Why does a high temperature have to be used to weld pieces of metal together

Answers

Answer 1

Answer:

because of the metling point of metals, it is difficult to just simply put metal together and have them to stay together without any type of glue or epoxy based creams.

wielding is used to melt the surface or even change the compound completely so they are able to combine with other metals.

same thing with atoms, you need a lot of heat, and speed to simply make salt or even copper because of the elements not really being favorable of each other.

Related Questions

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A solution contains 20.0 g of C6H12O6 (glucose) in 250 g. of water.A. what is freezing point depression of solvent?
A sample of gas has increased in temperature from 20° Celsius to 22° Celsius. Which of the following happens as the temperature of the gas goes up? The gas undergoes a phase change. The velocity of the gas particles decreases. The kinetic energy of the particles increases. An exothermic reaction is more likely to occur.
The mass spectrum of a sample of a pure element is shown above. Based on the data, the peak at 26amu represents an isotope of which of the following elements? A) Al with 13 neutrons B) Mg with 14 neutrons C) Fe with 26 neutrons D) Ti with 26 neutrons
Consider the equation: 2NO2= N2O4. Using ONLY the information given by the equation which of the following changes would increase the molar concentration at equilibrium of the product N2O4?

Draw .. the structural formula ( using c and h ) for 2- pentyne

Answers

Answer : The structural formula of 2-pentyne is shown below.

Explanation :

Structural formula : In the structural formula, the bonding and type of bonds which holds the atoms in molecule together are shown.

The given name of compound is, 2-pentyne.

A suffix '-yne' present at the end of the name represent the alkyne group.

For the number of carbon atom, we use prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.

In this compound, the parent chain is 5 membered and a triple bond is present at 2nd position of the parent chain.

Thus, the structural formula of 2-pentyne is shown below.

answer is below.........

Which of these pairs would form an ionic bond?-K and Br-C and H-H and O-Cu and Cu

Answers

The pair K and Br would form an ionic bond because K is a metal and Br is a non metal.

To answer your question about which of these pairs would form an ionic bond, let's look at each pair:

1. K (Potassium) and Br (Bromine) - K is a metal and Br is a non-metal. Metals tend to lose electrons, while non-metals tend to gain electrons. This transfer of electrons results in an ionic bond. Therefore, K and Br would form an ionic bond.

2. C (Carbon) and H (Hydrogen) - Both are non-metals, so they tend to share electrons, forming a covalent bond instead of an ionic bond.

3. H (Hydrogen) and O (Oxygen) - Both are non-metals, and they also tend to share electrons, forming a covalent bond rather than an ionic bond.

4. Cu (Copper) and Cu (Copper) - Since they are the same element and both are metals, they do not form an ionic bond.

In summary, the pair K and Br would form an ionic bond.

To understand what is ionic bond : brainly.com/question/957239

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Compared to the freezing point of 1.0 M KCl(aq) at standard pressure, the freezing point of 1.0 M CaCl2(aq) at standard pressure is(1) lower
(2) higher
(3) the same

Answers

Answer : The correct option is, (1) lower

Explanation :

Formula used for lowering in freezing point :

$\Delta T_f=i* k_f* m$

where,

$\DeltaT_b$ = change in freezing point

$k_b$ = freezing point constant

m = molality

i = Van't Hoff factor

According to the question, we conclude that the molality of the given solutions are the same. So, the freezing point depends only on the Van't Hoff factor.

Now we have to calculate the Van't Hoff factor for the given solutions.

(a) The dissociation of $KCl$ will be,

$KCl\rightarrow K^++Cl^-$

So, Van't Hoff factor = Number of solute particles = 1 + 1 = 2

(b) The dissociation of $CaCl_2$ will be,

$CaCl_2\rightarrow Ca^(2+)+2Cl^-$

So, Van't Hoff factor = Number of solute particles = 1 + 2 = 3

The freezing point depends only on the Van't Hoff factor. That means higher the Van't Hoff factor, lower will be the freezing point and vice-versa.

Thus, compared to the freezing point of 1.0 M $KCl(aq)$ at standard pressure, the freezing point of 1.0 M $CaCl_2(aq)$ at standard pressure is lower.

Given the unbalanced ionic equation:3Mg + ____ Fe3+ ==> 3Mg2+ + ____ Fe
When this equation is balanced, both Fe3+ and Fe have a coefficient of
(1) 1, because a total of 6 electrons is transferred
(2) 2, because a total of 6 electrons is transferred
(3) 1, because a total of 3 electrons is transferred
(4) 2, because a total of 3 electrons is transferred

Answers

Answer: The correct answer is Option 2.

Explanation:

For the given redox reaction, magnesium is getting oxidized because it is loosing electrons and iron is getting reduced because it is gaining electrons.

The half reaction for oxidation and reduction is given by the equations:

Oxidation half reaction: $Mg\rightarrow Mg^(2+)+2e^-$ × 3

Reduction half reaction: $Fe^(3+)+3e^-\rightarrow Fe$ × 2

Net ionic reaction: $3Mg+2Fe^(3+)\rightarrow 3Mg^(2+)+3Fe$

Total number of electrons transferred are 6.

So, the correct answer is Option 2.

The answer is (2) 2, because a total of 6 electrons is transferred. We can know the electron transferred number form Mg to Mg2+ ion. There is 3 Mg involved and two electrons per atom. So total is 6,

If 5.0 liters of carbon dioxide gas are produced by the reaction below at 273 K and 1.00 atm, how many liters of oxygen gas were used in the reaction?

Answers

The balanced chemical reaction was not given. I will just assume an organic compound for this case. The balanced reaction would be:

C6H6 + 15/2O2 = 6CO2 + 3H2O

We are given the amount of carbon dioxide gas produced from the reaction. This will be the starting point of our calculation. We use the ideal gas equation to find for the number of moles.

n = PV / RT = 1.00(5L) / (0.08206 atm L/mol K ) 273 K
n= 0.2232 mol CO2

0.2232 mol CO2 (15/2 mol O2 / 6 mol CO2) ( 14.03 g CO2 / 1 mol CO2 ) = 3.9144 mol O2

V = nRT/P = 3.9144 mol O2 x 273 K x 0.08206 atm L/mol K / 1 atm
V=87.6912 L

neon is a noble gases a very stable it does not readily combined with other elements which category does neon belong to

Answers

This is a nonmetal because gases cannot be metals

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What is the ∆G for the following reaction under standard conditions (T = 298 K) for the formation of NH4NO3(s)? 2NH3(g) + 2O2(g) NH4NO3(s) + H2O(l)Given:NH4NO3(s): ∆Hf = -365.56 kJ ∆Sf = 151.08 J/K. NH3(g): ∆Hf = -46.11 kJ ∆Sf = 192.45 J/K. H2O(l): ∆Hf = -285.830 kJ ∆Sf = 69.91 J/K. O2(g): ∆Hf = 0.00 kJ ∆Sf = 205 J/K.