An object of mass 1 kg contains 4 × 10²⁰ atoms. If one electron is removed for every atom of solid, the charge gained by solid in 1g is :

Answers

Answer 1
Answer:

Explanation:

To find the charge gained by the solid when one electron is removed from each of its atoms, you can follow these steps:

1. Calculate the total number of electrons in 1 gram of the solid. Since there are 4 × 10^20 atoms in 1 kg, there are (4 × 10^20 / 1000) atoms in 1 gram.

2. Multiply the number of atoms in 1 gram by the charge gained by removing one electron. Each electron has a charge of approximately -1.6 × 10^-19 coulombs.

3. The total charge gained by the solid in 1 gram is the result of the multiplication from step 2.

Let's calculate it step by step:

Number of atoms in 1 gram = (4 × 10^20 / 1000) = 4 × 10^17 atoms

Charge gained by removing one electron from an atom = -1.6 × 10^-19 C

Total charge gained by the solid in 1 gram = (4 × 10^17) × (-1.6 × 10^-19) C

Now, calculate this expression to find the charge gained by the solid in 1 gram.

Answer 2
Answer:

Final answer:

The charge gained by a solid when one electron is removed from each atom can be calculated by multiplying the charge of one electron by the number of atoms in the solid.

Explanation:

The question asks for the charge gained by a solid when one electron is removed from each atom of the solid. The charge gained by one atom can be calculated by multiplying the charge of one electron (1.602 × 10-19 C) by the number of atoms in one gram of the solid (4 × 1020 atoms/g). To find the total charge gained by the solid in 1g, we can multiply the charge gained by one atom by the number of atoms in 1g of the solid (1 mole = 6.02 × 1023 atoms).

Charge gained by one atom = 1.602 × 10-19 C

Number of atoms in 1g = 4 × 1020 atoms/g

Total charge gained by 1g of solid = Charge gained by one atom × Number of atoms in 1g

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How many moles of copper are formed when 3.8 moles of zinc are mixed with copper (II) sulfate?

Answers

CuSO₄+ Zn = Cu + ZnSO₄

1 mole Zn ---------> 1 mole Cu
3.8 mole Zn ------> ?

moles Cu = 3.8 x 1 / 1

= 3.8 moles of Cu

hope this helps!

Final answer:

When 3.8 moles of zinc are mixed with copper (II) sulfate, the same number of moles of copper will be formed.

Explanation:

To determine the number of moles of copper formed when 3.8 moles of zinc are mixed with copper (II) sulfate, we need to consider the balanced chemical equation for the reaction.

Zn + CuSO4 → Cu + ZnSO4

The stoichiometry of the reaction tells us that 1 mole of zinc reacts with 1 mole of copper sulfate to produce 1 mole of copper. Therefore, if 3.8 moles of zinc are mixed with copper sulfate, the same number of moles of copper will be formed.

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What determines the strength of an Arrhenius base?

Answers

The strength of an acid is related to the ease

Given the formula representing a compound: what is a chemical name of this compound? 2-pentene 2-pentyne 3-pentene 3-pentyne

Answers

The question is incomplete. Complete question is attached below.
..........................................................................................................................

Correct Answer: Option 1) 2-pentene

Reason:
Following are the IUPAC rules for naming the compound
1) Select the longest carbon chain. In present case longest carbon chain has 5 carbon atom. Hence, it is a pentane derivative.
2) In case of alkene, replace 'e' of alkane by 'ene'
3) Give lowest number to function group. In present case, it is double bond.

Applying above rules, the IUPAC name of compound is 2-pentene

The acidity or alkalinity of an unknown aqueous solution is indicated by its

Answers

The acidity or alkalinity of an unknown aqueous solution is indicated by its pH value. pH value determines whether something is acidic or alkaline.

Which substance is always a product when an Arrhenius acid in an aqueous solution reacts with an Arrhenius base in an aqueous solution?(1) HBr (3) KBr
(2) H2O (4) KOH

Answers

Answer: Option (B) is the correct answer.

Explanation:

According to Arrhenius, acid are the substance that produce hydrogen ions when dissolved in a solution.

For example, HBr \rightarrow H^(+) + Br^(-) shows that HBr is an Arrhenius acid.

Whereas Arrhenius bases are the substances that produce hydroxide ions when dissolved in a solution.

For example,  KOH \rightarrow K^(+) + OH^(-) shows that KOH is an Arrhenius base.

Therefore, when an Arrhenius acid in an aqueous solution reacts with an Arrhenius base in an aqueous solution then following reaction occurs.

                  HBr + KOH \rightarrow KBr + H_(2)O

Thus, we can conclude that out of the given options, KBr is the product.

The answer is (2). The question only ask the production of acid reacts with base. The acid has H+ ion and base has OH- ion. When they react, the production will always contain H2O.

A rock weighing 75.0g is placed in a graduated cylinder displacing the volume from 31.4 ml to 36.5ml. What is the density of the rock in grams /cubic centimeter.

Answers

Answer:

14.71 g/cm³

Explanation:

The density of a substance can be found by using the formula

density =  (mass)/(volume) \n

volume = final volume of water - initial volume of water

volume = 36.5 - 31.4 = 5.1 mL

But

1 mL = 1 cm³

5.1 mL = 5.1 cm³

From the question we have

density =  (75)/(5.1)  \n  = 14.705882..

We have the final answer as

14.71 g/cm³

Hope this helps you