4 (a2+b+c) a=-3 b=9 c=4

Answers

Answer 1

Answer: First, you should substitute a, b, and c with -3, 9, and 4, so you get 4(-3(2)+9+4)

Next, following PEMDAS, you solve everything in the (,), leaving you with 4(7).

Lastly, your answer is 28.

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Which inequality will have a shaded area below the boundary line? A. y - x > 5 B. 2x - 3y < 3 C. 2x - 3y < 7 D. 7x + 2y < 2 E. 3x + 4y > 12

Answers

Answer:
D. 7x + 2y < 2

Explanation:
The two general forma of the inequality are:
y < mx + c .........> In this case, shading is below the boundary line
y > mx + c .........> In this case, shading is above the boundary line

Since we are looking for the inequality with shading below the boundary line, therefore, we are looking for an y < mx + c format

Now, let's check the givens:
y - x > 5
Rearranging, we would get:
y > x + 5
The shading is above the boundary line. This option is incorrect

2x - 3y < 3
Rearranging, we would get:
2x - 3 < 3y
The shading is above the boundary line. This option is incorrect

2x - 3y < 7
Rearranging, we would get:
2x - 7 < 3y
The shading is above the boundary line. This option is incorrect

7x + 2y < 2
Rearranging, we would get:
2y < -7x + 2
The shading is below the boundary line. This option is correct

3x + 4y > 12
Rearranging, we would get:
4y > -3x + 12
The shading is above the boundary line. This option is incorrect

As a second solution, I attached the graphs of the 5 given functions.
Observing these graphs, we will find that the correct one is D

Hope this helps :)

When you change the inequality as the formula of y>ax+b, it is over the boundary line. While the formula is y<ax+b, it is below the boundary line. So we can get the answer is D.

If x=2+√3, find the value of x²+1/x²

Answers

$x^2+ (1)/(x^2) =x^2+2\cdot x\cdot (1)/(x) +((1)/(x))^2-2\cdot x\cdot (1)/(x) =(x+(1)/(x))^2-2\n\nx=2+ √(3) \ \ \ \Rightarrow\ \ \ x+ (1)/(x) =2+ √(3)+ (1)/(2+ √(3)) =2+ √(3)+ (2- √(3) )/((2+ √(3))(2- √(3))) =\n\n=2+ √(3) + (2- √(3) )/(4-3) =2+ √(3) +2- √(3) =4\n\nx+ (1)/(x) =4\ \ \ \Rightarrow\ \ \ (x+(1)/(x))^2-2=4^2-2=16-2=14$

x²+1/x² = $(x + 1/x)^(2)$ - 2 * x * ( 1 / x) = ( 2 + √3 + 2 - √3)^2 - 2 = 16 - 2 = 14.

Help with distance between points in geometry.Two equations given

y=-5/4x+3.5
4y+10.6=-5x

Answers

rearrange equations so they look nicer:
y = -5/4x + 7/2
4y = -4x + 14

make both equations equal 4y:
4y + 10.6 = -5/x
4y = -5/x -10.6

this means that:
-4x + 14 = -5/x - 10.6

rearrange to find x:
[multiply by x]
-4x^2 +14x = -5 - 10.6x
4x^2 - 14x + 10.6x + 5 = 0
4x^2 -3.4x + 5 = 0

use the quadratic equation: x = (-b ± √(b^2 - 4*a*c)) / 2a
for this equation, a = 4, b = -3.4 and c = 5
write the answer in the form (x - answer one) (x - answer two)
this will give either two answers. Input these into the equation 4y = -4x +14 to find the coordinates.

To find the distance between these two points:

distance = √(change in x) + (change in y)

Final answer:

To find the distance between two points using given equations, solve the equations simultaneously to find the coordinates of the points and then use the distance formula.

Explanation:

To find the distance between two points using the given equations, we first need to find the points of intersection. We can do this by solving the given equations simultaneously to find the values of x and y. Once we have the coordinates of the two points, we can use the distance formula to find the distance between them.

First, solve the given equations simultaneously to find the values of x and y.
Substitute the values of x and y into the distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2).
Calculate the distance using the given formula.

Learn more about Distance between points here:

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If f(x) and 1(x) are inverse functions of each other and f(x) = 2x+5, what is ri(8)?-1
3/2
41/8 23

Answers

Answer:

3/2

Step-by-step explanation:

A quality-control center finds that 2 out of 250 toy trains are defective. How many trains would they expect to be defective in a batch of 10,000?A.80

B.40

C.250

D.125

Answers

Its A. 10,000 divided by 250 is 40. Then multiply 40 by 2 and you get 80

10,000 / 250 = 40
40 * 2 = 80
80= A.

Of the 95 people enrolled in mathematics class, 93% are present. How many are present?

Answers

To determine the number of students who were present in the mathematics class, multiply the total number of people enrolled by the decimal equivalent of the given percentage. That is,
present = (95) x (0.93) = 88.35
Thus, there are only 88 persons present.

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