CHEMISTRY HIGH SCHOOL

What subatomic particles have a charge? (pick all that apply)Protons
Neutrons
Electrons

Answers

Answer 1

Answer:

Answer:

Protons- positive

Electrons - negative

Explanation:

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What triggers the small earthquakes that occur around a volcano before an eruption

Answers

Before the eruption,the fluid pressure from the rising magma (dense liquid) cracks the rocsk, the tectonic plates under the Earth's crust are moved and as a result earthquakes are caused. Manu small earthquakes in the area near a volcano hint what may happen.

Which of the following is an example of improved functioning as related to the benefits of muscular strength and endurance training?a. having stronger bones
b. easier to do household chores
c. lower blood pressure
d. larger lung capacity

Answers

I believe the answer is letter A

Answer:

Explanation:

What is the percent by mass of oxygen in carbon dioxide (CO2)?

Answers

72.7% is the percent by mass of oxygen in carbon dioxide. A percent is obtained by multiplying the result by 100.

One approach to show the concentration for an element within a compound or component in a combination is as a mass percentage. The mass percentage is computed by dividing the total weight of the combination by the mass of each component and multiplying the result by 100%. The mass percent is calculated by dividing the mass that contains the compound and solute by the mass for the element or solute.

Molar mass of oxygen = 32 g/mole

Molar mass of carbon dioxide = 44 g/mole

mass percentage of oxygen =(molar mass of oxygen/molar mass of carbon dioxide)× 100

=(32/44)× 100

=72.7%

To know more about mass percentage, here:

brainly.com/question/32197511

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Answer : The percent by mass of oxygen in carbon dioxide is, 72.72%

Solution : Given,

Molar mass of oxygen = 16 g/mole

Molar mass of carbon dioxide = 44 g/mole

As we know that there are 2 atoms of oxygen and 1 atom of carbon present in the carbon dioxide.

So, the molar mass of oxygen, $O_2$ = 2 × 16 = 32 g/mole

Now we have to calculate the percent by mass of oxygen in carbon dioxide.

$\%\text{ by mass of oxygen}=\frac{\text{Molar mass of oxygen}}{\text{Molar mass of }CO_2}* 100$

Now put all the given values in this expression, we get

$\%\text{ by mass of oxygen}=(32g/mole)/(44g/mole)* 100=72.72\%$

Therefore, the percent by mass of oxygen in carbon dioxide is, 72.72%

Predict the changes in the number of particles based the diagram.A) Pressure is indirectly related to moles.
B) Volume is proportionally related to moles.
C) Moles remains constant as pressure changes.
D) Temperature is directly related to the moles.

Answers

Pressure is indirectly related to volume.

As the volume increases at a constant temperature, the pressure decreases.

The changes in the number of particles based on the diagram is that Volume is proportionally related to moles. The answer is letter B. The rest of the choices do not answer the question above.

What is the % yield of CO2 if 10g of CO produces 12.8 g CO2?
2CO + O2 → 2CO2

Answers

Moles CO = 10.0 g / 28.01 g/mol = 0.357
the ratio between CO and CO2 is 2 : 2 ( or 1 : 1) so we would get 0.357 mole of CO2 ( 100% yield)

mass CO2 = 0.357 mol x 44.0098 g/mol = 15.7 g ( theoretical yield)

% yield = 12.8 x 100 / 15.7 = 81.5

Hope this helps.

The % yield is 81.5 :DDDDDD

How many electron are in 56fe 3

Answers

The periodic table is arranged in a way so that with each step the number of protons in the nucleus is increased by 1. It makes it for an easy choice to designate elements with numbers - atomic numbers, because in that case atomic number shows the number of protons possessed by the nucleus. Like this:
H has 1 proton
He has 2 protons
Li has 3 protons
Be has 4 protons and so on

Each proton has a charge of +1. The other particle present in the nucleus - the neutron - has zero electrical charge and thus irrelevant when computing the charge of a nucleus. It is easy to deduce that the nucleus charge equals the number of protons (which in turn equals the atomic number). So the nucleus charges are:
for H it's+1
for He it's +2
for Li it's +3
for Be it's +4 and so on

Atom is an electroneutral particle by definition. It means it's summed charge must be 0. Since we've looked at everything within the nucleus (the protons and the neutrons) it's time we turn our gaze to the space around it, which is full of orbiting electrons. Each electron has a charge of -1. To make up for the positive charge in the nucleus you have to fill the space aroung the nucleus with negative electrons.Thanks to the elementary nature of both proton and electron charge, you simply have to take the same number of electrons as that of protons! Like this:
H has 1 proton and 1 electron
He has 2 protons and 2 electrons
Li has 3 protons and 3 electrons
Be has 4 protons and 4 electrons and so on

Fe has atomic number 26. It means that Fe has 26 protons and 26 electrons. If it's a neutral atom

You typed 3. Is it accidental? If so, then the answer is above. If not, then you could be trying to type 56Fe +3, which means an ionic iron with charge +3. Charges are formed when you have too many or too few electrons to counter-balance the prositive charge of the nucleus. Charge +3 means you're 3 electrons short to negate the nucleus positive charge.

In other words, Fe+3 has 26 protons and 23 electrons.

Final answer:

56Fe3+ is an iron ion with a charge of +3, meaning it has 23 electrons after 3 electrons are lost from the uncharged state. It loses the 4s2 electrons first, then one of the 3d electrons.

Explanation:

The student's question refers to 56Fe3+. 56Fe3+ is an iron ion with a charge of +3, which means it has lost three electrons. Understanding the Electron configuration is vital here. Normally, iron (Fe) has 26 electrons as its atomic number is 26. Each electron has a negative charge. But in 56Fe3+, 3 electrons are lost; hence, it will have 23 electrons.

Let's look further into this. The electron configuration of an uncharged Fe atom is 1s²2s²2p6 3s²3p6 4s²3d6. The iron atom loses the 4s2 electrons first (becoming Fe2+), then one of the 3d electrons (becoming Fe3+ or 56Fe3+ as indicated in the question).