The weight of oxegon
Answer:
Explanation:
1) Increase the amount of charge on each object
2) Decrease the distance between each object
3) Increase the mass of the objects.
just colmpeated this in usa test prep 100% correct
orbiting a planet?
the mass of the satellite
the orbital radius of the satellite
the mass of the planet
the universal gravitational constant
Pls help I will give extra points
The mass of the satellite is not required when calculating the velocity of a satellite orbiting a planet.
Given that the centripetal force on the satellite is;
F = mv^2/r
Where;
F = centripetal force that keeps the satellite in its orbit
m = mass of the satellite
r = radius of the satellite
Since the force of gravity and the centripetal force both act on the satellite and they are exactly balanced;
F = GMm/r^2
Where;
G = gravitational constant
M = mass of the planet
m = mass of the satellite
r = radius of the satellite
Hence;
F = GMm/r^2 = mv^2/r
GMm/r^2 = mv^2/r
v = √GM/r
Thus, the mass of the satellite is not required when calculating the velocity of a satellite orbiting a planet.
Learn more: brainly.com/question/21454806
Answer:
i. the mass of the satellite will not be required in this calculation
Explanation:
When a satellite is orbiting a planet, it experiences two forces. The centripetal force and the gravitational force that the planet exerts on the satellite. In order for the satellite to keep in orbit, the centripetal force and the gravitational force must be equal.
The expression for the centripetal force is:
F_c = (m_s)v² / R
where
m_s is the mass of the satellite
R is the radius of the satellite's orbit
v is the velocity that the satellite travels with around the planet
The expression for the Gravitational force is:
F_g = (G M_p m_s) / R²
where
G is the universal gravitational constant
M_p is the mass of the planet
m_s is the mass of the satellite
R is the radius of the satellite's orbit
Thus, equating the two forces together, we get:
(G M_p m_s) / R² = (m_s)v² / R
We can cancel out m_s since it is a common factor on both sides.
Thus,
(G M_p) / R² = v² / R ⇒ M_p = v²R / G
Therefore, the mass of the satellite is not required to calculate the mass of the planet.
Explanation:
Hope this helps:)
a. the concentration of b-galactosidase
b. the concentration of Luria Broth
c. the concentation of glucose
d. the concentration of lactose
e. the concentration of ONPG
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Answer:
a. The concentration of β-galactosidase
Explanation:
β-Galactosidase is an enzyme that hydrolyzes ß-D-galactosides like lactose to glucose and galactose.
It also cleaves o-nitrophenyl-β-D-galactoside (ONPG) to yield galactose and o-nitrophenol, which is yellow, and can be measured by its absorption at 420 nm.
If the concentration of ONPG is greater than that of β-galactosidase, the concentration of o-nitrophenol produced is proportional to the concentration of the enzyme.
b)conductivity
c)hardness
d)odor
Alai is hitting each with a hammer, the physical property which he must be compared the two materials must be hardness.
A physical property is a characteristic of matter that is not associated with a change in its chemical composition. Familiar examples of physical properties include density, colour, hardness, melting and boiling points, and electrical conductivity.
Alai is hitting each with a hammer, the physical property which he must be compared to the two materials must be hardness.
Solubility can be tested when you put them in a solvent.
Odour can be tested with a smell.
Conductivity can be tested with electricity. Hardness can be tested with its resistance to the force that hits it.
Hence, Alai is comparing hardness.
Learn more about a physical property here:
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