CHEMISTRY HIGH SCHOOL

Carbon disulfide is prepared industrially by reacting carbon with sulfur dioxide according to the above equation. If 70.8 g of carbon react, how many moles of CS2 are produced? Show all work, include all units, and box your answer.

Answers

Answer 1
Answer:

Answer:

1.18 moles of CS₂ are produced by the reaction.

Explanation:

We present the reaction:

5C + 2SO₂  →  CS₂  +  4CO

5 moles of carbon react to 2 moles of sulfur dioxide in order to produce 1 mol of carbon disulfide and 4 moles of carbon monoxide.

As we do not have data from the SO₂, we assume this as the excess reagent. We convert the mass of carbon to moles:

70.8 g / 12 g/mol = 5.9 moles

Ratio is 5:1, so 5 moles of carbon react to produce 1 mol of CS₂

Then, 5.9 moles will produce (5.9 . 1) / 5 = 1.18 moles

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A + B → C Select the rate law for the reaction above using the following information: Holding the concentration of A constant and doubling the concentration of B results in the rate of the reaction increasing from 1.5E-3 M/s to 1.2E-2 M/s. Keeping the concentration of B constant and doubling A results in the rate of the reaction increasing from 1.5E-3 M/s to 3.0E-3 M/s.

Answers

For the initial conditions:
1.5E-3 = k A^n B^m

For the second condition:
1.2E-2 = k A^n (2B)^m
1.2E-2 = 2^m k A^n B^m
From the initial condition:
1.2E-2 = 2^m (1.5E-3)
m = 3.32

For the third condition:
3.0E-3 = k (2A)^n B^m
3.0E-3 = 2^n k A^n B^m
3.0E-3 = 2^n (1.5E-3)
n = 1

Therefore, the rate law is:
r = k A B^3.32

At constant temperature and pressure, 2.05 g of oxygen gas O2 is added to a 1.0 L balloon containing 1.00 g of O2. What is the new volume of the balloon?

Answers

Answer:

1.50 L.

Explanation:

  • From the general gas law:

PV = nRT,

Where, P is the pressure if the gas,

V is the volume if the gas container,

n is the no. of gas moles,

R is the general gas constant,

T is the temperature of the gas.

  • At constant P and T:

n₁V₂ = n₂V₁.

V₁ = 1.0 L, V₂ = ??? L.

n₁ = mass/molar mass = (2.05 g)/(32.0 g/mol) = 0.064 mol.

  • n₂ is the no. of moles of the total gas (2.05 g + 1.0 g).

n₂ = n₁ + (1.00 g)/(32.0 g/mol) = 0.0953 mol.

∴ V₂ = n₂V₁/n₁ = (0.0953 mol)(1.0 L)/(0.064 mol) = 1.489 L ≅ 1.50 L.

Why can color alone be used to identify most minerals?

Answers

Because a lot of minerals have the same color

The melting points of canola oil, corn oil, sunflower oil, and peanut oil are 10° C, -11° C, -17° C, and -2° C, If you cool a mixture of these oils to 5°C, which one can you separate easily?a. corn oil
b. canola oil
c. peanut oil
d. sunflower oil

Answers

Answer:

            Canola Oil

Explanation:

The data given is as;

     Oil                                             Melting Point / Freezing Point

Canola Oil                                                            10 °C

Corn Oil                                                                -11 °C

Sunflower Oil                                                       -17 °C

Peanut Oil                                                           -2 °C

When the mixture of these oils is cooled to 5 °C only the Canola oil will solidify because it has a melting point of 10 °C and exists in solid state below 10 °C (Freezing Point). Therefore, it can easily be separated from remaining mixture which is present in liquid state.

8 Which quantity is equal to one mole of Au?(1) the atomic mass in grams(2) the atomic number in grams
(3) the mass of neutrons in grams
(4) the number of neutrons in grams

Answers

Answer is (1) the atomic mass in grams since One mole of any element is equal to the atomic mass in grams.

Answer: option (1) the atomic mass in grams.

Explanation:

1) The atomic mass is the mass in grams of one mole of atoms.

2) Hence, it is always the atomic mass of an element equal to the mass of one mole of atoms of such element. Therefore, the atomic mass of Au is the mass of one moles of atoms of Au.

3) Here are some examples:

i) Atomic mass of gold: 196.67 g/atoms, means that 196.97 grams of Au is one mole of Au.

ii) Atomic mass of hydrogen: 1.008 g/mol, means that 1.008 grams of H is one mole of H.

iii) Atomic mass of oxygen: 15.999 g/mol, means that 15.999 grams of O is one mole of O.

iv) Atomic mass of lead: 207.2 g/mol, means that 207.2 grams of Pb is one mole of Pb.

Now you see it, the atomic mass in grams of an element is equal to one mole of the element.

1. When a metal and a(n) ___ bond, they do not share electrons. 2. The ___ atom transfers one or more valence electrons to the ____ atom, forming a chemically stable compound. 3. A(n) ___ is an atom that is no longer electrically neutral because it has lost or gained one or more valence electrons. a. An atom that loses one or more valence electrons becomes an ion with a(n) ___ charge.

Answers

Answer:

1 . Nonmetal

2. metal, non metal

3. Ion

4. positive
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