How many millimeters are in 0.30 meters?

Answers

Answer 1
Answer:

Answer:

300

Explanation:

Multiply Length by value of 1000

Answer 2
Answer: There should be 300 millimeters in .30 meters

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What is the name of a neutral group of atoms that are held together by covalent bond (this word has 8 letters)

Answers

The word that you're looking for is either nonpolar or molecule. Both have 8 letters. A molecule is a group of atoms held together by covalent bonds, and nonpolar is used to describe a molecule in which the electrons are shared equally between the atoms. 

Water is intitally present in a state where its molecules are far apart. During a change of state it’s molecule slow down which change of state has most likely taking place

Answers

Molecules will move faster and spread apart on warmer temperatures The colder it get the slower the molecules move so naturally those water molecules are on the path to freezing

Most modern forms of transportation are powered by fossil fuels. Carbon dioxide, methane, carbon monoxide, and other gases are released into the atmosphere during the production and combustion of these fuels. How might these gases cause climatic changes? These gases have no effect on atmospheric temperatures, so they are unable to cause any type of climatic changes. These gases cause more water vapor to condense, making climates wetter than they were in the past. These gases reduce the amount of thermal energy escaping into space, effectively warming the atmosphere.

Answers

hydronic acid and oxgeyn


Upwelling is a proccess in which warm, nutrient rich water from the deep ocean rises to the surface. TRUE or FALSE.

Answers

The statement about “Upwelling is a process in which warm, nutrient rich water from the deep ocean rises to the surface” is false. It must be the cold, nutrient rich water from the deep ocean that must rise to the surface and replaces warm surface water. The cause of upwelling is when the local wind patterns blow along the northwest coast of South America causing local surface currents to move away. The warm water is then replaced by the deep cold water

Answer:

false

Explanation:

How would you prepare 250 mL of a 6.0M NaNO3 solution from a 15M NaNO3 solution?

Answers

You would need to mix 0.100 liters (or 100 mL) of the 15M NaNO3 solution with enough solvent (e.g., water) to bring the total volume to 250 mL in order to obtain a 6.0M NaNO3 solution.

To prepare 250 mL of a 6.0M NaNO3 solution from a 15M NaNO3 solution, you can use the dilution formula:

C1V1 = C2V2

Where:

C1 = concentration of the stock solution

V1 = volume of the stock solution to be used

C2 = desired final concentration

V2 = final volume of the diluted solution

In this case:

C1 (concentration of the 15M NaNO3 solution) = 15M

C2 (desired final concentration) = 6.0M

V2 (final volume of the diluted solution) = 250 mL (0.250 L)

Now, plug in the values and solve for V1 (volume of the stock solution to be used):

15M * V1 = 6.0M * 0.250 L

V1 = (6.0M * 0.250 L) / 15M

V1 = 0.100 L

Thus, you would need to mix 0.100 liters (or 100 mL) of the 15M NaNO3 solution with enough solvent (e.g., water) to bring the total volume to 250 mL in order to obtain a 6.0M NaNO3 solution.

For more such questions on solvent:

brainly.com/question/25326161

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This is pretty simple actually :) You are going to use the equation M1xV1=M2xV2 
M stands for molarity and V is volume. Plug in the information you have, and then solve for the unknown using simple algebra.  You get 6.0M NaNo3 x 250mL= 15M NaNO3 x V2. Now solve for V2. Keep in mind that you will have to use stoichiometry to convert to liters instead of liters if your answer requires it. Hope this helps! :) 

New Pressure of gas when temp is 235 k

Answers

There is not much information given so I would have to make certain assumptions. Here are the following:
1. the gas is ideal 
2. The gas is in its standard pressure and specific volume. (1atm and 22.4L/mol)
3. There is no initial temperature hence the pressure given the assumptions above is the "new" pressure. 

PV=nRT

P= (0.0821L.atm/mol K)(235)/(22.4L/mol)
P=0.861 atm (below atmospheric pressure)