CHEMISTRY HIGH SCHOOL

Which structural adaptation would help a plant survive better in a shady environment? A.
thorns

B.
small leaves

C.
large leaves

D.
brightly colored flowers

Answers

Answer 1
Answer:

Answer:C.

large leaves

Explanation: I took the test

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The melting points of canola oil, corn oil, sunflower oil, and peanut oil are 10°C, –11°C, –17°C, and –2°C. If you cool a mixture of these oils to 5°C, which one can you separate easily?

Answers

Answer: the canola oil.

Explanation:

According to the melting points reported, at 5°C canola oil, whose melting point is 10°C, will freeze (become solid), while the other three, corn oil, sunflower oil, and peanut oil, having melting points several degrees below 5°C, will remain in liquid state.

Therefore, by decantation or filtration, which are processes that permit separate solids from liquids in a mixture, you can separate easily the solid canola oil from the other three liquid oils.

After separating the canola oil, If you continue cooling the mixture and reach a temperature of - 5°C. the peanut oil, whose melting point is -2°C, whill freeze and you will be able to separate it (again by decantation or filtration).

The same operation, cooling a third time until a temperature around 12°C, will permit you to separate the remaining two oils.

As you see, the knowledge of the physical properties of the substances is a useful tool to separate mixtures.
You can separate the canola oil because it turns back into a solid state while the others remain liquid.

In which type of solution does an equilibrium always exist?

Answers

You could argue that any solution with water in it has an equilibrium in it of some sort.  If a solution is over saturated there is an equilibrium between the dissociated and solid solute (for example NaCl(s)⇄Na⁺(aq)+Cl⁻(aq) when in water).  Even if the solution is not over saturated, water always has the reaction 2H₂O(l)⇄H₃O⁺(aq)+OH⁻(aq) since water can act as both an acid and a base (this reaction is also always at equilibrium and the equilibrium constant is 1×10⁻¹⁴).

Since we usually ignore the autoionization of water (unless dealing with acid base chemistry), I think the answer your teacher is looking for is over saturated solutions.

I hope this helps.  Let me know if anything is unclear or if you need a different answer. 

The chemical symbol for sodium is
a. Sn.
b. N.
c. S.
d. Na.

Answers

For this question the answer would be D. Na is the chemical symbol for sodium.
The answer would be D.

What is the molarity of a solution where 1.00 gram of NaCl (MM 58.5 g/mol)is dissolved in enough water to make 415 mL of solution?
a. 4.12 x 10-5 M

b. 7.09 x 10-3 M

c. 4.12 x 10-2 M

d. 2.41 M

Answers

To find the molarity of the solution, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's calculate the number of moles of NaCl using its molar mass (MM):

Mass of NaCl = 1.00 gram

Molar mass of NaCl = 58.5 g/mol

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

= 1.00 g / 58.5 g/mol

≈ 0.0171 mol

Next, we need to convert the volume of the solution from milliliters (mL) to liters (L):

Volume of solution = 415 mL = 415 / 1000 L

= 0.415 L

Now, we can calculate the molarity:

Molarity (M) = moles of solute / volume of solution

= 0.0171 mol / 0.415 L

≈ 0.0412 M

Therefore, the molarity of the solution is approximately 0.0412 M.

The closest answer option is c. 4.12 x 10^-2 M.

I hope this explanation helps! Let me know if you have any further questions.

The arrangement of particles is least ordered in a sample ofa. NaCl(aq)
b. NaCl()
c. NaCl(g)
d. NaCl(s)

Answers

Answer:

The arrangement of particles is least ordered is  a > c > b > d

Explanation:

Given that,

The arrangement of particles is least ordered in a sample of NaCl.

We know that,

The least ordered arrangement are.

The form of state of particle in least ordered.

So, The least ordered arrangement will be

aqua > gas > liquid > solid

The arrangement of particles is least ordered in a sample of NaCl

NaCl(aq) > NaCl(g) > NaCl(l) > NaCl(s)

Hence, The arrangement of particles is least ordered is a > c > b > d

How does adding salt affect the freezing point of water?

Answers

One of the colligative properties of water is the freezing point depression. A colligative property is a change in the property of water due to some amount of solute. Adding salt will lower down the freezing point of water which means that more heat would be needed to bring the boil to freeze. 
When adding salt, the more you add the freezing point drops. The sodium and chlorine ions from the salt get in the way of the water molecules. This makes it harder for them to be rearranged into crystals. Salt prevents ice from staying solid because it raises the temperature .
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