A husband and wife celebrate their birthdays on the same day of the month, but in different months. Every year, their birthdays fall on the same day of the week. If the husband's birthday is in March and the wife's birthday is later in the year, find the month of the wife's birthday.

Answers

Answer 1
Answer: Well, let's assume March 1st is Sunday. April 1st is Wednesday, May 1st is Saturday, June 1st is Tuesday, July 1st is Thursday, August 1st is Friday, September 1st is Sunday. So, her birthday must be in September.

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Make a conjecture about the next item in the sequence. 1, –8, –17, –26, –35a. –53
c. –46
b. –44
d. –43

Answers

the rule is substract 9
so the answer is b. -44

Find the area and the circumference of a circle with diameter 5 cm.Use the value 3.14 for it, and do not round your answers. Be sure to include the correct units in your answers.

Answers


The Circumference of the circle is
15.7

and Area is
19.625

What is x squared plus y squared equals nine

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x^2+y^2=9\n\nit's\ a\ circle\n\ncenter:(0;\ 0)\n\nradius:r=\sqrt9=3\n\nlook\ at\ the\ picture

Justin was asked to write equations based on the triangle below. So far he has come up with the following equations: Which of the following would be another correct equation?

Answers

Answer:

C: tan 60 = √3

Step-by-step explanation:

Let the adjacent part of the triangle be x and let the opposite side be y.

Thus, from trigonometric ratios;

x/10 = cos 60

We are given cos 60 = ½

Thus;

x/10 = ½

x = ½ × 10

x = 5

Similarly;

y/10 = sin 60

Now,from trigonometric relationship we know that; sin 60 = cos 30. Thus;

y/10 = cos 30

We are given cos 30 = (√3)/2

Thus;

y/10 = (√3)/2

y = 10 × (√3)/2

y = 5√3

Since it is a right angle triangle with one angle being 60°, it means the other one is 30° since sum of angles in a triangle is 180°.

Thus;

5/(5√3) = tan 30°

1/√3 = tan 30

Similarly;

5/10 = sin 60°

sin 60° = ½

Also;

tan 60 = (5√3)/5

tan 60 = √3

Also;

sin 30 = 5/10

sin 30 = ½

Looking at the options, the only correct one is Option C

Complete the equation to show two equivalent expressions.

g2 – 4g – 21 = (g – )(g + )

Answers

Answer:

g^2-4g-21=(g-7)(g+3)

Step-by-step explanation:

To complete the left side of the equation, we need to bring it to the form

(g-a)(g+b)

expanding this expression we get:

g^2+bg-ag-ab

g^2+(b-a)g-ab

Thus we have

g^2-4g-21=g^2+(b-a)g-ab

from here we see that for both sides of the equation to be equal, it must be that

b-a=-4

-ab=-21.

Getting rid of the negative signs we get:

a-b=4

ab=21

At this point we can either guess the solution to this system (that's how you usually solve these types of problems) or solve for a and b systematically.

The solutions to this set are a=7 and b=3. (you have to guess on this—it's easier)

Therefore, we have

(g-a)(g+b)=(g-7)(g+3)

which completes our equation

\boxed{ g^2-4g-21=(g-7)(g+3)}

Answer: -7 and +3

did the assignment

8k-1=15 ? Help I have a question were we have to work this out what do I do?

Answers

8k-1=15\ \ \ \ /+1\n\n8k-1+1=15+1\n\n8k=16\ \ \ \ /:8\n\n8k:8=16:8\n\nk=2
you have to add 1 to  the -1 and you will get 0.What you have to do next is also add 1 to 15 because you want a variable on one side and a number on the other.So now you have 8k=16. So you divide 8 to 8k and you get nothing divide 8 and 16 and your answer for k =2 hope you get it right.trust mw it is very easy when you get use to it