Carbonic acid dissolves limestone and other rocks. This is an example of _____. chemical errosion

Answers

Answer 1
Answer:

Carbonic acid dissolves limestone and other rocks. This is an example of chemical erosion. An example is in the caves. Caves are formed where rainwater as it falls through the atmosphere absorbs carbon dioxide. The carbon dioxide makes the rain acidic to react it with the limestone bedrock. The rainwater is absorbed by the soil into the ground. Then as it enters through the soil, the rainwater will absorb more carbon dioxide that is produced by the decomposers. The carbon dioxide with water reacts to form carbonic acid. The carbonic acid will react to limestone and dissolves it slowly. As the space become larger, water can enter into it.

Answer 2
Answer:

Answer:

chemical errosion

Explanation:


Related Questions

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Which of the following is not a state of matter?A. solidB. liquidC. waterD. plasma
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Given the balanced equation representing a reaction:CH4(g) + 2O2(g) --> 2H2O(g) + CO2(g) + heat
Which statement is true about energy in this reaction?
(1) The reaction is exothermic because it releases heat.
(2) The reaction is exothermic because it absorbs heat.
(3) The reaction is endothermic because it releases heat.
(4) The reaction is endothermic because it absorbs heat.

Answers

The answer is (1) the reaction is exothermic because it releases heat. From the reaction, we can see that the heat is at the right of the equation which means the reaction releases heat. So it is called exothermic reaction. Endothermic reaction absorbs heat.

Answer: The answer is (2) the reaction is exothermic because it releases heat.

Morant Bay is 33 km south of Port Antonio a pigeon can fly at a speed of 1.2 m s what is the displacement of morant bay from Port Antonio​

Answers

Answer:

33km due south

Explanation:

Morant Bay is 33km south of Port Antonio;

  Problem: displacement of Morant bay from Port Antonio;

Displacement is a vector quantity. It is the length of path between two position and the direction inclusive.

So, it has magnitude and must be specified with a direction.

  • Therefore, the displacement of Morant Bay from Port Antonio is 33km due south.

A brick measures 25 cm by 12 cm by 13 cm. What is the volume of the brick in cm3? How many millilitters of water would this brick displace?

Answers

Answer:

Volume of brick = 3900 cm3 = 3.9*10^3 cm3

Volume of water displaced = 3900 ml = 3.9*10^3 ml

Explanation:

Given:

Dimension of the brick = 25 cm, 12 cm, 13 cm

To determine:

a) Volume of the brick

b) Volume (ml) of water displaced by the brick

Calculation:

a) Volume of the brick (cube) is expressed as a product of the dimensions

Volume = length (l)*width(w)*height(h)

Volume = 25cm*12cm*13 cm = 3900cm^(3) = 3.9*10^(3) cm^(3)

b) The volume of water displaced is equal to  the volume of the brick.

Since, 1 ml = 1 cm3

Therefore, volume of water displaced = 3900 ml = 3.9*10^3 ml

25 cm x 12 cm x 13 cm = 3900 cm^3 Water has a density of 1 mL/cm^3, so the brick would displace 3900 mL of water.

How does the number of protons compare to the number ofelectrons in an anion?
a There are more electrons than protons.
b There are more protons than electrons.
c
There is no consistent relationship between the
numbers of protons and electrons.
d There are equal numbers of protons and electrons.

Answers

It is A).
Electrons are negatively charged and an anion is a negatively charged ion so that means there is more electrons(negative charge) than protons(positive charge) in an anion

Answer:B is the right answer

Explanation:

Which compound has the highest percent composition by mass of strontium?

Answers

Assuming all the compounds of interest are given. We proceed on the theoretical way of answering this question. Assume 1 gram of each compound. Multiply it by the reciprocal of the molar mass of the compound. Then multiply it by the molar ratio of the Strontium to the compound. Then, multiply it by the molar mass of strontium. Finally divide this answer by 1 gram and multiply by 100. 

Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions. Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) S (s) (nonspontaneous)? Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq) (nonspontaneous)? 2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq) (spontaneous?) Are these correct?

Answers

A electrochemical reaction is said to be spontaneous, if E^(0) cell is positive. 

Answer 1:
Consider reactionNi^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s) 

The cell representation of above reaction is given by;
    
S^(2-)/S // Ni^(2+)/Ni

Hence, E^(0)cell = E^(0) Ni^(2+/Ni) - E^(0) S/S^(2-)
we know that, {E^(0) Ni^(2+)/Ni = -0.25 v
and {E^(0) S/ S^(2-) = -0.47 v

Therefore, E^(0) cell = - 0.25 - (-0.47) = 0.22 v

Since,  E^(0) cell is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2: 
Consider reactionPb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)

The cell representation of above reaction is given by;
    H_(2) / H^(+) // Pb^(2+) /Pb

Hence, E^(0)cell = E^(0) Pb/Pb^(2+) - E^(0) H_(2)/H^(+)
we know that, {E^(0) Pb^(2+)/Pb = -0.126 v
and {E^(0) H_(2)/ H^(+) = -0 v

Therefore, E^(0) cell = - 0.126 - 0 = -0.126 v

Since,  E^(0) cell is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3
Consider reaction2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)

The cell representation of above reaction is given by;
    Cr/Cr^(2+) // Ag^(+)/Ag

Hence, E^(0)cell = E^(0) Ag^(+)/Ag - E^(0) Cr/Cr^(2+)
we know that, {E^(0) Ag^(+)/Ag = -0.22 v
and {E^(0) Cr/ Cr^(2+) = -0.913 v

Therefore, E^(0) cell = - 0.22 - (-0.913) = 0.693 v

Since,  E^(0) cell is positive, hence cell reaction is spontaneous

Answer: Ni^(2+)(aq)+S^(2-)(aq)\rightarrow Ni(s)+S(s)  : non spontaneous

Pb^(2+)(aq)+H_2(g)\rightarrow Pb(s)+2H^+(aq)  : non spontaneous

2Ag^(+)(aq)+Cr(s)\rightarrow 2Ag(s)+Cr^(2+)(aq)  : spontaneous

Explanation:

a) Ni^(2+)(aq)+S^(2-)(aq)\rightarrow Ni(s)+S(s)

Here S undergoes oxidation by loss of electrons, thus act as anode. Ni undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_(cathode)- E^0_(anode)

Where both E^0 are standard reduction potentials.

E^0_([Ni^(2+)/Ni])=-0.25V

E^0_([S^(2-)/S])=0.407VV

E^0=E^0_([Ni^(2+)/Ni])- E^0_([S^(2-)/S])

E^0=-0.25-(0.407V)-0.657V

As value of E^0 is negative, the reaction is non spontaneous.

b)Pb^(2+)(aq)+H_2(g)\rightarrow Pb(s)+2H^+(aq)

Here Hydrogen undergoes oxidation by loss of electrons, thus act as anode. Pb undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_(cathode)- E^0_(anode)

Where both E^0 are standard reduction potentials.

E^0_([Pb^(2+)/Pb])=-0.13

E^0_([H^(+)/H_2])=0V

E^0=E^0_([Pb^(2+)/Pb])- E^0_([H^(+)/H_2])

E^0=-0.13-(0V)=-0.13V

As value of E^0 is negative, the reaction is non spontaneous.

c) 2Ag^(+)(aq)+Cr(s)\rightarrow 2Ag(s)+Cr^(2+)(aq)

Here Cr undergoes oxidation by loss of electrons, thus act as anode. Ag undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_(cathode)- E^0_(anode)

Where both E^0 are standard reduction potentials.

E^0_([Ag^(+)/Ag])=+0.80V

E^0_([Cr^(2+)/Cr])=-0.913V

E^0=E^0_([Ag^(+)/Ag])- E^0_([Cr^(2+)/Cr])

E^0=+0.80-(-0.913V)=1.713V

As value of E^0 is positive, the reaction is spontaneous.