MATHEMATICS COLLEGE

“In which quadrant would you find point P if the coordinates of P are (–5, ...”Assuming that P is not on an axis, what are the possible answers to this question?
quadrant I or quadrant II
quadrant II or quadrant III
quadrant II or quadrant IV
quadrant III or quadrant IV

Answers

Answer 1
Answer:

Answer:

quadrant II or quadrant III

Step-by-step explanation:

Quadrants are numbered I to IV in the counterclockwise direction, starting with upper right. Quadrants II and III are to the left of the y-axis, where x-coordinates are negative.
Answer 2
Answer:

Answer:

B - quadrant ll or quadrant lll

Step-by-step explanation:

Got it right on edge

Also I ain’t never seen two pretty best friends

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Graph the line 3x + 6y =12.
Use the technique developed in this section to solve the minimization problem. Minimize C = −3x − 2y − z subject to −x + 2y − z ≤ 20 x − 2y + 2z ≤ 25 2x + 4y − 3z ≤ 30 x ≥ 0, y ≥ 0, z ≥ 0 The minimum is C = at (x, y, z) = .

A test consists of 10 true/false questions. To pass the test a student must answer at least 6 questions correctly. If a student guesses on each question, what is the probability that the student will pass the test?

Answers

Answer:

37.70% probability that the student will pass the test

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the student guesses it correctly, or he does not. The probability of a student guessing a question correctly is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)

In which C_(n,x) is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_(n,x) = (n!)/(x!(n-x)!)

And p is the probability of X happening.

10 true/false questions.

10 questions, so n = 10

True/false questions, 2 options, one of which is correct. So p = (1)/(2) = 0.5

If a student guesses on each question, what is the probability that the student will pass the test?

P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)

P(X = 6) = C_(10,6).(0.5)^(6).(0.5)^(4) = 0.2051

P(X = 7) = C_(10,7).(0.5)^(7).(0.5)^(3) = 0.1172

P(X = 8) = C_(10,8).(0.5)^(8).(0.5)^(2) = 0.0439

P(X = 9) = C_(10,9).(0.5)^(9).(0.5)^(1) = 0.0098

P(X = 10) = C_(10,10).(0.5)^(10).(0.5)^(0) = 0.0010

P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.2051 + 0.1172 + 0.0439 + 0.0098 + 0.0010 = 0.3770

37.70% probability that the student will pass the test

Solve for x. Write both solutions, separated
by a comma.
5x2 + 2x - 7 = 0

Answers

Answer:

it equals 1

Step-by-step explanation:

(5)(2)+2x−7=5

Step 1: Simplify both sides of the equation.

(5)(2)+2x−7=5

10+2x+−7=5

(2x)+(10+−7)=5(Combine Like Terms)

2x+3=5

2x+3=5

Step 2: Subtract 3 from both sides.

2x+3−3=5−3

2x=2

Step 3: Divide both sides by 2.

2x

2

=

2

2

x=1

A television is 28.5 inches wide and 16 inches long.Using the Pythagorean Theorem, what is the length of the diagonal of the television, rounded to the nearest inch?

Answers

Answer:

  33 in

Step-by-step explanation:

The Pythagorean theorem tells you ...

  diagonal² = length² +width²

  diagonal² = (16 in)² +(28.5 in)² = 1068.25 in²

  diagonal = √(1068.25 in²) ≈ 32.684 in

The diagonal of the television is about 33 inches.

Find the area of the composite figure below.

Answers

Answer:

702 ft²

Step-by-step explanation:

24x27=648

(30-24)x(27-18)=6x9=54

648+54=702 ft²

Solve for y. y/6 = 3/9 simplify your answer as much as possible​

Answers

Answer: y=2

Step-by-step explanation:

y/6 = 3/9        multiply both sides by 6/1 (since 6/1 times y/6 equals 1y or just y)

y = 18/9          now that y is isolated, just simplify 18/9

y=2                 18 divided by 9 is 2

Which fraction is bigger 7/36, or 4/9

Answers

Answer:

4/9 is bigger

Step-by-step explanation:

For the 1st fraction, since 9 × 4 = 36,

4/9 = 4 × 4

        9 × 4 = 16/36

Likewise, for the 2nd fraction, since 36 × 1 = 36,

7/36= 7 × 1

        36 × 1 = 7/36

Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction

16/36> 7/36 or 4/9 > 7/36
7/36 is bigger
7 goes into 36 5 times
and 4 goes in 9 only 4 times
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