What type of change goes on inside when a glow stick is activated?Chemical
Physical
Both

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Answer 1
Answer:

Answer:

Chemical

Explanation:

Answer 2
Answer: chemical that’s your answer boy

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Gaseous methane (CH₄) reacts with gaseous oxygen gas (O₂) to produce gaseous carbon dioxide (CO₂) and gaseous water (H₂O) If 0.391 g of carbon dioxide is produced from the reaction of 0.16 g of methane and 0.84 g of oxygen gas, calculate the percent yield of carbon dioxide.

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Answer : The percent yield of CO_2 is, 68.4 %

Solution : Given,

Mass of CH_4 = 0.16 g

Mass of O_2 = 0.84 g

Molar mass of CH_4 = 16 g/mole

Molar mass of O_2 = 32 g/mole

Molar mass of CO_2 = 44 g/mole

First we have to calculate the moles of CH_4 and O_2.

\text{ Moles of }CH_4=\frac{\text{ Mass of }CH_4}{\text{ Molar mass of }CH_4}=(0.16g)/(16g/mole)=0.01moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=(0.84g)/(32g/mole)=0.026moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 0.026 moles of O_2 react with (0.026)/(2)=0.013 moles of CH_4

From this we conclude that, CH_4 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of CO_2

From the reaction, we conclude that

As, 2 mole of O_2 react to give 1 mole of CO_2

So, 0.026 moles of O_2 react to give (0.026)/(2)=0.013 moles of CO_2

Now we have to calculate the mass of CO_2

\text{ Mass of }CO_2=\text{ Moles of }CO_2* \text{ Molar mass of }CO_2

\text{ Mass of }CO_2=(0.013moles)* (44g/mole)=0.572g

Theoretical yield of CO_2 = 0.572 g

Experimental yield of CO_2 = 0.391 g

Now we have to calculate the percent yield of CO_2

\% \text{ yield of }CO_2=\frac{\text{ Experimental yield of }CO_2}{\text{ Theretical yield of }CO_2}* 100

\% \text{ yield of }CO_2=(0.391g)/(0.572g)* 100=68.4\%

Therefore, the percent yield of CO_2 is, 68.4 %

How many hydrogen atoms are in the chemical formula C6H12O6

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6 carbon , 12 hydrogen 6 oxygen = 24 atoms
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How many moles of tungsten atoms are in 4.8 × 1023 atoms of tungsten?

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Answer:-  0.80 moles

Solution:- Number of atoms of tungsten are given and we are asked to calculate the moles of tungsten atoms. So, it is a atom to mole conversion and for this we use the Avogadro number.

Number of atoms are divided by Avogadro number to get the number of moles.

Avogadro number is 6.022*10^2^3 . Given number of atoms is 4.8*10^2^3 . let's divide it by Avogadro number.

4.8*10^2^3atoms((1mol)/(6.022*10^2^3atoms))

Numerator and denominator has equal exponent so it is canceled. So, we only need to divide 4.8 by 6.022 and round the answer to two sig figs as given number of atoms has only two sig figs.

4.8((1mol)/(6.022))

= 0.80 moles

Hence, there are 0.80 moles of tungsten atoms in given number of atoms.

when 200 grams of water cools from 50 c to 25 c the total amount of heat energy released by the water is?

Answers

Answer : The heat released by the eater is, 2.1* 10^4J[/tex]

Explanation :

Formula used :

Q=m* c* \Delta T

or,

Q=m* c* (T_2-T_1)

where,

Q = heat released = ?

m = mass of water = 200 g

c = specific heat of water = 4.184J/g^oC

T_1 = initial temperature  = 50^oC

T_2 = final temperature  = 25^oC

Now put all the given value in the above formula, we get:

Q=200g* 4.184J/g^oC* (25-50)^oC

Q=20920J=2.1* 10^4J[/tex]

Therefore, the heat released by the eater is, 2.1* 10^4J[/tex]

Specific Heat:
Heat Energy= Mass of substance X Specific Heat X Change in Temp. 
1. change in temp |50-25| = 25
2. specific heat of Water(H2O) = cal/g (Celsius) 1.000
heat energy= 200g X 1.000 X 25
Heat energy = 5000cal
 

Given the equation: 2Na + 2H2O → 2NaOH + H2 Which substance in this equation is a binary compound?

Answers

Answer: In the following equation, H_2O is considered as a binary compound.

Explanation: A binary compound is considered as a compound having 2 elements only. In the following chemical equation:

2Na+2H_2O\rightarrow 2NaOH+H_2

There are 2 compounds present because compound is defined as the chemical combination of two or more elements in a fixed ratio.

In the equation, compounds are: H_2O and NaOH

H_2O consists of 2 elements which are hydrogen and oxygen and hence is considered as a binary compound.

NaOH consists of 3 elements which are sodium, hydrogen and oxygen and hence, cannot be considered as a binary compound.

Define the law of conservation of charge and provide an example.Define opposite charges attract and like charges repel and provide an example.

Define Electricity along with an example.

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Answer:

Conservation of Charge is the principle that the total electric charge in an isolated system never changes. The net quantity of electric charge, the amount of positive charge minus the amount of negative charge in the universe, is always conserved.