Smither thinks that a special juice will increase the productivity of workers. He creates two groups of 50 workers and assigns each group the same task (in this case, they’re supposed to staple a set of papers). Group A is given the special juice to drink while they work. Group B is not given the special juice. After an hour, Smither counts how many stacks of papers each group has made. The above experiment could be made more valid by _____. Choose the best answer • running a pretrial or using existing data from a time when nobody drinks the juice as a baseline. • increasing the number of groups to 4 with 25 people in each group. • using coconut water instead of juice. • testing the subjects for longer periods of time

Answers

Answer 1
Answer:

Answer:

The experiment could be made more valid by:

• Running a pretrial or using existing data from a time when nobody drinks the juice as a baseline.

This option would help establish a baseline productivity level for the workers before introducing the special juice. By comparing the performance of Group A (given the special juice) with the baseline performance, it would be easier to determine whether the special juice indeed had an impact on productivity. This approach helps control for any external factors that may affect productivity, making the experiment more valid and the results more reliable.

Answer 2
Answer: The best answer is: running a pretrial or using existing data from a time when nobody drinks the juice as a baseline.
This would make the experiment more valid because it establishes a baseline for comparison. By comparing the productivity of both groups with no juice consumption, any differences observed in productivity between Group A (given the special juice) and Group B (not given the special juice) can be more confidently attributed to the juice itself rather than other factors. This helps to ensure that any observed effects are indeed caused by the special juice and not due to other variables or random chance.

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20 ÷ 4 = 5 (?) heh (O.o)

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Answers

cos \alpha +cos \beta =2\cdot cos ( \alpha + \beta )/(2) \cdot cos ( \alpha - \beta )/(2)\n-----------------\n\n \alpha =3x\ \ \ and\ \ \  \beta =x\n\n

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Aisha owns an apparel store. She bought some shirts and jeans from a wholesaler for $3,900. Each shirt cost $12 and each pair of jeans cost $28. If she sold the shirts at 70% profit and jeans at 125% profit, her total profit was $3,885. How many shirts and jeans did she buy from the wholesalers?

Answers

Let

x------->  the number of shirts

y------>  the number of jeans

we know that

12x+28y=3,900 -------> equation 1

If she sold the shirts at 70\% profit and jeans at 125\% profit, her total profit was \$3,885

so

1.7*(12x)+2.25*(28y)=3,900+3,885

20.4x+63y=7,785 -------> equation 2

we have the following system of equations

12x+28y=3,900 -------> equation 1

20.4x+63y=7,785 -------> equation 2

using a graph tool

see the attached figure

The solution of the system is the intersection both graphs

the solution is the point (150,75)

that means

x=150\ shirts\ny=75\ jeans

therefore

the answer is

the number of shirts is 150

the number of jeans is 75

Let the number of shirts be x, and the jeans be y.

Total cost of shirts = 12x
Total cost of Jeans = 28y

This means that:        12x + 28y = 3900..........(a)

Selling price for Shirts 70% profit, means = 100% + 70% = 170% of the cost price

170/100  * 12x = 1.7*12x = 20.4x 

Selling price for Jeans 125% profit, means = 100% + 125% = 225% of the cost price

225/100  * 28y = 2.25*28y = 63y

Total profit = 3885, remember total cost = 3900

Total selling price = 3885 + 3900 = 7785

20.4x + 63y = 7785..........(b)


12x + 28y = 3900.............(a)

20.4x + 63y = 7785...........(b)

Solving the simultaneous equation with a programmable calculator:

x = 150, y = 75

150 shirts and 75 jeans.

A(x)=(2x-5)(x+1)-(5x-3)(2x-5)

Answers

Answer:

-8x² + 28x - 20

Step-by-step explanation:

To simplify the expression A(x) = ( 2x - 5 )( x + 1 ) - ( 5x - 3 )( 2x - 5 ), you can start by using the distributive propertyto expand both sets of parentheses and then combine like terms:

A ( x ) = ( 2x - 5 ) ( x + 1 ) - ( 5x - 3 ) ( 2x - 5 )

  • Expand the first set of parentheses.

( 2x - 5 ) ( x + 1 )

2x ( x ) + 2x ( 1 ) - 5 ( x ) - 5 ( 1 )

2x² + 2x - 5x - 5

  • Now, expand the second set of parentheses.

( 5x - 3 ) ( 2x - 5 )

5x ( 2x ) + 5x ( -5 ) - 3 ( 2x ) - 3 ( -5 )

10x² - 25x - 6x + 15

  • Now, let's combine like terms within each part.

2x² + 2x - 5x - 5 - ( 10x² - 25x - 6x + 15)

  • Distribute the negative sign to both terms in the second parentheses.

2x² + 2x - 5x - 5 - 10x² + 25x + 6x - 15

  • Combine like terms in the entire expression.

( 2x² - 10x² ) + ( 2x - 5x + 25x + 6x ) + ( -5 - 15 )

  • Simplify further.

-8x² + 28x - 20

A ( x ) = -8x² + 28x - 20