Which of the following is an example in which you are traveling at constant speed but not at constant velocity? A) rolling freely down a hill in a cart, traveling in a straight line B) driving backward at exactly 50 km/hr C) driving around in a circle at exactly 100 km/hr D) jumping up and down, with a period of exactly 60 hops per minute E) none of the above
Answers
Speed is defined as rate of change in position or we can say it is ratio of total distance moved in total interval of times
While in order to find the velocity we know that it is ratio of total displacement and total time
so here main difference is that speed is scalar quantity and we do not require any direction in speed while in velocity we require direction as well as magnitude
Here we need to select a case where speed is constant while velocity is not constant.
It is only possible when direction is continuously changing but magnitude remains the same
so here correct answer will be
C) driving around in a circle at exactly 100 km/hr
Final answer:
Constant speed but not constant velocity is representational of circular motion, where speed is steady but the direction of movement continuously changes - such as driving around a circle at 100 km/hr.
Explanation:
The example in which you are traveling at a constant speed but not at constant velocity is C) driving around in a circle at exactly 100 km/hr. Velocity incorporates both speed and direction. Despite maintaining a constant speed, the constant change in direction (which is characteristic of circular motion) means the velocity is not constant.
To illustrate further, imagine a car moving around a circular track at a steady speed of 100 km/hr. Despite the speed remaining constant, the car is continuously changing direction. Therefore, its velocity, a vector quantity taking into account both magnitude (speed) and direction, is constantly changing.
In contrast, if we consider other examples such as driving straight forward or backward at a specific speed, the direction remains constant, therefore maintaining a constant velocity unless the speed changes.
Learn more about Constant Speed and Velocity here:
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Answer:
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46 000 000 * 6.6846e-9 = 0.3 AU
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Each of you gets a pallet of bricks, and you have to
put the bricks up on the bed of a truck, by hand.
Both pallets have the same number of bricks.
The pallet is way too heavy to lift, so you both cut the bands
that hold the bricks, and you lift the bricks from the pallet onto
the truck, by hand, two or three or four bricks at a time.
-- You get your pallet of bricks onto the truck in 45 minutes.
-- Your partner gets his pallet of bricks onto the truck in 3 days.
-- Work = (force) times (distance).
You and your partner both lifted the same amount of weight
up to the same height. You both did the same amount of work.
-- Power = (work done) divided by (time it takes to do the work) .
Your partner took roughly 96 times as long as you took
to do the same amount of work.
You did it faster. He did it slower.
You produced more power. He produced less power.
Answers
Answer:
Force exerted on the car is 7030 N.
Explanation:
It is given that,
Mass of the car, m = 740 kg
Initial speed of the car, u = 19 m/s
Final speed of the car, v = 0
Time taken, t = 2 s
Let F is the force exerted on the car during this stop. We know that it is equal to the product of force and acceleration. Mathematically, it is given as :
F = -7030 N
So, the force exerted on the car during this stop is 7030 N. Hence, this is the required solution.
acceleration = change_in_velocity / time
so:
force = 740 kg * (19 m/s - 0 m/s) / 2.0 s
= 740 * 19 / 2 kg m per second^{2}
= 7030 kg m per second^{2}
= 7030 newtons of force
Answers
(mass-1) x (mass-2) / (the distance between them)-squared
Do you see (distance-squared) in the denominator there ?
That steers you straight to the function [ y proportional to 1/x² ] ... in the middle.
none of the above
the graph is something like that