What is the definition of dynamics in physics

Answers

Answer 1

Answer: A part of mechanics dealing with the movement of bodies under the activity of power.

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The mass of the sun is 1.99×1030kg and its distance to the Earth is 1.50×1011m. What is the gravitational force of the sun on the earth?

Answers

In order to calculate the gravitational force of the two bodies we use the formula which is expressed as:

F = GMm/R²

where G = 6.67 x 10^-11 in SI unit, M and m are the mass of the two bodies and R is the distance between them.

F = 6.67 x 10^-11 (1.99×10^30) (6×10^24) / (1.50×10^11)²
F = 3.53×10^22N

The gravitational force of attraction acting on the earth due to sun is $\boxed{3.539*{{10}^(22)}\,{\text{N}}}$ or $\boxed{3.54*{{10}^(22)}\,{\text{N}}}$ .

Further Explanation:

The Newton’s law of Gravitation states that the gravitational force of attraction acting between two bodies is directly proportional to the product of the mass of the two bodies and inversely proportional to the square of the distance between the two bodies.

Given:

The mass of the sun is $1.99*{10^(30)}\,{\text{kg}}$ .

The distance between the Earth and the sun is $1.50*{10^(11)}\,{\text{m}}$ .

Concept:

The gravitational force of attraction between the two bodies can be represented mathematically as:

$F=\frac{{G{M_1}{M_2}}}{{{r^2}}}$

Here, $F$ is the gravitational force of attraction, $G$ is the gravitational constant, ${M_1}$ is the mass of the first body, ${M_2}$ is the mass of the second body and $r$ is the distance between them.

Since the two bodies are Sun and the Earth so the masses of the two are considered.

The mass of the Earth is $6* {10^(24)}\,{\text{kg}}$ and the value of Gravitational constant is $6.67*{10^( - 11)}\,{{{\text{N}}\cdot{{\text{m}}^{\text{2}}}}\mathord{\left/{\vphantom{{{\text{N}}\cdot{{\text{m}}^{\text{2}}}}{{\text{k}}{{\text{g}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace} {{\text{k}}{{\text{g}}^{\text{2}}}}}$ .

Substitute $6.67*{10^( - 11)}\,{{{\text{N}}\cdot{{\text{m}}^{\text{2}}}}\mathord{\left/{\vphantom{{{\text{N}}\cdot{{\text{m}}^{\text{2}}}}{{\text{k}}{{\text{g}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace} {{\text{k}}{{\text{g}}^{\text{2}}}}}$ for $G$ , $1.99*{10^(30)}\,{\text{kg}}$ for ${M_1}$ , $6* {10^(24)}\,{\text{kg}}$ for ${M_2}$ and $1.50*{10^(11)}\,{\text{m}}$ for $r$ in above equation.

$\begin{aligned}F&=\frac{{\left({6.67*{{10}^(-11)}\,}\right)*\left({1.99*{{10}^(30)}\,{\text{kg}}}\right)*\left({6*{{10}^(24)}\,{\text{kg}}}\right)}}{{{{\left({1.50*{{10}^(11)}\,{\text{m}}}\right)}^2}}}\n&=\frac{{7.964*{{10}^(44)}}}{{2.25*{{10}^(22)}}}\n&=3.539*{10^(22)}\,{\text{N}}\n\end{aligned}$

Therefore, the gravitational force of attraction acting on the earth due to sun is $\boxed{3.539*{{10}^(22)}\,{\text{N}}}$ or $\boxed{3.54* {{10}^(22)}\,{\text{N}}}$ .

Learn More:

1. Calculate the total force on the earth due to Venus, Jupiter and Saturn brainly.com/question/2887352

2. A rocket being thrust upward as the force of the fuel being burned pushes downward brainly.com/question/11411375

3. A 50-kg meteorite moving at 1000 m/s strikes earth. Assume the velocity is along the line brainly.com/question/6536722

Answer details:

Grade: High school

Subject: Physics

Chapter: Newton’s law of Gravitation

Keywords:

Gravitational force, attraction, newton’s law, earth, sun, mass of the sun, distance, 1.99*10^30 kg, 1.50*10^11 m, 6.67x10^-11, gravitational constant.

Before starting this problem, review Conceptual Example 3 in your text. Suppose that the hail described there comes straight down at a mass rate of m/?t = 0.030 kg/s and an initial velocity of v0 = -15 m/s and strikes the roof perpendicularly. Suppose that the hail bounces off the roof of the car with a velocity of +15 m/s. Ignoring the weight of the hailstones, calculated the force exerted by the hail on the roof. __________N

Answers

Answer:

0.9 N

Explanation:

The force exerted on an object is related to its change in momentum by:

$F=(\Delta p)/(\Delta t)$

where

F is the force exerted

$\Delta p$ is the change in momentum

$\Delta t$ is the time interval

The change in momentum can be rewritten as

$\Delta p = m(v-u)$

where

m is the mass

u is the initial velocity

v is the final velocity

So the formula can be rewritten as

$F=(m(v-u))/(\Delta t)$

In this problem we have:

$(m)/(\Delta t)=0.030 kg/s$ is the mass rate

$u=-15 m/s$ is the initial velocity

$v=+15 m/s$ is the final velocity

Therefore, the force exerted by the hail on the roof is:

$F=(0.030)(+15-(-15))=0.9 N$

Describe a situation when you might travel at a high velocity but a low acceleration

Answers

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and you doze off.

Your seat is #24-B in a passenger jet in straight and level flight,
cruising in calm air 35,000 feet above the ground, taking you to
visit your grandmother on the coast, at 500 miles per hour.

A 600 kg car is at test and then accelerated to 5m/s , what is its original kinetic energy

Answers

Answer:

0 J

Explanation:

Kinetic energy is defined as:

KE = 1/2 m v²

where m is mass and v is velocity.

The car starts at rest, so it has zero velocity. Therefore, its initial kinetic energy is 0 J.

A skier reaches the bottom of a slope with a velocity of 12 meters per second north. If the skier comes to a complete stop in 3 seconds, what is the acceleration

Answers

The skier's acceleration is 4 meter per square seconds in south direction.

What is acceleration?

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.

Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.

Acceleration is a vector quantity since it has both a magnitude and a direction.

The skier's acceleration is = change in velocity ÷ time interval

= ( final velocity - initial velocity) ÷ time interval

= (0 m/s - 12 m/s) ÷ 3 seconds

= - 4 meter per square seconds.

Hence, the skier's acceleration is 4 meter per square seconds in south direction.

Learn more about acceleration here:

brainly.com/question/12550364

#SPJ2

Answer:

A skier reaches the bottom of a slope with a velocity of 12 meters per second north. If the skier comes to a complete stop in 3 seconds. A. 36 m/s (squared) north

Explanation:

A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 60t + 6. What will the height be at t = 3 seconds?A.) 35 feet
B.) 40 feet
C.) 42 feet
D.) 45 feet

Answers

To answer the question, directly substitute the value given for t to the given function of height.
h = -16t² + 60t + 6
h = (-16)(3 s)² + (60)(3) + 6 = 42
Therefore, the height of the ball after 3 seconds is 42 ft.

Answer:

The height of the ball when it hits t = 3 seconds will be 42 feet.

Explanation:

The user above me provides a very helpful explanation, so I am only writing this in his/her/their honor for his/her/their work :D

h = -16t² + 60t + 6

h = (-16)(3 s)² + (60)(3) + 6 = 42

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