Which of the following is a change from a less condensed to a more condensed state of matter?A.) Boiling
B.) Evaporating
C.) Condensation
D.) Melting

Answers

Answer 1
Answer: The answer is C. Condensation is a change from a less condensed to a more condensed state of matter. It is a phase change from the gas state to liquid state. The gas is the less condensed state and the liquid is the more condensed state as compared to gas.

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Why is H2SO4 regarded as an ampholyte

Answers

I think sulfuric acid cannot be regarded as an ampholyte. Ampholytes are amphoteric molecules or that contains both acidic and basic groups. An amphoteric compound can react both as an acid and a base which sulfuric acid is not capable.

Which is a molecule?
A. Ne
B. NaCL
C. Trail Mix
D. graphene

Answers

B) NaCl is a molecule.

Choose the letter of the choice that best completes the statement or answers the question. Elements in the same group have the same __________. A. atomic radius
B. energy level of outer electrons
C. nuclear charge
D. number of valence electrons

Answers

I think the correct answer from the choices listed above is option D. Elements in the same group have the same number of valence electrons. They have the same number of electrons in the outer orbital. They are the electrons that are involved with chemical bonding with other elements.
Elements in the same group have D. Same number of valence electrons.

What is the total mass of 2.0 moles of diatomic hydrogen?

Answers

Explanation:

A diatomic molecule is defined as the molecule which contains two atoms.

For example, a H_(2) molecule has two atoms of hydrogen.

Molar mass of a H_(2) molecule is 2.0 g/mol. Therefore, calculate the mass of 2.0 moles of diatomic hydrogen as follows.

        No. of moles = \frac{mass}{\text{molar mass}}

                2.0 mol = (mass)/(2.0 g/mol)

                mass = 1 g

therefore, we can conclude that total mass of 2.0 moles of diatomic hydrogen is 1 g.

diatomic hydrogen is written as H2                                                                                (2.02 grams H2) <------- if each hydrogen atom is 1.01 grams, then two hydrogen atoms are 2.02 grams                                                                                                                  2.0 moles H2 X 2.02 grams H2                                                                                             ------------- (divide to cancel moles)   = 4.04 grams/mole H2 ÷ one mole = 4.04 grams H2

                                                          

Which of the following materials is damaged by acid rain

Answers

What are the options?

According to Hess’s law, if a series of intermediate reactions are combined, the enthalpy change of the overall reaction isthe difference between the enthalpies of the intermediate reactions.
the sum of the enthalpy changes of the intermediate reactions.
the product of the enthalpy changes of the intermediate reactions.
the fraction of the individual enthalpies of the intermediate reactions.

Answers

Answer : The correct option is, the sum of the enthalpy changes of the intermediate reactions.

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

For example :

The formation reaction of CO will be,

C(graphite)+(1)/(2)O_2(g)\rightarrow CO(g)    \Delta H_(formation)

The intermediate balanced chemical reaction will be,

(1) C(graphite)+(1)/(2)O_2(g)\rightarrow CO_2(g)    \Delta H_1

(2)CO+(1)/(2)O_2(g)\rightarrow CO_2(g)    \Delta H_2

The expression for enthalpy of formation of CO is,

\Delta H_(formation)=[n* \Delta H_1]+[n* \Delta H_2]

where,

n = number of moles

By adding reaction 1 and reverse reaction of reaction 2, we get the enthalpy of formation of CO.

Hence, the correct option is, the sum of the enthalpy changes of the intermediate reactions.

I think the answer is B. the sum of the enthalpy changes of the intermidiate reactions