What was concluded about the structure of the atom as the result of the gold foil experiment?(1) A positively charged nucleus is surrounded by positively charged particles.
(2) A positively charged nucleus is surrounded by mostly empty space.
(3) A negatively charged nucleus is surrounded by positively charged particles.
(4) A negatively charged nucleus is surrounded by mostly empty space.

Answers

Answer 1

Answer:

Answer is: 2) A positively charged nucleus is surrounded by mostly empty space.

Rutherford theorized that atoms have their charge concentrated in a very small nucleus.

This was famous Rutherford's Gold Foil Experiment: he bombarded thin foil of gold with positive alpha particles (helium atom particles, consist of two protons and two neutrons).

Rutherford observed the deflection of alpha particles on the photographic film and notice that most of alpha particles passed straight through foil.

That is different from Plum Pudding model, because it shows that most of the atom is empty space.

Answer 2

Answer:

The conclusion about the structure of the atom as the result of the gold foil experiment is that a positively charged nucleus is surrounded by mostly empty space. The answer is number 2. Also, he concluded that an atom was not an empty space but rather, the electrons are scattered.

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An experimental procedure requires 10 ml of acid to be dissolved into a beaker of water. An additional 5 ml of acid is added to the solution. Which statement best describes the new solution?

Answers

If we dissolve 10 mL of acid into a beaker of water. The acid will be diluted.
Since the number of moles of acid will not change, we can use this formula:
M1 V1 = M2 V2

Where M is the concentration of the acid in the solution
V1 = 10 mL
and
V2 = Vwater + 10

If we add an additional 5 mL of acid, the new concentration of the acid will be:
M = (M1 (5mL) + M2 (Vwater + 10mL)) / (5mL + Vwater + 10mL)

The concentration of acid in the new solution will increase.

Long story short, C is the answer.

According to the arrhenius theory an acid is a substance that

Answers

The Arrhenius theory established that acids and some bases: dissociate giving rise to ions.

What is the Arrhenius theory?

Arrhenius's theory was a theory of acids and bases formulated on the basis of his theory of ionization of substances in aqueous solutions.

Principles of the Arrhenius theory

Acid substances are those that dissociate into hydrogen ions in aqueous solution.

Basic substances are those that dissociate into hydroxyl ions in aqueous solution.

Therefore, we can conclude that the Arrhenius theory explains that the characteristic properties of aqueous solutions of acids are due to hydrogen ions.

Learn more about the Arrhenius theory here: brainly.com/question/3920636

Answer:

According to the theory, an Arrhenius acid is a substance that gives hydrogen ion, $H^(+)$ (or protons) as the only positively charged ions, when dissociated in water.

Explanation:

What this means is that acids increase the concentration of protons in water to form hydronium ions,as opposed to the idea that there aren't free hydrogen cations floating around in aqueous solution.

The Arrhenius definitions of acidity and alkalinity are restricted to aqueous solutions and refer to the concentration of dissolved ions.

A typical neon light contains neon gas mixed with argon gas. If the total pressure of the mixture is 1.63 atm and the partial pressure of the neon is 0.71
atm. What is the partial pressure (atm) of argon?

Answers

the partial pressure of argon is:

1.63-0.71= 0.92 atm

1.63 atm - 0.71 atm = 0.92 atm

Is amber eye color considered brown?

Answers

Hello,

Amber eye color is not considered brown. The colors in the amber eye color are golden or copper.

Thanks for using brainly.

As the activation energy of a reaction decreases, the number of molecules with at least this much energy ______________.

Answers

Answer:

Increasing

Explanation:

The melting points of canola oil, corn oil, sunflower oil, and peanut oil are 10°C, –11°C, –17°C, and –2°C. If you cool a mixture of these oils to 5°C, which one can you separate easily?

Answers

Answer: the canola oil.

Explanation:

According to the melting points reported, at 5°C canola oil, whose melting point is 10°C, will freeze (become solid), while the other three, corn oil, sunflower oil, and peanut oil, having melting points several degrees below 5°C, will remain in liquid state.

Therefore, by decantation or filtration, which are processes that permit separate solids from liquids in a mixture, you can separate easily the solid canola oil from the other three liquid oils.

After separating the canola oil, If you continue cooling the mixture and reach a temperature of - 5°C. the peanut oil, whose melting point is -2°C, whill freeze and you will be able to separate it (again by decantation or filtration).

The same operation, cooling a third time until a temperature around 12°C, will permit you to separate the remaining two oils.

As you see, the knowledge of the physical properties of the substances is a useful tool to separate mixtures.

You can separate the canola oil because it turns back into a solid state while the others remain liquid.

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Pentane, C5H12, will react as shown below:____C5H12(l) + ____O2 --- ______CO2 +_______ H2OH20(g)1. Balance the equation above by putting coefficients into each blank space.1C5H12+ 8O2----- 5CO2+ 6 H2O (this is what I got)2. How many atoms of oxygen are in 144 grams of pentane?step 1: 144g of C5H12*(1mole/72.17)= 1.995moles of C5H12step 2: 1.995moles of C5H12*(8moles of O2/1mole of C5H12)= 15.962 moles of O2step 3: 15.962 moles of O2*(6.02*10^23 atoms of O2/1mole of O2)= 9.609*10^24 atoms of O2 (I don't know if I did this right)3. How many atoms of oxygen are in 192 grams of carbon dioxide gas?step 1: 192 grams of CO2 *(1mole of CO2/44.01grams of CO2)= 4.363 moles of CO2step two: 4.36moles of CO2* ( 1 mole of O2/1mole of CO2)= step 3: 4.363* (6.02*10^23) = 2.627*10^24 atoms of O2 (I don't know if this is correct.4. A) CIRCLE ONE: True or False:reactant you begin with fewer grams of is your limiting reactant.B) If 32 g of oxygen gas and 32 g of pentane are combined, how much water will be produced, in moles? (Use your reaction from the top of the first page)NEED HELP ASAP THANK YOU!!!