An Inhibitor is a substance that interferes with the action of a catalyst in a chemical reaction. A catalyst accelerates a reaction by providing an alternate mechanism with a lower activation energy. Inhibitors interrupt this process thereby reducing the efficacy of the catalyst.
A substance that interferes with the action of a catalyst in a chemical reaction is known as an Inhibitor. A catalyst is a substance that increases the rate of a chemical reaction without being changed in the process itself. It functions by offering an alternative mechanism for the reaction, typically involving a lower activation energy.
For instance, imagine a scenario where reactant substances are undergoing a change as indicated in a chemical equation. A catalyst interacts with a reactant to form an intermediate substance, which then decomposes or reacts with another reactant to regenerate the original catalyst and form the product successfully. However, an inhibitor disrupts this process, effectively decreasing the efficiency of the catalyst.
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More energy will be released from the old substance than the new substance will need to form its chemical bonds.
The color will change as a result of the reaction.
The substance will bubble as a result of the reaction.
Answer:
B
Explanation:
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB
B) unequal heating of different parts of earth
C) differences in elevation on different landmasses
D) greenhouse gases
(no guessing please )
In order to calculate the volume of 0.0023 moles of CO2, we use the ideal gas law and understand that one mole of an ideal gas at standard temperature and pressure occupies a volume of 22.4 liters. The volume for 0.0023 moles of CO2 is found to be approximately 0.05152 liters.
To solve for the volume of the 0.0023 moles of CO2, we need to use the ideal gas law, PV=nRT, where P depicts the pressure, V signifies the volume we need to find, n equals the number of moles, R denotes the universal gas constant, and T denotes the temperature. Assuming the relationship takes place at standard temperature and pressure (STP, 0 degrees Celsius, 1 atm), we can solve for V.
At STP, 1 mole of any ideal gas occupies a volume of 22.4 liters. Therefore, V = n * (Volume of 1 mole at STP), which equals 0.0023 moles * 22.4 L/mole = 0.05152 liters.
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