Describe the conditions under which a real gas is most likely to behave ideally

Answers

Answer 1
Answer:

Answer:

  • The conditions under which a real gas is most likely to behave ideally is at low pressure and hight temperatures.

Explanation:

According to molecular kinetic theory, 1) gas particles (molecules or atoms) occupy a negligible fraction of the total volume of the gas, and 2) the force of attraction between gas molecules is zero.

Those two assumptions constitute the basis for the behavior of a gas and an ideal gas.

The lower the pressure and the higher the temperature the closer those assumptions are valid for real gases.

At low pressure, the particles of the gas will be more separated from each other and so the tiny volume they occupy will be a smaller fraction of the total volume.

At higher temperatures, the particles will have more kinetic energy, which means that they will have larger average speed, and so the forces between the molecules will count less.

So, you conclude that under low pressure and high temperatures a real gas is most likely to behave ideally.


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How many moles of oxygen atoms are present in 5 moles of Mg3(PO4)2

Answers

How many moles of oxygen atoms are present in 5 moles of Mg3(PO4)2

All you have to do is to create a ratio between the molecule and the oxygen atom.

5 moles of Mg3(PO4)2 (4x2 moles O/1 mole Mg3(PO4)2) = 40 moles of oxygen

The shortest wavelengths occur in the:red end of the spectrum
blue end of the spectrum
middle of the spectrum

The light-gathering capacity of a telescope is dependent upon the:
magnification
focal length
size of human iris
area of aperture

Answers

Answer:

1) blue end of the spectrum

2) area of aperture

Explanation:

1) The electromagnetic spectrum encompases a wide range of frequency (ν) and wavelength (λ) that includes gamma rays, x-rays, ultra violet(UV), visible, infra red (IR), microwaves and radiowaves. The wavelength increases from gamma rays to radio waves.

The wavelength perceivable by human eyes lies in the UV-visible region which extends from 380 nm in the blue to 740 nm in the red.The shortest wavelengths occur in the blue end of the spectrum which also have the highest energy. In contrast, longer wavelengths occur on the red which have lower energy.

2) The light gathering capacity of a telescope is dependent upon its area of aperture. Larger the area, greater is the light gathering power which implies that the telescope has the capability of detecting weak or faint objects.

The area of the aperture is essentially the area of the objective of the telescopic lens which is given as:

area = (\pi*D^(2)  )/(4)

where D = diameter of the lens

1) blue end of the spectrum

2) area of aperture

. SE7.12D Which of the following statements accurately represents the differences inplant and animal cells?
Only plant cells have a cell wall, chloroplasts, and a large vacuole.
Only animal cells have a cell wall, chloroplasts, and a large vacuole.
Only plant cells have a cell membrane, mitochondria, and cytoplasm.
Only animal cells have a cell membrane, mitochondria, and
cytoplasm.
CLEAR ALL

Answers

Features which are found in plant cellsonly are the chloroplast, large vacuole and cell wall.

  • Plants and animal cells consists of the following parts ; Mitochondria, cell membrane, vacuole, cytoplasm and so on.

  • The vacuole present in animal cells are much smaller than those found in plant Cells. Hence, vacuole in animal cells are called small vacuole

  • Plant cells also consists of cell wall, chloroplast and a large vacuole. All these are missing in animal cells.

Therefore, Only plant cells have "acellwall,chloroplastsandalargevacuole."

Learn more : brainly.com/question/18012076?referrer=searchResults

Only plant cells have a cell wall, chloroplasts, and a large vacuole.

I hope this helped :)

A 34.87 g sample of a substance is initially at 27.1 C. after absorbing 1071 J of heat, the temperature of the substance is 145.0 C. what is the specific heat (SH) of the substance?SH=___ J / g * C

Answers

H= (1071)/(34.87)*145\nH= (155295)/(34.87) \nH= (15529500)/(3487) \nH=4453.542

Answer: .1044 J/g*C°

Explanation: The equation you need to use for this problem is :

c= q/m* ΔT

We are given

T1= 27.1  C°

T2= 145 C°

M= 34.87g

1071 J absorbed heatt

So let's  solve specific heat

c= 1071J/ (87grams)*(145 C°- 27.1 C°)

c= 1071J/10,257.3 g*C°

c= .1044 J/g*C°

c=specific heat

A sample of sodium hydroxide (NaOH) has a mass of 160.0 g. The molar mass of NaOH is 40.00 g/mol. How many moles of NaOH does this sample contain?A) 4.000
B) 40.00
C) 160.0
D) 6,400

Answers

The correct answer is A. A  sample of sodium hydroxide (NaOH) has a mass of 160.0 g which is equal to 4 moles of NaOH. TO calculate this, we use the relation of the molar mass given. 

160.0 g NaOh ( 1 mol NaOH / 40.0 g NaOH ) = 4.000 mol NaOH
The answer is a because all you have to is 160*1/40=4.000

HELP PLEASE. Predict the new element formed when u-238 undergoes 2 alpha decay, 1 beta decay, and 1 gamma radiation. Write nuclear equation.

Answers

This hypothetical process would produce actinium-230.

Explanation

An alpha decay reduces the atomic number of a nucleus by two and its mass number by four.

There are two types of beta decay: beta minus β⁻ and beta plus β⁺.

The mass number of a nucleus stays the same in either process. In β⁻ decay, the atomic number increases by one. An electron e⁻ is produced. In β⁺ decay, the atomic number decreases by one. A positron e⁺ is produced. Positrons are antiparticles of electrons.

β⁻ are more common than β⁺ in decays involving uranium. Assuming that the "beta decay" here refers to β⁻ decay.

Gamma decays do not influence the atomic or mass number of a nucleus.

Uranium has an atomic number of 92. 238 is the mass number of this particular isotope. The hypothetical product would have an atomic number of 92 - 2 ⨯ 2 + 1 = 89. Actinium has atomic number 89. As a result, the product is an isotope of actinium. The mass number of this hypothetical isotope would be 238 - 2 ⨯ 4 = 230. Therefore, actinium-230 is produced.

The overall nuclear reaction would involve five different particles. On the reactant side, there is

  • one uranium-238 atom.

On the product side, there are

  • one actinium-230 atom,
  • two alpha particles (a.k.a. helium-4 nuclei),
  • one electron, and
  • one gamma particle (a.k.a. photon).

\;_{\phantom{2}92}^(238) \text{U} \to \;_{\phantom{2}89}^(230) \text{Ac} + \;_(2)^(4) \text{He} + \;_(2)^(4) \text{He} + \text{e}^(-) + \gamma

Consider: what would be the products if the nucleus undergoes a β⁺ decay instead?