Solve the quadratic equation for x. What is one of the roots? (x + 6)^2 = 49

Answers

Answer 1
Answer:

The value of one of the roots x of the quadratic equation(x + 6)^2 = 49 is 1.

A polynomial is an expression with nonnegative coefficients and consists of constants, variables, and operators ( addition, subtraction multiplication, and division)The highest power of the polynomial is called the degree of the polynomial. The polynomial whose degree is 2 is called a quadratic polynomial.

For example; 3x^2- 5x+9=0, here the degree of the polynomial is 2, so it is a quadratic polynomial.

The roots of the equation can be calculated as:

( x+6)^2 = 49\n( x+6)^2 = (7)^2\n x+6 = 7\nx = 7-6\nx = 1

Thus, one of the roots of the equation  (x + 6)^2 = 49 is 1.

Learn more about polynomials here:

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Answer 2
Answer:

Answer:

x equals -1 and it also equals -13. They are both considered the roots.

Step-by-step

  1. (x+6)^2= 49    to get rid of the exponent square root each side of the equation.
  2. (x+6)= √49     Find square root of 49.
  3. (x+6)= ±7        It could be positive 7 or -7 because both of them squared equal 49. Now solve for each possible equation, (x+6)= 7 and  (x+6)=-7.
  4. (x+6)=7  subtract 6 from each side.
  5. x= 1
  6. (x+6)=-7  Subtract 6 from each side.
  7. x=-13
  8. So the answers are -13 and 1.


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Find all real square roots of -121.

Answers

Answer:

11

Step-by-step explanation:

3n+8=23 answer and the work to show the answer please

Answers

Answer: n = 5

Step-by-step explanation: To solve for n, we must first isolate the term containing n which in this problem is 3n.

Since 8 is being added to 3n, we subtract 8 from both sides of the equation to isolate the 3n. On the left, the +8 and -8 cancel out and on the right 23 - 8 is 15.

So we have 3n = 15.

Now we can finish things off by just dividing both sides of the equation by 3. On the left the 3's cancel and on the right 15 divided by 3 is 5 so n = 5 and you can check your answer by plugging 5 back in for n in the original equation which is shown below in bold.

3(5) + 8 = 23 or 15 + 8 = 23.

Answer:

n = 5

Step-by-step explanation:

3n + 8 = 23

     - 8    - 8   Subtract 8 from both sides

3n = 15

n = 5      Divide both sides by 3

You rode your bike 27 miles during the last month. Your total travel time was 3 hours. What was your average speed in miles per hour?

Answers

you divide 27 by 3 which equal 9

27÷3=9
You divide 27 by 3. Your answer would be 9mph

Find the greatest common factor 2x^2a+2xa^2

Answers

Answer:

The GCF is

2ax

Step-by-step explanation:

The given expression is:

2 {x}^(2) a + 2x {a}^(2)

We rewrite each term as product of primes to get:

2 {x}^(2) a = 2 *  {x}^(2)  * a

2x {a}^(2)= 2 * x *  {a}^(2)

The greatest common factor is the product of the least powers of the factors common to the prime factorizations.

GCF = 2 * x * a = 2ax

A cylinder has a radius of 12m and a height of 8m. What is the approximate surface area of the cylinder? use 3.14 for Pi.

Answers

Surface Area = 2 × π × r × (r+h). So  2 × π × 12 × (12+8). Then 2 × π × 12 × 20. And then 480 π. And your answer is about 1507.
Simple, A=2πrh+2πr²=2*π*12*8+2*π*12²=1507.96447m². If you want to round your answer, it would be 1507.96m²

HELP PLEASE!!!!!! I REALLY NEED HELP!
(Science) (15 pts)





1. My amplifier uses a filament that requires a maximum of 5 volts at a current of 15 amperes.
Calculate the resistance of the tube. (Round to no more than two numbers to the right of the decimal)

2. How many ohms of resistance are present in a light bulb that draws 2 amperes at 120 volts?

3. A 250 watt radio will draw how many amps when operating on 240 volts? (Round to no more than two numbers to the right of the decimal)

Answers

The problems of physics that are given here can be solved using Ohms laws. As per the Ohms law, we can write
Resistance = Current/Voltage.
Now coming to the questions that are given.
1. In this question,
Current = 15 amperes
Voltage = 5 volts
Then
Resistance = 5/15
                   = 1/3
                   = 0.33 ohms
So the resistance of the tube will be 0.33 ohms
2. Given information's are noted below
Current = 2 amperes
Voltage = 120 volts
Resistance = 120/2
                   = 60 ohms
 So 60 ohms of resistance is present in the bulb.
3. Given information's
Current = 250 watt
Voltage = 240 volts
Resistance = 250/240
                   = 25/24
                   = 1.04 ohms.
The radio will draw 1.04 ohms.