Which of the following is the general term for the sequence m, -m, m, -m, . . .? A. m(-1)^(n-1)
B. (-m)^n
C. (-1)m^(n + 1)
D. (-1)m^(n - 1)

Answer:

  A. m(-1)^(n-1)

Step-by-step explanation:

The degree of m doesn't change so none of the expressions with n as an exponent of m can possibly be correct. That leaves only choice A.

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You will find that when alternating signs are required, the term (-1)^n will be a factor. An offset of ±1 can be added to the n to make the initial sign be what you want. Here we want +1 for n=1, so an exponent of (n-1) is appropriate.

Final answer:

The general term for the sequence m, -m, m, -m, ... is m(-1)^(n-1). This is correct because -1 when raised to an odd power gives -1, and when raised to an even power gives 1, ensuring alternation between m and -m.

Explanation:

The question refers to a sequence where the terms alternate between positive and negative values of m. The general term that describes such a sequence is m(-1)^(n-1).

This term works because when raised to an odd power, -1 gives -1, and when raised to an even power, -1 gives 1. Thus, the expression alternates between m and -m for different values of n.

For instance, when n is 1, the term is m; when n is 2, the term is -m; when n is 3, the term is m; and so on. Therefore, the correct answer is option A: m(-1)^(n-1).

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