I Need The Answer QuickJessica's employer pays the employee's at his store "time and a half" for overtime when they work more than 40 hours per week. Jessica's regular hourly wage is $7.50 and she worked 48 hours this week.

Jessica's gross pay will be: $______

Answers

Answer 1

Answer: You could have found the answer in less time than it took you to post the question.

-- Jessica's hourly rate is $7.50 per hour for the first 40 hours,

-- It's (1.5 x $7.50) for each hour over 40 hours.

-- Jessica earned (40 x $7.50) for the first 40 hours.

-- She earned (1.5 x $7.50) for each of the next 8 hours.

First multiplyum, then addum up.

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Write the equation of a parabola, in standard form, that goes through these points: (0, 3) (1, 4) (-1, -6)

Answers

Hello,

P:y=ax²+bx+c is the equation.

(0,3)∈P==>3=a*0+b*0+c==>c=3
(1,4)∈P==>4=a+b+3==>a+b=1 (1)
(-1,-6)∈P==>-6=a-b+3==>a-b=-3 (2)

(1)+(2)==>2a=-2==>a=-1
(1)==>b=1-(-1)==>b=2

y=x²+2x+3
y=(x+1)²+2
Vertex is (-1,2)

Write the standard form of the line with x- intercept of 3 and y-intercept of 4

Answers

it would be y=-4/3x+4

which in standard form is 4x+3y=12

An underwater canyon begins at 40 feetbelow sea level and is 105 feet deep.
What is the elevation of the bottom of
the canyon?

Answers

Answer:

145 feet.

Step-by-step explanation:

Given that:

An underwater canyon begins at depth = 40 ft

Depth of canyon = 105 ft

To find:

The elevation of the bottom of the canyon = ?

Solution:

Kindly refer to the image attached for the given dimensions.

A is the sea level.

B is the point at which the canyon starts and

C is the bottom of the canyon.

As per question statement, we are given that:

AB = 40 feet

BC = 105 feet

And we have to find the distance AC = ?

It is clearly observable that:

$AC = AB + BC\n\Rightarrow AC = 40 + 105\n\Rightarrow \bold{AC = 145 ft}$

So, the elevation of the bottom of the canyon is 145 ft.

Find the distance between (–3, –3) and (6, 12). Round the answer to the nearest hundredth, if necessary.

Answers

$A=(x_A;y_A)\ \ \ and\ \ \ B=(x_B;y_B)\n\n \Rightarrow\ \ \ |AB|= √((x_A-x_B)^2+(y_A-y_B)^2) \n----------------------\n\nA=(-3;-3);\ \ \ B=(6;12)\n\n|AB|= √((-3-6)^2+(-3-12)^2) =\n\n.\ \ \ \ \ \ = √(81+225) = √(306) =3 √(34) \approx17.49$

$(-3, -3), \ \ (6, 12)\n \ndistance \ formula : \n \nd =\sqrt{(x_(2)-x_(1))^2 +(y_(2)-y_(1))^2} \n \nd =√((6-(-3))^2 +(12-(-3) )^2) =√((6+3)^2 +(12+3 )^2) =√(9^2+15^2)=\n \n=√(81+225)=√(306)=√(9\cdot 34)=3√(34)=3\cdot 5.83= 17.49$

Factor the expression y2+6y-16