an suv is traveling at a speed of 18 m/s. If the suv has a mass of 1,550 kg, what force must be applied to stop it in 8 seconds?
Answers
Vt = 0 -> cause speed boat will stop in 8 s
m = 1550kg
t= 8s
F,,???/
Vt = Vo - a.t
0 = 18 - a.8
18 = a8
a=2,25m/s^2
F = m.a
F = 1550 . 2,25
F =3487,5N
The force that must be applied to stop the SUV in 8 seconds is approximately 3,487.5 Newtons (N).
To calculate the force required to stop the SUV, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) times acceleration (a). In this case, the acceleration is the change in velocity over time.
First, let's find the acceleration (a):
Acceleration (a) = (final velocity - initial velocity) / time
a = (0 m/s - 18 m/s) / 8 s
a = -18 m/s / 8 s
a = -2.25 m/s²
The negative sign indicates that the SUV is decelerating or slowing down.
Now, we have the acceleration (-2.25 m/s²) and the mass of the SUV (1,550 kg). We can use Newton's second law to find the force:
Force (F) = mass (m) x acceleration (a)
F = 1,550 kg x (-2.25 m/s²)
F = -3,487.5 N
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Answers
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