13=-5/4a PLEASEE HELP ME WITH THIS

Answers

Answer 1
Answer:

Move 4a to the other side.

13(4a) = -5

52a  = -5

a = -5/52

hope this helped :D


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Find the average rate of change from x = 7 to x = 14 for the function f(x) = 0.01(2)^x and select the correct answer below. 23.22
35.84
128
163.84

Answers

Answer: 23.22


Step-by-step explanation:

Given function: f(x)=0.01(2)^x

At x=7

f(7)=0.01(2)^7=1.28

At x=14

f(14)=0.01(2)^(14)=163.84

We know that the rate of change from x_1 to  x_2 of function is given by

=(f(x_2)-f(x_1))/(x_2-x_1)

Therefore, The rate of change of given function from x=7 to x=14

=(f(14)-f(7))/(14-7)\n\n=(163.84-1.28)/(14-7)\n\n=(162.56)/(7)\n\n=23.22

Therefore, the average rate of change from x = 7 to x = 14 for the given function is 23.22

Answer:

the answer is 23.22

Step-by-step explanation:

How many feet per hour is 200cm per minute ?

Answers

Answer:

393.7 feet per hr

Step-by-step explanation:

200cm per min

12000cm per hr

cm to feet. divide by 30.48

393.7 ft per hr

the answer is 393 feet per hour

Find the circumference of a circle whose radius is 15.4cm

Answers

r=15,4\ cm\nC=2\cdot\ \pi\ \cdot\ r\nC=2\cdot\ \pi\ \cdot\ 15,4\ cm\nC=30,8\ \pi\ cm

\pi\approx\ 3,14

C=30,8\ \cdot\ 3,14\ cm\nC=96,712\ cm


π = 3,14

c = 2.π.r
c = 2.3,14.15,4
c ≈ 96,7

What is a real situation that would be represented by
a+3

Answers

a is just a variable to cover up any number you want. a can be anything you want, such as the money in your bank account.
a+3
a=200
200+3

George jogged a total distance of 9 and 1 over 2 miles during the months of October and November. If George only jogged 1 over 4 mile every day, which expression shows the number of days he went jogging?9 and 1 over 2 multiplied by 1 over 4
9 and 1 over 2 plus 1 over 4
9 and 1 over 2 minus 1 over 4
9 and 1 over 2 divided by 1 over 4

Answers

1/4x = 9 1/2
x = (9 1/2) / (1/4)......9 and 1/2 divided by 1 over 4 <===
x = (19/2) / (1/4)
x = 19/2 * 4
x = 76/2 = 38 days is how long he went jogging

Answer:

Question:

George jogged a total distance of 9 and 1 over 2 miles during the months of October and November. If George only jogged 1 over 4 mile every day, which expression shows the number of days in which he went jogging?

We know:

He jogged 9 1/2 miles during October and November

1/4 mile every day

Answer:

9 and 1 over 2 divided by 1 over 4

2x-y ;x=5,y=1 evaluating algebraic expressions

Answers

Answer:

9

Step-by-step explanation:

2(5)-(1)

10-1

9