What number should be added to both sides of the equation to complete the square?x2 + 12x = 11

Answers

Answer 1
Answer: given:
x² + 12x = 11

perfect square:

a² + 2ab + b²

a² = x² ⇒ x * x
2ab = 12x ⇒ 2(6)x
b² = 6² ⇒ 36

x² + 12x + 36 = 11 + 36

(x+6)(x+6) = 47

Both sides must be added with 36.
Answer 2
Answer:

Answer:

36.

Step-by-step explanation:

We have been given an equation x^2+12x=11 and we are asked to find the number that should be added to both sides of the equation to complete the square.

To complete the square we divide the constant with x term by two and add the square of that number to both sides of equation to complete the square.

((b)/(2))^2

We can see that constant of x term is 12, so let us divide 12 by 2.

(12^2)/(2^2)

(144)/(4)

36

Therefore, we should add 36 to both sides of our equation to complete the square.

After adding 36 to both sides of our equation we will get,

x^2+12x+36=11+36

x^2+12x+6^2=47

(x+6)^2=47


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How do you find the perimeter of a triangle?

Answers

To find the perimeter you need to add all 3 sides
Yes, the user Marient is right.

You must add all of the lengths of each side to find the primeriter.

This goes for every shape. :)

A 2 by 3 rectangle contains 8 squares. can you see how?

Answers

The number of squares in a 2 by 3 rectangle is 8 by counting squares in the figure. In total, there are 8 squares.

Given that 2 by 3 rectangle contains 8 squares.

To understand why there are 8 squares in a 2 by 3 rectangle, let's break it down. A square can be formed by using any side of the rectangle as its base. In a 2 by 3 rectangle, there are 2 rows and 3 columns. We can consider each row and column as the side length of a square.

Starting with the smaller squares, we have four 1 by 1 square. These squares are formed by taking each cell of the rectangle as a base. Next, we have two 2 by 2 squares, one in the top left and one in the bottom right corner. These squares are formed by taking the top left and bottom right 2 by 2 cells as their bases.

Finally, there are two larger squares that can be formed in a 2 by 3 rectangle. One is a 2 by 3 square that occupies the entire rectangle. The other is a 3 by 3 square, formed by taking the top three cells of the first column and the bottom three cells of the second column as its bases.

So, in total, there are 8 squares that can be formed within a 2 by 3 rectangle.

Learn more about squares and rectangle here:

brainly.com/question/17508193

#SPJ2

Step-by-step explanation:

A kite, flying 50 feet high in the air is attached by a string to a stake in the sand. How long is the string to the nearest tenth of a foot?a) 50.0 feet
b) 70.7 feet
c) 86.6 feet
d) 100.0 feet ...?

Answers

Height of the kite from the ground = 50 feet
Angle at which the kite is flying = 45 degrees
Let us assume the length of the string = x feet
Then
x = 50 * (square root 2)
   = 50 * 1.414
   = 70.7 feet
From the above deduction, it can be concluded that the correct option among all the options that are given in the question is the second option or option "b". 

Answer:

the answer is b) 70.7 feet

Step-by-step explanation:

thank you for amazing answers on the board.

Does the circle with center c(0,5) that passes through the point a(6,2) also pass through the point b(-3,11)?

Answers

Hello,
Answer Yes.

|CA|²=(6-0)²+(2-5)²=36+9=48

|CB|²=(-3-0)²+(11-5)²=9+36=45


Please someone help me i do not know the answer

Answers

Answer:

For #9, the part of the expression that represents the quotient is the division problem in parenthesis. Specifically, "(45 ÷ 9)". I believe you only need the division symbol for this, though. Correct me if I'm wrong.

As for #10, the part of the expression representing the product of two factors is 5.2 being multiplied by the variable u. This results in the the term 5.2u, with the coefficient being 5.2 and the variable being u.

Identify the vertex of the quadratic function in standard form y=2x^2 -16x+31

Answers

Answer:

(4,1)

Step-by-step explanation:

The vertex of the quadratic can be found using -b/2a. The vertex is the point (-b/2a, f(-b/2a)).

To find the x coordinate of the quadratic, define its a,b, and c. The quadratic has a = 2, b=-16, and c=31. Then -b/2a is -(-16)/2(2) = 16/4 = 4.

To find the y-coordinate, input the x=4 and solve for y.

y=2(4)^2-16(4)+31\ny=2(16)-64+31\ny=32-64+31\ny=1

The vertex is (4,1).