (p0 + px)(n0 - nx)Where R is the revenue, p0 is the starting price, n0 is the amount sold at the starting price, p is the price increase, n is the decrease in the amount sold per price increase, and x is the number of price increases.Crop A: Watermelons have a starting price of $12.00 per m2 of area sold. At this price, you can sell 45 m2 worth. For every $2.00 increase, you will sell 1 m2 less. So the first task is to figure out how to put these values into the equation above and turn it into a quadratic function. Then you will need to find the value of x to make the revenue as large as possible. Once you know x, the number of price increases, you can then find what you should price your Watermelons per m2.Equation: R =Number of price increases: x =Price of Watermelon per m^2 =Okay, now we can do the same thing with the grapes, just to give you that extra practice with quadratic functions. The starting price of grapes per m² is $8.00, at which you can sell 60 m² worth. For every $3.00 increase in price, you sell 3 m² less. So use the same method you just used to find the price of grapes per m² of area to maximize revenue.Equation: R =Number of price increases: x =Price of grape per m^2 =Okay, so now, all in all, we have built our farm and found what to price each of our crops at. Now let’s find what amount of each crop to grow and find our profits. Getting right into it, we have the following cost equations:CW = $20.00 * W + $50.00CG = $10.00 * G + $40.00Where CW is the total cost of planting and growing Watermelons, CG is the total cost of planting and growing Grapes, W is the area of Watermelons planted, and G is the area of Grapes planted. Now that we know our cost, we can finally find our profits. Profit is equal to the price per unit area, multiplied by the area sold, subtracted by the total cost planting and growing them, or, Profit = Price * Area - Cost. But at this point, we still don’t know the area of each crop in our field. But we do know a couple of things to figure it out. We know the total area of our farm, found in the first part. Which we can say is, Area = G + W And we were also only given $1590 to plant the crops. So, $1590.00= CW+CG I’ll help you simplify this a bit:$1590.00=$20.00*W+$50.00+$10.00*G+$40.00 $1590.00=$20.00*W+$10.00*G+$90.00So now we have enough information to solve for the areas of Watermelons and Grapes in your field. Here’s some room to do that. Hint: Use either substitution or graph the two equations to find an intersection.Area of watermelon to plant:Area of grapes to pant:Profit of the crops:
Please helpppp this stuff is due by tonight!!
Answers
Answers
21/23
21*32=672 and 23*32=736, so 672/736
29/32
29*23=667 and 32*23=736, so 667/736
672/736 is greater than 667/736
-4x + 5 - 5 > 29 - 5
-4x > -24
-4x/-4 > -24/-4
x > 6
What were his two mistakes?
Answers
Answer:
-4x > 24
x< 6
Step-by-step explanation:
-4x + 5 > 29
-4x + 5 - 5 > 29 - 5 (subtracted 5 on both sides)
To remove +5, Sam subtracted 5 on both sides. but 29-5 is 24
we always put the sign of greatest number . so its positive
-4x > 24 is correct
-4x/-4 > 24/-4
Dividing both sides by -4 is correct. But when we divide by negative number we need to flip the inequality sign . so > becomes <
x < 6
Answers
because if it rose 30%, it's now 130% of what is used to be
or (what it used to be) ×1.3
so do the reverse and divide the new cost by 1.3
so 273÷1.3 which is 210
Answer:
210
Step-by-step explanation:
-y + 12 = 4x
Solve with elimination
Answers
Then add the first equation to the second equation
4x +12 = -7y
-4x + 12 = y this eliminates the x's
24 = - 6y then divide by - 6
- 6 - 6
- 4 = y
So if you know that y = negative 4, you can substitute into either equation. I pick the second one because I am a lazy person.
-y + 12 = 4 x
-(-4) + 12 = 4 x combine your numbers
16 = 4 x then divide by 4
4 = x
So your solution is: x = 4 and y = -4 or this is also written (4, -4)
Does that work for you?
Answers
Answer:
so waht is the question?
Step-by-step explanation: