CHEMISTRY HIGH SCHOOL

Which of the following substance is not an acid? 1. Substance A is tested and found to have a pH of 3. 2. Substance B, a common food, tastes sour. 3. Substance C causes metals to corrode. 4. Substance D feels slippery in solution.

Answers

Answer 1
Answer:

Answer

  • The correct option is 4. feel slippery.

Explanation:

Acid and base have different characteristic which identify either it is acid or base.

1. Substance A is tested and found to have a pH of 3.

This option is for acid because acid have pH in the range of 0-6

2. Substance B, a common food, tastes sour?

This option is also for acid because acid have sour taste.

3. Substance C causes metals to corrode.

This option is also for acid because acid can cause corrosion

4. Substance D feels slippery in solution

This option is not for acid but it is for base because bases have the properties of slippery.
Answer 2
Answer: Substance d as it's the only one with none acid traits

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Given the equation: 2Na + 2H2O → 2NaOH + H2 Which substance in this equation is a binary compound?

Phosphorus is most abundant in the

Answers

Phosphorus is about 0.099% in the Earth's crust. Among the elements in Group 15 in the periodic table,  it is the most abundant. Also, it is the most dispersed element in nature. However, it does not occur as a free element. It occurs as a compound.

Mendeleev’s principle of chemical periodicity states that when the elements are arranged according to their atomic numbers. This periodic law allows elements with similar properties to appear at regular intervals. Predict the group of elements and their number of valence electrons that will combine in a 2:1 ratio to with sodium. A)bromine, chlorine, iodine, 7
B)
sulfur, selenium, polonium, 6
Eliminate
C)
hydrogen, fluorine, potassium, 1
D)
calcium, phosphorus, tellurium, 2

Answers

The correct option is B.

Sodium will react with elements in GROUP 6, WHICH HAVE SIX ELECTRONS IN THEIR OUTERMOST SHELLS.

Sodium is a metal with atomic number 11. The electronic configuration of sodium is 2,8,1. This implies that, sodium has one electron in its outermost shell. Sodium always donate this electron in order to become stable. Elements in group 6 have six electrons in their outermost shells and they require two more electrons to attain stability. In order to form chemical bonds with elements from group 6, two atoms of sodium will react with each atom of those elements, that is, the ratio of reaction will be 2:1. By so doing, the two sodium atoms will be the ones that will donate the two electrons that the group 6 elements need to attain stability. One example of compounds formed by such reaction is sodium sulfide, Na2S.

The main part of this question is the "2:1 ratio."

On the periodic table, bromine, chlorine, and iodine have 7 valence electrons and sulfur, selenium, and polonium have 6, so these choices are viable based on their valence electrons. However, fluorine does not have 1 valence electron and phosphorus and tellurium do not have 2 valence electrons, so C) and D) are automatically out, leaving A) and B).

If we know that the sodium will combine in a 2:1 ratio, we know that the charge of the ions must have a 2:1 ratio too; that's how ionic compounds work. Sodium (Na) has an ion with a charge of +1 (Na+), so that means whatever ion it combines with in a 2:1 ratio must have a charge of -2   -   a 2:1 ratio.

Bromine, chlorine, and iodine have a charge of -1, but sulfur, selenium, and polonium have charges of -2. This gives us the correct answer as C).

Which of the following statements about ionic bonds is false?A) the resulting compound in a water solution can conduct electricity.
B) the resulting compound cannot be dissolved in water.
C) the resulting compound forms solid crystals.
D) the resulting compound has high melting and boiling points.

Answers

The answer is B) the resulting compound cannot be dissolved in water. Ionic compounds are, in fact, very soluble in water. They are known to dissociate in aqueous solutions, producing ions or charged atoms. This makes aqueous solutions of ionic compounds good conductors of electricity. As solids, ionic compounds form salt crystals. They have high melting and boiling points due to the strong ionic bond that holds them.

What is the general procedure from extracting a metal from its ore

Answers

Ores are naturally occurring rocks that contain metal or metal compounds in sufficient amounts to make it worthwhile extracting them. For example, iron ore is used to make iron and steel.

How many liters of 0.1107 M KCI contains 15.00 g of KCI (FW= 74.6 g/mol)

Answers

Answer:

1.81 liters of KCl solution

Explanation:

Molarity is expressed as:

Molarity=(molesofsolute)/(litersofsolution)

Solving for Liters of solution:

Liters of solution = (molesofsolute)/(Molarity) (1)

Using the molecular weight fo the KCl to find the moles of solute:

15.00gKCl*(1molKCl)/(74.6gKCl)=0.20molesKCl

Replacing in the formula (1):

Liters of solution = (0.20molesKCl)/(0.1107M)

Liters of solution = 1.81 liters
Number of moles:

n = sample mass / molar mass

n = 15.00 / 74.6

n = 0.2010 moles of KCl

Therefore:

Molarity = moles / Volume

0.1107 = 0.2010 / V

V = 0.2010 / 0.1107

V = 1.815 L 

Determine the unknown mineral using the information given below. Be sure to use significant figure rules when doing calculations. Mass is shown on the triple beam. Scale Test Mineral Mineral H. Density, g/cc 10 diamond tellurium 2 2.07 9 corundum galena 2.5 7.58 8 topaz anglesite 2.5 - 3 6.4 7 quartz chalcocite 2.5 - 3 5.6 6 feldspar copper 2.5 - 3 9.0 5 apatite gold 2.5 - 3 19.3 4 fluorite silver 2.5 - 3 10.5 3 calcite arsenic 3.5 5.7 2 gypsum barite 3 - 3.5 4.4 1 talc dolomite 3.5 - 4 2.9 platinum 4.5 21.5 willemite 5.5 4.0 magnetite 6 5.18 pyrite 6 - 6.5 5.02 pyrolusite 6 - 6.5 5.0 cassiterite 6.5 6.9 diamond 10 3.52 Volume of water displaced = 0.175 L Mass: g Density. g/cm³ Hardness: = - Determine the unknown mineral. Unknown mineral:

Answers

The unknown mineral is likely "barite" due to its density of approximately 0.0251 g/cm³, which closely matches the calculated density of the unknown mineral.

To determine the unknown mineral, we can use the given information about its mass, volume of water displaced, and density. Here are the steps to find the unknown mineral:

1. Calculate the density of the unknown mineral using the formula: Density (g/cm³) = Mass (g) / Volume (cm³).

2. Use the density value to identify the mineral from the provided list.

Given:

- Mass of the unknown mineral = mass on the triple beam = 4.4 g

- Volume of water displaced = 0.175 L = 175 cm³ (since 1 L = 1000 cm³)

Now, calculate the density of the unknown mineral:

Density (g/cm³) = Mass (g) / Volume (cm³)

Density = 4.4 g / 175 cm³ = 0.0251 g/cm³

The density of the unknown mineral is approximately 0.0251 g/cm³. Now, let's find the mineral with a similar density from the provided list:

Among the given minerals, the closest density match is with "barite." Barite has a density of approximately 4.4 g/cm³, which is quite close to the calculated density of the unknown mineral.

Therefore, the unknown mineral is likely "barite."

For more such questions on Mineral Identification

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Answer:

Mass: 981.0 g

Density: 5.61 g/cm^3

Hardness: = 2.5 - 3

Unknown material: Chalcocite

I just got a 100 on the test ^ so that is right
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