What is the #1 or main component of the earths ancient atmosphere?

Answers

Answer 1
Answer: I am pretty sure it was composed of mostly CO₂.  

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When an inflated balloon is exposed to cold air,a. the temperature inside the balloon rises.
b. the pressure inside the balloon rises.
c. the volume of the balloon decreases.
d. the volume of the balloon increases

Answers

The correct answerwould be C. The volume of the balloon will decrease. As depicted in Charles’Law which states that volume and temperature are directly proportional to each other,when the pressure of the gas is at a constant. When this theory is applied, theballoon will decrease in volume when it is exposed to cold air because the gas pressureinside the balloon remains the same. It is easier to remember this concept withthe equation V/T = K where V is volume, T is Temperature and K is constantpressure. 

Which statement is NOT TRUE about elements in group 16?a. They need two electrons to complete their octet.
b. They have an oxidation number of 2-
c. They have an oxidation number of 2+
d. The have six valence electrons.

Answers

All the statement is true about the elements of group 16.

What is Groups and Periods in Periodic table ?

In periodic table 18 vertical column are present which is called groups which are arranged from left to right in the periodic table.

In periodic table 7 horizontal rows are present which is called periods.

Now lets check all options one by one.

Option (A): They need two electrons to complete their octet.

In periodic table Group sixteen have 6 elements in its valence shell. Group 16 elements needed two electrons to complete the octet valency. The valency of group 16 elements is 2. So it is true about the group 16 elements.

Hence, it is incorrect option.

Option (B): They have an oxidation number of 2-

Group 16 show variable oxidation state that is -2, +2, +4 and +6. So the statement is true.

Hence it is incorrect option.

Option (C): They have an oxidation number of 2+.

Group 16 show variable oxidation state that is -2, +2, +4 and +6. So the statement is true.

Hence it is incorrect option.

Option (D): They have six valence electrons

Group 16 elements are called Chalcogens. They have 6 valence electron so they achieve noble gas configuration. So it is true statement.

Hence, it is incorrect option.

Thus, from the above conclusion we can say that all the statement is true about the elements of group 16.

Learn more about the Group 16 elements here: brainly.com/question/19965333
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The most suitable answer is C becuase they would gain two elctrons to atain that stable OCTET thus becoming a anion with a charge of -2 and by virtue oxidation states of -2.  There is however an exception with oxygen in two cases. But I still remain that the best answer would be C

Calculate the molarity (M) of 1.5 L solution of todium nitrate (NaNO3) containing 61.2 g of NaNO3

Answers

Answer:

\huge\boxed{\sf Molarity = 0.48\ M}

Explanation:

Given data:

Volume of solution = 1.5 L

Mass of solute = 61.2 g

Molar mass of solute:

= 23 + 14 + (16 × 3)

= 23 + 14 + 48

= 85 g/mol

Required:

Molarity = ?

Formula:

Molarity = no. of moles of solute / volume

Solution:

First, we have to find moles of solute.

We know that,

Moles = mass / molar mass

Moles = 61.2 / 85

Moles = 0.72 moles

Now, finding molarity:

Molarity = 0.72 / 1.5

Molarity = 0.48 M

\rule[225]{225}{2}

The molarity of the 1.5 L solution of sodium nitrate containing 61.2 g of NaNO3 is approximately **0.480 M**

To calculate the molarity (M) of a solution, you can use the formula:

\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution (L)}} \]

- Volume of solution (\( V \)) = 1.5 L

- Mass of sodium nitrate = 61.2 g

- Molar mass of sodium nitrate = 85 g/mol (Na: 23 g/mol, N: 14 g/mol, O: 16 g/mol)

First, calculate the moles of sodium nitrate using its molar mass:

\[ \text{Moles of } \text{NaNO}_3 = \frac{\text{Mass}}{\text{Molar mass}} = \frac{61.2 \, \text{g}}{85 \, \text{g/mol}} \approx 0.720 \, \text{mol} \]

Now, substitute the values into the molarity formula:

\[ \text{Molarity (M)} = \frac{0.720 \, \text{mol}}{1.5 \, \text{L}} \]Calculate:\[ \text{Molarity (M)} \approx 0.480 \, \text{M} \]

So, the molarity of the 1.5 L solution of sodium nitrate containing 61.2 g of NaNO3 is approximately **0.480 M**.

To know more about molarity refer here:
brainly.com/question/31545539#

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What is the average surface temperature of Uranus

Answers

The average surface temperature of Uranus (nearly being the coldest planet in the solar system) is -224°C
The surface of Uranus.The second coldest planet in our solar system is -224°C

Claculate the molar mass of sodium sulphate na2so4

Answers

Na₂SO₄ = 23 * 2 + 32 + 16 * 4 = 142.0 g/mol

hope this helps!

What is the value of mass of electron?for which has 6.25 × 10^18?

Answers

Answer: the mass of an electron is approximately 9.10938356 × 10^-31 kilograms (kg)

Explanation: