The nucleus of an atom of K-42 contains(1) 19 protons and 23 neutrons
(2) 19 protons and 42 neutrons
(3) 20 protons and 19 neutrons
(4) 23 protons and 19 neutrons

Answer:

• Option A. n = 6 to n = 1

Explanation:

Niels Bohr was a Danish physicist who proposed the hydrogen atom quantum model to explain the discontinuity of the atom's emission spectra.

In Bohr hydrogen atom model, the electrons occupy orbits identified with the numbers n = 1, 2, 3, 4, ... Each number (orbit) corresponds to a different energy level  or state. The number n = 1 corresponds to the lowest energy level, and each higher number corresponds to a higher energy level.

This table shows the relative energy of the different orbits of the Bhor hydrogen atom:

Orbit      Quantum       Energy      Relative

              number         level          energy

First          n = 1                  1                   E₁

Second    n = 2                 2                2E₁

Third        n = 3                 3                 9E₁

Fourth      n = 4                 4                16E₁

Fifth          n = 5                5                25E₁

Sixth         n = 6                6                36E₁

Seventh    n = 7                7                49E₁

When an electron jumps from a higher energy state down to a lower energy state, it emits a photon with an energy equal to the difference of the energies between the initial and the final states.

Since the n = 6 to n = 1 transition results in the higher relative energy difference (36E₁ - E₁ = 35E₁), you conclude that it is this transition which results in the emission of the highest-energy photon, which is the option A.

Final answer:

In the Bohrhydrogen atom model, the highest energy photon is emitted during the transition from the highest energy level to the lowest energy level. For the given options, the highest energy photon would be emitted in the transition from n=6 to n=1.

Explanation:

In the Bohr hydrogen atom model, the highest energyphoton is emitted during the transition from the highest energy level to the lowest energy level. In our choices, the largest transition (indicating the greatest energy change) is from n=6 to n=1. This is because the energy difference between the energy levels is the greatest, resulting in the emission of a photon with the highest energy.

In general, the greater the transition between the energy levels in a hydrogen atom (i.e. the more levels the electron 'jumps' downward), the higher the energy of the emitted photon.

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The carbon atoms bind together to create the compound's framework. Therefore, the name of the hydrocarbon CH(CH)CH is  n-octane.

What is hydrocarbon?

Any member of a group of organic compounds comprised only of the atoms carbon (C) as well as hydrogen (H) (H). The carbon atoms bind together to create the compound's framework, as well as the hydrogen atoms connect to them in a variety of ways.

Petroleum as well as natural gas are mostly composed of hydrocarbons. They are used as fuels and lubricants, as well as raw materials to make polymers, fibers, rubbers, solvents, explosives, various industrial chemicals. The name of the hydrocarbon CH(CH)CH is n-octane.

Therefore, the name of the hydrocarbon CH(CH)CH is n-octane.

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Answer is: n-octane.

Octane is the straight-chain alkane (an acyclic saturated hydrocarbon) with eight carbon atoms.

Carbons in octane have sp3 hybridization (carbon’s 2s and three 2p orbitals combine into four identical sp3 orbitals).

Orbitals in sp3 hybridization have a tetrahedral arrangement and form single (sigma) bonds.

Burning octane fuel is very fast chemical reaction, it happens in immediately.

Main products of the combustion of fossil fuels are carbon(IV) oxide and water.  

Chemical reaction: C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O; ΔH = -5500 kJ/mol.

Answer:

83

Explanation:

eighty-three