Why does salt dissolve in water?

Answers

Answer 1

Answer: The water dissolves the salt because the water molecules are able to interact with the salt-forming particles, called ions. When the water Interacts with the trainers of the salt ions, the solid salt crystal structure Suffers breakdown, until the trainers of the salt ions are completely surrounded by water molecules. At this time the salt is fully dissolved by water.

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Related Questions

The density of a liquid gold is 19.32 g/mL. If you were to fill a 2.000 liter soda bottle with gold what would the mass of the liquid be?
The diagram shows a ball resting at the top of a hill. Which statement best describes the energy in this system
Carbonic acid dissolves limestone and other rocks. This is an example of _____. chemical errosion
Under conditions when glucose oxidation is elevated, the acetyl-CoA produced will allosterically activate which of the following enzymes leading to an increase in the production of oxaloacetate?a. Pyruvate carboxylase b. Citrate lyase c. Acetyl-CoA carboxylase d. Malate dehydrogenase
Which of the following substance is not an acid? 1. Substance A is tested and found to have a pH of 3. 2. Substance B, a common food, tastes sour. 3. Substance C causes metals to corrode. 4. Substance D feels slippery in solution.

What are some non examples of systems.

Answers

Solar systems nuclear systems there are all types of systems which one do you prefer

As the result of experimental work, a student finds the density of a liquid to be .137 g/ml. the known density of the liquid is .1478 g/ml. find the student's experimental error (ee) and percentage error (pe).

Answers

the known density of the liquid is

$d_known = 0.1478 g /ml$

the density of a liquid

$d_calculated = 0.137 g /mol$

$experimental error = d_known – d_calculated$

$= 0.1478 – 0.137 = 0.0108 g /mL$

Thus, experimental error of 0.0108 g /mL is present.

$Percentage error = [ (d_known – d_calculated) / (d_known) ] * 100$

$=[ (0.0108) / 0.1478 ] * 100$

$= 7.31 %$

Thus, Percentage error of 7.31 % is present.

You fill a balloon with 0.77 moles of gas at 36°C at a pressure of 1 atm. What is the volume of the balloon?

Answers

The volume of the balloon can be calculated using the ideal gas law:

V = nRT/P

where:
n = number of moles of gas (0.77 moles in this case)
R = the ideal gas constant (0.08206 L·atm/(mol·K))
T = temperature in Kelvin (36°C + 273.15 = 309.15 K)
P = pressure (1 atm)

Plugging in the values, we get:

V = (0.77 mol)(0.08206 L·atm/(mol·K))(309.15 K)/(1 atm) ≈ 19.7 L
the volume of the balloon is approximately 19.7 liters.

Will a double replacement reaction occur if a potassium hydroxide solution is mixed with a lead(II) nitrate solution? Briefly explain.

Answers

Explanation:

A chemical reaction equation that contains same number of atoms on both reactant and product side is known as a balanced chemical reaction equation.

And, when positive and negative ions of the two reactant species exchange their position then this type of reaction is known as double replacement reaction.

For example, $KOH + Pb(NO_(3))_(2) \rightarrow KNO_(3) + Pb(OH)_(2)$

Here, number of reactant molecules are as follows.

K = 1

OH = 1

Pb = 1

$NO_(3)$ = 2

Number of product molecules are as follows.

K = 1

OH = 2

Pb = 1

$NO_(3)$ = 1

Hence, to balance this equation multiply KOH by 2 on reactant side and multiply $KNO_(3)$ by 2 on product side.

Therefore, the balanced chemical reaction equation is as follows.

$2KOH + Pb(NO_(3))_(2) \rightarrow 2KNO_(3) + Pb(OH)_(2)$

Since, both positive and negative ions on the reactant side get exchanged. Hence, it is a double replacement reaction.

No - a precipitation will occur though. Potassium nitrate is soluble in water, so the potassium and nitrate ions will remain spectator ions and stay in solution. Lead (II) hydroxide is not soluble, and will precipitate out of solution to form a solid product.

1. Use the chemical equation of Photosynthesis to answer the following prompts.Answer in complete sentences.
6CO2 + 6H2O --> C6H12O6 +602
1. Identify evidence that a chemical reaction has occurred.
2. What element is the most abundant in this chemical reaction?
3. Identify the number of protons, neutrons, and electrons found in the most
abundant element.
4. Identify where we would find the protons, neutrons, and electrons in the
atom of this element.
5. Identify the group and period of the element on the Periodic Table.
swer

Answers

Answer:

1. The evidence that chemical reaction has occurred can be found in the change of the reagents present after the reaction, that is formation of glucose in the area where the reaction is taking place

2. The most abundant element of the chemical reaction is oxygen which has a total quantity of 18 atoms in the reaction

3. The oxygen atom has an atomic number of 8 and therefore contains 8 protons and 8 neutrons and (therefore) 8 electrons (to be neutral, electronically)

4. The protons and the neutrons of the atom, oxygen, are located in the nucleus, while the electron are found in the different orbitals surrounding the atom

5. The element, oxygen, symbol, O, belongs to the group 16 of period 2 in the periodic table

Explanation:

A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. What is the final volume, in liters, when each of the following changes occurs in the quantity of the gas at a constant pressure and temperature?A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.
B. A sample of 2.00 g of O2 is removed.
C. A sample of 4.00 g of O2 is added to the 4.80 g of O2 gas in the container.

Answers

The correct answer for the question that is being presented above is this one: "A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container." A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. The final volume, in liters, when each of the following changes occurs in the quantity of the gas at a constant pressure and temperature is that A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.

Final answer:

By using the ideal gas law and molar mass calculations, the final volumes are found to be A. 65.0 L, B. 8.75 L, and C. 27.5 L.

Explanation:

To calculate the final volume when additional O2 is added or when some O2 is removed, we can use the concept of the molar mass and the ideal gas law that states that volume is directly proportional to the amount of gas, assuming pressure and temperature is constant.

The molar mass of O2 is approximately 32.00 g/mol.

A. 0.500 moles of O2 is added. This equals 0.500 * 32 g = 16 g. The total mass in the system is now 20.8 g. If the original 15.0 L represented 4.80 g, now 20.8 g would represent 15.0 L * 20.8/4.80 = 65.0 L.

B. 2.00 g of O2 is removed. So, the total mass in the system is now 2.80 g. If the original 15.0 L represented 4.80 g, now 2.80 g would represent 15.0 L * 2.80/4.80 = 8.75 L.

C. 4.00 g of O2 is added. So, the total mass in the system is now 8.80 g. If the original 15.0 L represented 4.80 g, now 8.80 g would represent 15.0 L * 8.80/4.80 = 27.5 L.

Learn more about Gas Laws here:

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