The diagram shows a ball resting at the top of a hill. Which statement best describes the energy in this system

Answers

Answer 1

Answer:

Option A is correct.

A.The potential energy in the system is greatest at X.

Explanation:

A ball resting at the top of a hill will have greatest potential energy because when an object is at rest it tend to have greatest potential energy. When It moves from position X to Y the potential energy of the ball will decrease and its kinetic energy will increase.

Answer 2

Answer:

Answer choices are listed below.

A.The potential energy in the system is greatest at X.

B.The kinetic energy in the system is greatest at X.
C.Total energy in the system decreases as the ball moves from X to Y.
D.Total energy in the system increases as the ball moves from X to Y.

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Which of the following contains both ionic and covalent bonding?KOH
N2O5
CH4
HBr

Answers

Answer: KOH

Explanation:

Being KOH the only not binary compound it is the candidate to be the one with two different type of bondings.

In fact, KOHis a ionic compound because the cation K⁺ forms a ionic bond with the anion OH⁻.

On the other hand, the oxigen and hydrogen atoms in OH⁻ are covalently bonded.

The ionic bond is the result of the union of two atoms with a high elecronegativity difference, while the covalent bonding is the result of a combination of two atoms whose electronegativities is not so different.

Being K and alkali metal (the elements with lowest electronegativity) and OH⁻ an anion, they easily form the ionic bond.

From tables, the electronegativity of H is 2.20 and the electronegativity of O is 3.16, which leads to a difference of 3.16 - 2.20 = 0.96. This difference is not enough to form ions but covalent bonds. That is why the bond O-H is covalent.

When you analyze the bonds of the other choices, N-O, C-H, and H-Br, y ou conclude that the electronegativities lead to covalent bonds too.

N2O5 contains both ionic and covalent bonding. The Option B.

Why does N2O5 contain both ionic and covalent bonding?

N2O5 also known as dinitrogen pentoxide, contains both ionic and covalent bonding. In this compound, the nitrogen atoms (N) form covalent bonds with each other resulting in the formation of a covalent molecule.

But the compound also contains oxygen atoms (O) that bond with the nitrogen atoms through ionic bonding. The oxygen atoms gain electrons from the nitrogen atoms leading to the formation of negative ions (NO3-) and positive ions (N2O4+).

Answers

Answer:

D - Silver has lower reactivity than hydrogen and cannot replace it

Explanation:

If we assume , Ag also reacts just like other metals as

Metal + H₂O ---> Metal Hydroxide + H₂

then Ag forms as

Ag + H2O ----->AgOH + $(1)/(2)$ H2

here Ag is converting into Ag⁺ and 2H⁺ are converting into H₂

for reaction Ag --->Ag⁺ + e⁻ E° = -0.799 V

for reaction H⁺ + e⁻ ----> $(1)/(2)$ H₂ E° = 0 V

by Adding those 2 above equations net E° will be -0.799 which is negative.As per Faradays Law

ΔG° = -nFE°

here we got E° as negative then ΔG° will be positive

As per thermodynamics if ΔG° is +ve then reaction is not feasible

so, then given reaction does not occur.....

Answer:

Silver has lower reactivity than hydrogen and cannot replace it

Explanation:

took test

Science fair ideas???

Answers

You can use a website called sciencebuddies to find a project

How many calories are there in 32 Calories

Answers

Answer:

Explanation:

1. Science is different than many other ways of thinking because it is based on-opinions
-facts
-personal viewpoints
-none of the above

Answers

Answer:

Facts

Explanation:

You can literally read the lesson it tells you science is

all about facts

Ammonia, NH3, can be classified as a base because in a chemical reaction with an acid, ammonia will (1 point)produce hydroxide ions in solution. produce hydronium ions in solution. donate a proton and become NH2–. accept a proton and become NH4+.

Answers

Answer: Option (d) is the correct answer.

Explanation:

Bases are the electron rich species which readily accept a proton. Therefore, when ammonia is classified as a base in a chemical reaction with an acid, it readily accepts a proton to give ammonium cation.

For example, the reaction of ammonia with hydrochloric acid will be as follows.

$NH_(3) + HCl \rightarrow NH^(+)_(4) + Cl^(-)$

Thus, we can conclude that ammonia, $NH_(3)$ , will accept a proton and become $NH^(+)_(4)$ .

NH will accept a proton and become NH4+

Bases follow $B^-+H^+=BH$ , with $B^-=NH_3$ in our case.

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