An outline shows __________ among __________. connections . . . vacation destinations bonds . . . atomic elements associations . . . clauses and phrases relationships . . . main points

Answers

Answer 1
Answer: An outline shows relationships among main points. It is very important to have an outline when writing an article or an essay because it helps the writer organize the paragraphs in such a way that the idea is clearly conveyed to the audience. In essence, an outline helps the writer give cohesion when it is time for the actual writing of the article or literary work.

Related Questions

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What mass of solute is needed to prepare each of the following solutions? a. 3.00 L of 0.125 M K2SO4 b. 550 mL of 0.015 M NaF c. 700 mL of 0.350 M C6H12O6
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The ___________________ in the mouth secrete enzymes which help prepare the food for digestion in the stomach.a. teeth
B.tongue
C.salivary glands
D.pancreas

Answers

The salivary glands in the mouth secrete enzymes which help prepare the food for digestion in the stomach.

Answer: salivary glands

Explanation:

this is the correction i got 100% correct

The force most responsible for holding the nucleus of an atom together is the:

Answers

Strong nuclear force. I think that's the one one that holds the nucleons together.

Consider the reaction: K2S(aq)+Co(NO3)2(aq)=2KNO3(aq)+CoS(s) what volume of 0.255 M K2S solution is required to completely react with 160 mL of 0.130 M Co(NO3)2?

Answers

The volume will be "81.6 mL".

The given reaction is:

  • K_2S(aq)+Co(NO_3)_2(aq) \rightarrow 2KNO_3(aq)+CoS(s)

The values are:

Molarity of K_2S,

  • M_1 = 0.215 M

Volume of Co(NO_3)_2,

  • V_2 = 160 \ mL

Molarity of C0(NO_3)_2,

  • M_2 = 0.130 \ M

As we know,

V_1 = (M_2 V_2)/(M_1)

By substituting the values, we get

       = (0.130* 160)/(0.255)

       = (20.8)/(0.255)

       = 81.6 \ mL

Learn more:

brainly.com/question/3583591

based off of the chemical equation given, you know that K₂S reacts with Co(NO₃)₂ in a 1 to 1 molar ratio.  That means that the number of moles of both reactants need to be equal for both of them to completely react with each other.  

You can find the number of moles of Co(NO₃)₂ by multiplying 0.130M by 0.160L to get 0.0208 moles of Co(NO₃)₂.  That means that you need to find a volume of 0.225M K₂S that contains 0.0208 moles of K₂S.  You can do this by dividing the 0.0208 by 0.255 to get 0.0816L of K₂S.  That means that you need 81.6mL of 0.255M K₂S to fully react with 160mL of 0.130M Co(NO₃)₂.

I hope this helps.  Let me know in the comments if anything is unclear.

How many atoms of carbon are in 24 grams of carbon?a) 1.2 x 10²⁴ atoms
b) 1.7 x 10²⁶ atoms
c) 1.2 x 10²⁵ atoms
d) 3.0 x 10²⁴ atoms
e) 3.0 x 10²³ atoms

Can anyone explain this one?

Answers

(3 grams of carbon) x (1 mole of carbon/12 grams ) =3/12 = 1/4 of a mole of carbon. Then... ( 1/4 of a mole) x (6.02 x 10^23 atoms/mole) = approximately 1.5 x 10^23 atoms.

Calcium reacts with water. This reaction is represented by the balanced equation below. The aqueous product of this reaction can be heated to evaporate the water, leaving a white solid, Ca(OH)2(s).Ca(s) + H2O(l) ==> Ca(OH)2(aq) + H2(g)

Compare the electrical conductivity of the aqueous product in the reaction to the electrical conductivity of the white solid that remains after the water is evaporated from the solution.

Write the chemical name of the base produced in the reaction.

State one change in reaction conditions that will increase the rate of the reaction.

Answers

Answer:

- Calcium is more conductive than calcium hydroxide.

- Calcium hydroxide.

- Addition of more either calcium or water to the reaction vessel

Explanation:

Hello,

In this case, based on the given reaction and information, calcium's electrical conductivity 0.298 106/(cm*Ω) which is a relatively high value compared to it its base has due to its large insolubility.

In addition, the name of the formed base is calcium hydroxide based on the IUPAC rules.

Moreover, the addition of more either calcium or water to the reaction vessel will generate more calcium hydroxide.

Best regards.

The aqueous product conducts electricity while the solid does not. Ionic solids do not conduct electricity, but ions dissolved in solution do.The chemical name of the base is calcium hydroxide.Increasing the temperature of the system would increase the rate of the reaction.

Does anyone know how to do this? the solubility of barium carbonate, BaCO3, is 0.0100 g/L. Its molar mass is 197.3 g/mol. What is the Ksp of barium carbonate?

Answers

The value of {{\text{K}}_{{\text{sp}}}} for barium carbonate is \boxed{{\text{2}}{{.6 * 1}}{{\text{0}}^{{\text{ - 9}}}}}.

Further explanation:

Solubility product constant:

The equilibrium constant between the compound and its ion, when dissolved in solution, is known as solubility product constant. It is denoted by {{\text{K}}_{{\text{sp}}}}. The solubility product constant is used to calculate the product of the concentration of ions at equilibrium.

Higher the solubility product constant more will be the solubility of the compound.

The general reaction is as follows:

{\text{AB}}\left({aq}\right)\to{{\text{A}}^+}\left({aq}\right)+{{\text{B}}^-}\left({aq}\right)

The expression to calculate the solubility product for the general reaction is as follows:

\boxed{{{\text{K}}_{{\text{sp}}}}=\left[{{{\text{A}}^+}}\right]\left[{{{\text{B}}^-}}\right]}

Here,

{{\text{K}}_{{\text{sp}}}} is the solubility product constant.

\left[ {{{\text{A}}^ + }} \right] is the concentration of {{\text{A}}^ + }ions.

\left[ {{{\text{B}}^ - }} \right]is the concentration of {{\text{B}}^ - }ions.

The dissociation of {\text{BaC}}{{\text{O}}_{\text{3}}} occurs as follows:

{\text{BaC}}{{\text{O}}_3}\to{\text{B}}{{\text{a}}^(2+)}+{\text{CO}}_3^(2-)

The given solubility of {\text{BaC}}{{\text{O}}_{\text{3}}} is 0.0100 g/L. Firstly, it is to be converted in mol/L. So the solubility of {\text{BaC}}{{\text{O}}_{\text{3}}} is calculated as follows:

{\text{Solubility of BaC}}{{\text{O}}_{\text{3}}}\left({{\text{mol/L}}}\right)= \frac{{{\text{Solubility of BaC}}{{\text{O}}_{\text{3}}}\left({{\text{g/L}}}\right)}}{{{\text{Molar mass of BaC}}{{\text{O}}_{\text{3}}}\left({{\text{g/mol}}}\right)}}      …… (1)

The solubility of {\text{BaC}}{{\text{O}}_{\text{3}}} is 0.0100 g/L.

The molar mass of {\text{BaC}}{{\text{O}}_{\text{3}}} is 197.3 g/mol.

Substitute these values in equation (1).

\begin{aligned}{\text{Solubility of BaC}}{{\text{O}}_{\text{3}}}&=\left( {\frac{{{\text{0}}{\text{.0100 g}}}}{{{\text{1 L}}}}}\right)\left({\frac{{{\text{1 mol}}}}{{{\text{197}}{\text{.3 g}}}}} \right)\n&=0.00005068\;{\text{mol/L}}\n\end{aligned}

It is evident from the chemical equation, one mole of {\text{BaC}}{{\text{O}}_{\text{3}}} dissociates to form one mole of {\text{B}}{{\text{a}}^(2+)} and one mole of {\text{CO}}_3^(2-). So the solubility of both {\text{B}}{{\text{a}}^(2+)} and {\text{CO}}_3^(2-)is 0.00005068 mol/L.

The formula to calculate the solubility product of  is as follows:

{{\text{K}}_{{\text{sp}}}}=\left[{{\text{B}}{{\text{a}}^{{\text{2+}}}}}\right]\left[{{\text{CO}}{{_3^2}^-}}\right]                                      …… (2)

Substitute 0.00005068 mol/L for\left[{{\text{B}}{{\text{a}}^{{\text{2+}}}}}\right] and 0.00005068 mol/L for \left[{{\text{CO}}_3^(2-)}\right]in equation (2).

\begin{aligned}{{\text{K}}_{{\text{sp}}}}&=\left({{\text{0}}{\text{.00005068}}} \right)\left({{\text{0}}{\text{.00005068}}}\right)\n&=2.6*{10^(-9)}\n\end{aligned}

Therefore, the value of {{\mathbf{K}}_{{\mathbf{sp}} for {\mathbf{BaC}}{{\mathbf{O}}_{\mathbf{3} is {\mathbf{2}}{\mathbf{.6 * 1}}{{\mathbf{0}}^(-9)}.

Learn more:

1. Sort the solubility of gas will increase or decrease: brainly.com/question/2802008.

2. What is the pressure of the gas?: brainly.com/question/6340739.

Answer details:

Grade: School School

Subject: Chemistry

Chapter: Chemical equilibrium

Keywords: solubility, Ba2+, CO32-, BaCO3, Ksp, solubility product, molar mass, 197.3 g/mol, mol/L, g/L, 0.0100 g/L.

It's simple, just follow my steps.

1º - in 1 L we have 0.0100~g of BaCO_3

2º - let's find the number of moles.

\eta=(m)/(MM)

\eta=(0.0100)/(197.3)

\boxed{\boxed{\eta=5.07*10^(-5)~mol}}

3º - The concentration will be

C=5.07*10^(-5)~mol/L

But we have this reaction

BaCO_3\rightleftharpoons Ba^(2+)+CO_3^(2-)

This concentration will be the concentration of Ba^(2+)~~and~~CO_3^(2-)

K_(sp)=([Ba^(2+)][CO_3^(2-)])/([BaCO_3])

considering [BaCO_3]=1~mol/L

K_(sp)=[Ba^(2+)][CO_3^(2-)]

and

[Ba^(2+)]=[CO_3^(2-)]=5.07*10^(-5)~mol/L

We can replace it

K_(sp)=(5.07*10^(-5))*(5.07*10^(-5))

K_(sp)\approx25.70*10^(-10)

Therefore the K_(sp) is:

\boxed{\boxed{\boxed{K_(sp)\approx2.57*10^(-11)}}}