1
3
Ob
Oc
O d
10
2
Answer:
1.33%
Explanation:
In an aqueous solution, a weak acid such as acetic acid, will be in equilibrium with its conjugate base, acetate ion, thus:
CH₃CO₂H(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CH₃CO₂⁻(aq )
Where dissociation constant, ka, is defined as the ratio of concentrations of products and reactants:
Ka = 1.8x10⁻⁵ = [H₃O⁺] [CH₃CO₂⁻] / [CH₃CO₂H]
H₂O is not taken into account in the equilibrium because is a pure liquid
When a solution of acetic acid becomes to equilibrium, the original concentration of the acid decreases producing more H₃O⁺ and CH₃CO₂⁻.
The concentrations at equilibrium when a 0.100M solution of acetic acid reaches this state, is:
[CH₃CO₂H] = 0.100M - X
[H₃O⁺] = X
[CH₃CO₂⁻] = X
Where X is reaction coordinate.
Replacing in Ka expression:
1.8x10⁻⁵ = [H₃O⁺] [CH₃CO₂⁻] / [CH₃CO₂H]
1.8x10⁻⁵ = [X] [X] / [0.100M - X]
1.8x10⁻⁶ - 1.8x10⁻⁵X = X²
1.8x10⁻⁶ - 1.8x10⁻⁵X - X² = 0
Solving for X:
X = -0.00135 → False solution. There is no negative concentrations.
X = 0.00133 → Right solution.
That means concentration of acetate ion is:
[CH₃CO₂⁻] = 0.00133M.
Now, percent ionization is defined as 100 times the ratio between weak acid that is ionizated, [CH₃CO₂⁻] = 0.00133M, per initial concentration of the acid, [CH₃CO₂H] = 0.100M. Replacing:
% Ionization = 0.00133M / 0.100M × 100 =
A: protons
B:electrons
C:neutrons
D:quarks
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2: If the atomic number of an element is 16, then it has 16 electrons.
True
False
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3: An unknown substance is tested and found to have the following physical properties:
brittle
fair conductor of electricity
dull (not shiny)
The substance is most likely a _____.
A:metal
B:metalloid
C:nonmetal
D:can not be determined without more data
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1)Protons and Neutrons have approximately equal masses
2)TRUE
3) B-Metalloid
Answer:
its a and b
Explanation:
i got it right on test
Answer the correct answer out of the four is option c spectroscopy
Explanation- The interaction between electromagnetic radiation and matter studied. This study is commonly known as spectroscopy. It can also be named as study of absorption spectra or emission spectra.
The former spectrum is formed when energy is absorbed from Photons or light energy by electrons while the latter spectrum is formed due to a wavelength of light that is released when electrons jump from higher to lower level.
Answer:
D spectroscopy
Explanation: