CHEMISTRY HIGH SCHOOL

Acids form __________ ions in water.a. hydrogen
c. positive
b. hydroxide
d. both a and c

Answers

Answer 1
Answer: Hydroxide is for bases, so that is wrong. Hydrogen is for acids, which is correct. 

Answer: Hydrogen 
Answer 2
Answer:

answer: THIS IS CORRECT I TOOK THE TEST D: BOTH A AND C

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What is the affect of increasing the water's mass?how does it reflect it's temperature?

Answers

I assume what you're asking about is, how does the temperature changes when we increase water's mass, according the formula for heat ? 
Well the formula is : Q=m\cdot c\cdot \Delta t (where Q is heat, m is mass, c is specific heat and \Delta t is change in temperature. So according this formula, increasing mass will increase the substance's heat, but won't effect it's temperature since they are not related. Unless,  if you want to keep the substance's heat constant, in that case when you increase it's mass you will have to decrease the temperature

How would the equilibrium change if NO2 were added to SO2(g) + NO2(g) NO(g) + SO3(g) + heat?A. The equilibrium constant would increase.
B. The amount of NO and SO3 would decrease.
C. The amount of NO and SO3 would increase.
D. The amount of NO2 and SO2 would increase.

Answers

The answer to this question would be that the amount of No and SO3 would increase. The correct choice is C. 

The equilibrium of this chemical reaction would change if NO₂ were added because: C. the amount of NO and SO₃ would increase.

What is an equilibrium?

An equilibrium can be defined as a condition in which there is no net change in the amounts of both reactants and products with respect to time, during a reversible chemical reaction.

This ultimately implies that, the rate of the forwardchemical reaction is equal to the rate of the backwardchemical reaction at equilibrium.

In this context, we can infer and logically conclude that the equilibrium of this chemical reaction would change when NO₂ is added because the amount of NO and SO₃ would increase:

                      SO₂(g) + NO₂(g) ⇆ NO(g) + SO₃(g) + heat

Read more on equilibrium here: brainly.com/question/5081082

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When an electron is displaced in a semiconductor, the hole that's left behind isA. attracted to the negative terminal of the voltage source.
B. attracted to the anode of the voltage source.
C. considered an impurity in the crystal.
D. incapable of carrying a charge.

(D. is wrong)

Answers

answer is A : attracted to the negative terminal of the voltage source
 I think, that the "hole"moves as it captures a free electron leaving another hole in a slightly different place. The electron leaving leaves a net + charge, which is attracted to the negative terminal. Because the "hole" behaves as a positive charge it is attracted towards the negative terminal.

Answer:

A. attracted to the negative terminal of the voltage source.

Explanation:

bc that is what the hole that's left behind does

Smooth muscles can be found in each of the organs below exceptA. the stomach
B. the small intestine
C. the heart
D. the large intestine

Answers

c. the heart

Smooth muscles are the type of muscles that can be found in the organs like the stomach, the small intestine and the large intestine however, smooth muscles cannot be found in the heart. A smooth muscle is also called as the involuntary muscle which means that it cannot be controlled and that it contracts or expands without you telling these muscles to do so. They can also be found on the walls of the other inner organs like the bladder, uterus and blood vessels. These type of muscles has longer or almost permanent contractions compared to that of the skeletal muscles.
C, the heart, because the heart is Cardiac Muscle.

If the pressure P applied to a gas is increased while the gas is held at a constant temperature, then the volume V of the gas will decrease. The rate of change of the volume of gas with respect to the pressure is proportional to the reciprocal of the square of the pressure. Which of the following is a differential equation that could describe this relationship?

Answers

The differential relationship has been \rm \bold{(dV)/(dP)\;=\;(C)/(P^2)}.

The gas has been termed to be the ideal gas. For an ideal gas at a constant temperature, the relationship of the change in pressure and volume can be given as constant. The relationship has been given with the application of Boyle's law.

The product of the pressure and volume has been a constant quantity for a reaction.

Pressure * Volume = Constant

PV = C

V = \rm (C)/(P)

Differentiating the equation:

\rm (dV)/(dt)\;=\;(C)/(P^2)\;(dP)/(dt)

\rm (dV)/(dt)\;*\;(dt)/(dP)\;=\;(C)/(P^2)

\rm (dV)/(dP)\;=\;(C)/(P^2)

The differential relationship has been \rm \bold{(dV)/(dP)\;=\;(C)/(P^2)}.

For more information about pressure at a constant temperature, refer to the link:

brainly.com/question/12152879?

Answer:

A differential equation that could describe the relationship of the rate of change of the volume of gas with respect to the pressure is;

V' = -(C)/(P^2).

Explanation:

Boyle's law states that at constant temperature, the pressure of a given mass of gas is inversely proportional to its volume.

That is;

P₁×V₁ = P₂×V₂ or

P×V = Constant, C

That is V = (C)/(P)

Therefore, the rate of change of volume of a gas is given as

(dV)/(dt) = -(C)/(P^2) (dP)/(dt) which gives

(dV)/(dt) * (dt)/(dP)= (dV)/(dP) = -(C)/(P^2)

That is the rate of change of the volume of gas with respect to the pressure is proportional to the reciprocal of the square of the pressure.

(dV)/(dP) = -(C)/(P^2).

V' = -(C)/(P^2).

Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. Your calculator answer would be 11.76 cm2 . Now suppose you are asked to enter the answer to two significant figures. (Note that if you do not round your answer to two significant figures, your answer will fall outside of the grading tolerance and be graded as incorrect.)

Answers

1) ALL non-zero numbers (1,2,3,4,5,6,7,8,9) are ALWAYS significant.2) ALL zeroes between non-zero numbers are ALWAYS significant.3) ALL zeroes which are SIMULTANEOUSLY to the right of the decimal point AND at the end of the number are ALWAYS significant.4) ALL zeroes which are to the left of a written decimal point and are in a number >= 10 are ALWAYS significant.

so it will be 11.76 = 12 bc 7 rounds up
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