Which of the following atoms releases more energy than oxygen when an electron is added to its valence energy level? Select one:
a. helium (He)
b. fluorine (F)
c. carbon (C)
d. nitrogen (N)

Answers

Answer 1

Answer: The answer is b. fluorine (F). This is because fluorine is a more electronegative (electron loving) atom compared to oxygen. It is found on the 7th group of the periodic table, so it has 7 valence electrons. It only needs one more electron to achieve the ideal number of valence electrons which is 8. Oxygen, on the other hand, is in group 6 so it needs 2 more electrons to complete its valency. Helium can't be the answer because it is already in group 8, meaning it is already stable and won't release energy.

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Science fair ideas???

Answers

You can use a website called sciencebuddies to find a project

In a solution of salt and water, which component is the solute? A.
salt

B.
water

C.
beaker

D.
oxygen

Answers

Answer : The correct option is (A) Salt.

Explanation :

Solute : It is defined as a substance which is dissolved in a solvent. It is a smaller component of a solution.

Solvent : It is defined as a substance that dissolves a solute. It is a larger component of a solution.

In a salt and water solution, the solute is salt component and the solvent is water component.

Therefore, the correct answer is Salt.

The component of the solute is SALT.

What color is used to show OXYGENATED blood?

Answers

Answer:

MRCORRECT has answered the question

Explanation:

The color of human blood ranges from bright red when oxygenated to a darker red when deoxygenated. It owes its color to hemoglobin, to which oxygen binds.

Consider the following balanced chemical equation. 4 KO 2 + 2 H 2 O ⟶ 4 KOH + 3 O 2 How is the rate of appearance of O 2 , Δ [ O 2 ] Δ t , related to the rate of disappearance of KO 2 ?

Answers

The appearance of Oxygen molecule is directly related or dependent to the rate of disappearance of potassium superoxide (KO2).

The rate of appearance of O2 is directly related to the rate of disappearance of KO2 because potassium superoxide (KO2) has oxygen molecule which is attached to the potassium so when the potassium reacts with water molecules, the potassium hydroxide (KOH ) and oxygen molecules is formed.

If the chemical reaction occurs then we get oxygen molecules so we can conclude that appearance of Oxygen molecule is directly related or dependent to the rate of disappearance of potassium superoxide (KO2).

Learn more: brainly.com/question/14917767

Answer : The rate of appearance of $O_2$ related to the rate of disappearance of $KO_2$ is,

$(d[O_2])/(dt)=-(3)/(4)(d[KO_2])/(dt)$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-(1)/(a)(d[A])/(dt)$

$\text{Rate of disappearance of B}=-(1)/(b)(d[B])/(dt)$

$\text{Rate of formation of C}=+(1)/(c)(d[C])/(dt)$

$\text{Rate of formation of D}=+(1)/(d)(d[D])/(dt)$

$Rate=-(1)/(a)(d[A])/(dt)=-(1)/(b)(d[B])/(dt)=+(1)/(c)(d[C])/(dt)=+(1)/(d)(d[D])/(dt)$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$4KO_2+2H_2O\rightarrow 4KOH+3O_2$

The expression for rate of reaction :

$\text{Rate of disappearance of }KO_2=-(1)/(4)(d[KO_2])/(dt)$

$\text{Rate of disappearance of }H_2O=-(1)/(2)(d[H_2O])/(dt)$

$\text{Rate of formation of }KOH=+(1)/(4)(d[KOH])/(dt)$

$\text{Rate of formation of }O_2=+(1)/(3)(d[O_2])/(dt)$

The overall rate expression is:

$\text{Rate of reaction}=-(1)/(4)(d[KO_2])/(dt)=-(1)/(2)(d[H_2O])/(dt)=+(1)/(4)(d[KOH])/(dt)=+(1)/(3)(d[O_2])/(dt)$

Now we have to determine the rate of appearance of $O_2$ related to the rate of disappearance of $KO_2$ .

$-(1)/(4)(d[KO_2])/(dt)=+(1)/(3)(d[O_2])/(dt)$

or,

$+(1)/(3)(d[O_2])/(dt)=-(1)/(4)(d[KO_2])/(dt)$

$(d[O_2])/(dt)=-(3)/(4)(d[KO_2])/(dt)$

Thus, the rate of appearance of $O_2$ related to the rate of disappearance of $KO_2$ is,

$(d[O_2])/(dt)=-(3)/(4)(d[KO_2])/(dt)$

What coefficients are needed to balance the equation for the complete combustion of methane? enter the coefficients in the order ch4, o2, co2, and h2o, respectively.

Answers

The coefficients in the order CH₄, O₂, CO₂, and H₂O, are 1,2,1,2

The equation becomes:

CH₄ (g) + 2O₂ (g) -> CO₂ (g) + 2H₂0 (g)

Further explanation

Complete combustion of hydrocarbon with oxygen will be obtained by CO₂ and H₂O compounds.

If O is insufficient there will be incomplete combustion produced by CO and H and O

Hydrocarbon combustion reactions (specifically alkanes)

$\large {\boxed {\bold {C_nH _ (_2_n _ + _ 2_) + \frac {3n + 1} {2} O_2 ----> nCO_2 + (n + 1) H_2O}}}$

Equalization of chemical reaction equations can be done using variables.

Steps in equalizing the reaction equation:

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product

3. Select the coefficient of the substance with the most complex chemical formula equal to 1

For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:

Balancing C atoms, H and last atoms O atoms

Methana combustion reaction

CH₄ (g) + O₂ (g) -> CO₂ (g) + H₂0 (g)

We give the most complex compounds, namely Methane, we give the number 1

So the reaction becomes

CH₄ (g) + aO₂ (g) -> bCO₂ (g) + cH₂0 (g)

C atom on the left 1, right b, so b = 1

H atom on the left 4, right 2c, so 2c = 4 ---> c = 2

Atom O on the left 2a, right 2b + c, so 2a = 2b + c

2a = 2.1 + 2

2a = 4

a = 2

The equation becomes:

CH₄ (g) + 2O₂ (g) -> CO₂ (g) + 2H₂0 (g)

Learn more

the combustion of octane in gasoline

brainly.com/question/8175791

brainly.com/question/897044

hydrogen and excess oxygen

brainly.com/question/1405182

Keywords: methane, combustion, hydrocarbons, equalization of reaction equations

The balanced chemical equation is as follows:

${\text{C}}{{\text{H}}_4}\left( g \right) + 2{{\text{O}}_2}\left( g \right) \to {\text{C}}{{\text{O}}_{\text{2}}}\left( g \right) + 2{{\text{H}}_{\text{2}}}{\text{O}}\left( g \right)$

The coefficients of ${\mathbf{C}}{{\mathbf{H}}_{\mathbf{4}}}$ is $\boxed1$ , ${{\mathbf{O}}_{\mathbf{2}}}$ is $\boxed2$ , ${\mathbf{C}}{{\mathbf{O}}_{\mathbf{2}}}$ is $\boxed1$ and ${{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}}$ is $\boxed2$

Further Explanation:

The chemical reaction that contains equal number of atoms of the different elements in the reactant as well as in the product side is known as balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

Combustion reaction is the reaction in which the reactant reacts with molecular oxygen to form carbon dioxide and water molecule. Molecularoxygen acts as the oxidizing agent in these reactions. The large amount of heat is released and therefore combustion reactions are exothermic reaction.

The steps to balance a chemical reaction are as follows:

Step 1: Complete the reaction and write the unbalanced symbol equation.

In the combustion reaction, ${\text{C}}{{\text{H}}_4}$ reacts with ${{\text{O}}_2}$ to form ${\text{C}}{{\text{O}}_{\text{2}}}$ and ${{\text{H}}_{\text{2}}}{\text{O}}$ . The physical state of ${\text{C}}{{\text{H}}_4}$ is gas, ${{\text{O}}_2}$ is gas, ${\text{C}}{{\text{O}}_{\text{2}}}$ is gas and ${{\text{H}}_{\text{2}}}{\text{O}}$ is gas. The unbalanced chemical equation is as follows:

${\text{C}}{{\text{H}}_4}\left(g\right)+{{\text{O}}_2}\left(g\right)\to{\text{C}}{{\text{O}}_{\text{2}}}\left(g\right)+{{\text{H}}_{\text{2}}}{\text{O}}\left(g\right)$

Step 2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately. There is one carbon atom on both the reactant and product side. 2 oxygen atoms are present on the reactant side while 3 oxygen atoms are present on the product side. The number of hydrogen atoms on the reactant and product sides is 4 and 2 respectively. (Refer table in the attached image).

Step 3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side but in the combustion reaction there is only carbon, hydrogen and oxygen atom.

Step 4: After this, we balance the number of atoms of oxygen and then carbon atom followed by hydrogen atoms. To balance the number of atoms of oxygen and hydrogen, we have to multiply ${{\text{O}}_2}$ by 2 and ${{\text{H}}_{\text{2}}}{\text{O}}$ by 2. The chemical equation is as follows:

${\text{C}}{{\text{H}}_4}\left(g\right)+2{{\text{O}}_2}\left(g\right)\to{\text{C}}{{\text{O}}_{\text{2}}}\left(g\right)+2{{\text{H}}_{\text{2}}}{\text{O}}\left(g\right)$

Step 5: Finally, we check the number of atoms of each element on both sides. If the number is same then the chemical equation is balanced. The balanced chemical equation is as follows:

${\text{C}}{{\text{H}}_4}\left(g\right)+2{{\text{O}}_2}\left( g \right) \to{\text{C}}{{\text{O}}_{\text{2}}}\left(g\right)+2{{\text{H}}_{\text{2}}}{\text{O}}\left(g\right)$

The coefficients of ${\text{C}}{{\text{H}}_4}$ is 1, ${{\text{O}}_2}$ is 2, ${\text{C}}{{\text{O}}_{\text{2}}}$ is 1 and ${{\text{H}}_{\text{2}}}{\text{O}}$ is 2.

Learn more:

1. Balanced chemical equation brainly.com/question/1405182

2. Learn more about how to calculate moles of the base in given volume brainly.com/question/4283309

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: Balancing, CH4, O2, CO2, H2O, phases, physical state, solid, liquid, gas, aqueous, coefficients, and combustion reactions.

What is the Bond Type and Molecular polarity of PCl3?

Answers

It is covalent bonding. The electrons are shared between the phosphorus and the chlorines.

covalent bonding is when electrons are shared between two elements.

molecular polarity is a little bit complicated, but I will try to explain ;)
PCl3 is an alternation on tetrahedral molecules.
It means that P has one lone pair of electrons. This pair of electrons are only attracted to the P nuclei and thus a greater freedom of motion.
This means that their orbital is bigger and this pushes the 3 Cl atoms closer together.
The angle between each Cl now is 107 and the angle between Cls and P is greater than 107.
Now, due to this shape, and also electronegativity (Cl is more electronegative than P meaning that it tends to hog the electrons they share closer to itself), PCl3 is polar. Electrons that are shared tend to flow closer towards the Cl than the P side.
Therefore, on the Cl side of the molecule it's, more negative. On the P side, it's more positive.

In the given question, bond type for the molecule $\rm PCl_3$ is covalent bond and molecular polarity of $\rm PCl_3$ is polar in nature, respectively.

Polarity is caused if it has an uneven distribution of electrons, causing one end of the molecule to be slightly positive and the other end to be slightly negative.

The bond type of $\rm PCl_3$ is covalent. Covalent bonds form when atoms share electrons to achieve a more stable electron configuration. In $\rm PCl_3$ , the phosphorus atom shares three of its valence electrons with three chlorine atoms to form three covalent bonds.

The molecular polarity of $\rm PCl_3$ is polar. In $\rm PCl_3$ , the three chlorine atoms exert a stronger pull on the shared electrons, causing them to be slightly negative, while the phosphorus atom is slightly positive. This creates a dipole moment, making the molecule polar.

Therefore, $\rm PCl_3$ has covalent bonds and it is a polar molecule.

Learn more about Polarity here:

brainly.com/question/14250786

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