A rectangular prism has a base of 18 cm by 15 cm and a diagonal of 25 cm. Identify its height. Round to the nearest tenth. HELP PLEASE! I don't understand this question!!

Answers

Answer 1
Answer:

Answer:

8.7 cm

Step-by-step explanation:

You know the relationship between the diagonal of a rectangular prism and the sides as d^2 = x^2 + y^2 + z^2 where x, y and z are the three dimensions of the prism. from your data, 25^2 =18^2 + 15^2 + z^2 or z^2 = 25^2 -18^2 - 15^2. With some simple calculation you getz^2 = 625 - 324 - 225 = 76, or z= 8.7178....


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Identify the factors of the terms of the expression 5+6a+11b

Answers

5 + 6a + 11b

terms: 5; 6a; 11b

Factors of 5: 1; 5
Factors of 6a: 1; 2; 3; 6; a; 2a; 3a; 6a
Factors of 11b: 1; 11; b; 11b

Find the vertex, focus, directrix, and focal width of the parabola. x = 4y2.

Answers

- Vertex : ( 0, 0 ).
- Focus: ( p/2, 0 );
y² = 1/4 x
y² = 2 p x  ⇒ 2 p = 1/4
p = 1/8
p/2 = 1/16
F ( 1/16, 0)
- Directrix:
x = - p/2 x
x = - 1/16 x
- The focal length:
2 p = 2 · 1/8 = 1/4

Answer:

The vertex is (0,0), focus of the parabola is ((1)/(16),0), directrix of the parabola is y=-(1)/(16), focal width is (1)/(4).

Step-by-step explanation:

The given equation of parabola is

x=4y^2

It can be written as

y^2=(1)/(4)x           ....(1)

The general equation of parabola is

(y-k)^2=4p(x-h)           ... (2)

Where, (h,k) is vertex, (h+p,k) is focus, y=h-p is directrix and |4p| is focal width.

On comparing (1) and (2), we get

h=0,k=0

The vertex is (0,0).

4p=(1)/(4)

p=(1)/(16)

Focus of the parabola is

(h+p,k)=(0+(1)/(16),0)=((1)/(16),0)

Therefore focus of the parabola is((1)/(16),0).

Directrix of the parabola is

y=h-p=0-(1)/(16)=-(1)/(16)

Directrix of the parabola isy=-(1)/(16).

Focal width is

|4p|=|4* (1)/(16)|=(1)/(4)

Focal width is(1)/(4).

Determine whether the vectors u and v are parallel, orthogonal, or neither. u = <7, 2>, v = <21, 6>

Answers

Vectors are orthogonal if their dot product is equal to zero:
u · v = 7· 21 + 2 · 6 = 147 + 12 = 159 ≠ 0
Vectors are parallel if the angle between them is 0°, or cos ( u, v ) = 1
cos  ( u, v ) = ( u · v ) / ( | u | · | v | ) =
= 159 / (√(7² + 2²) · √(21² + 6²) ) =
= 159 / ( √ (49 + 4 ) · √ ( 441 + 36 ) ) = 
= 159 / (√53 · √477 ) = 159 / 159 = 1
Answer : The vectors u and v are parallel. 

Answer:

Parallel

Step-by-step explanation:

orthogonal: dot product of u times v= 0 degrees

utimesv= 7x21+2x6=147+12=159

Parallel: cos (u,v)=1

cos (u,v)=(u·v)/ IuI·IvI

cos (u,v)= 159/ (sqrt 7^2+2^2)·(sqrt 21^2 +6^2)

159/(sqrt 49+4) ·(sqrt 441+36)

159/(sqrt 53)·(sqrt 477)=

159/159

=1; therefore it is parallel

The path of a roller coaster after it has reached the top of the first hill follows a polynomial function as shown in the graph below....

Answers

The interval that f(x) is increasing is the distance from 200 to 300.
The minimum value of f(x) in the interval 0<x<300 is 200.
At a value of 500, the value of f(x) is 0.
The function can't be a quadratic function since there are two points in the graph where f(x) changes its rate from increasing to decreasing or the opposite. A quadratic function has only one of that point.
Hello there.

The path of a roller coaster after it has reached the top of the first hill follows a polynomial function as shown in the graph below....

Option A

Help me solve this problem please

Answers

Answer:

y = -2x + 17

Step-by-step explanation:

y has to equal 5:

incorrect

y = -2x - 17

y = -2(6) - 17

y = -12 - 17

y = -29

incorrect

y = -2x - 16

y = -2(6) - 16

y = -12 - 16

y = -28

incorrect

y = -2x + 16

y = -2(6) + 16

y = -12 + 16

y = 4

correct

y = -2x + 17

y = -2(6) + 17

y = -12 + 17

y = 5

How do i work out:
(y+3) (y-3)
------- = --------- + 2
4 5

Answers

y=13

(when you have fractions like the one in this problem, you get rid of them by multiplying both sides by the denominator.)