Initially, a 55.0 liter compressible container, holding 2.4 moles of a gas, exerts a pressure of 760 millimeters of mercury at a temperature of 280 Kelvin. What is the pressure when the container is compressed to 43.0 liters, the moles of gas reduces to 1.8 moles, and the temperature changes to 36 degrees Celsius?93.7 mm Hg
492 mm Hg
740 mm Hg
805 mm Hg

Answer: The correct answer is Option B.

Explanation:

Prokaryotic cells are defined as the cells which does not contain any membrane bound organelles nor they contain nucleus. They are single-celled organisms. For Example: Bacteria, archaea

Eukaryotic cells are defined as the cells which contain membrane-bound organelles. These cells also contain nucleus and also they have DNA which is contained in the nucleus. They can be single-celled or multi-celled organisms. For Example: Animal cells, Plant cells.

Archaea and cyanobacteria are the examples of prokaryotic cells and thus, will not contain nucleus or any membrane-bound organelles.

Hence, the correct answer is Option B.

The cells contain a nucleus and membrane-bound organelles is eukaryotic.

Option B is correct.

How do we explain?

Eukaryotic cells are the most complex cells and contain a nucleus and membrane-bound organelles. Prokaryotic cells, archaea, and cyanobacteria do not have a nucleus or membrane-bound organelles.

The cells that contain a nucleus and membrane-bound organelles are eukaryotic cells \Prokaryotic cells including bacteria and archaea  lack a nucleus and membrane-bound organelles. Cyanobacteria  are a type of prokaryotic bacteria, so they also lack a nucleus and membrane-bound organelles.

Therefore option B is correct

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Answer:

The pressure inside the wine bottle at 21 °C is 4.8 · 10² atm

Explanation:

Hi there!

We know that 1 mol of CO₂ is produced per mol of produced ethanol.

If the final concentration of ethanol is 13%, let´s calculate how many moles of ethanol are present at that concentration.

A concentration of 13% means that in 100 ml of solution, 13 ml is dissolved ethanol. We have 754 ml of solution, then, the volume of ethanol will be:

754 ml solution · (13 ml ethanol/100 ml solution) = 98 ml ethanol

With the density, we can calculate the mass of ethanol present:

density = mass/ volume

0.79 g/ml = mass / 98 ml

mass = 0.79 g/ml · 98 ml

mass = 77 g

The molar mass of ethanol is 46.07 g/mol, then 77 g of ethanol is equal to:

77 g · (1 mol/46.07 g) = 1.7 mol

Then, the number of moles of CO₂ produced will be 1.7 mol.

Using the equation of the ideal gas law, we can calculate the pressure of CO₂:

P = nRT/V

Where:

P = pressure

n = number of moles

R = ideal gas constant

T = temperature

V = volume

The volume will be the headspace of the bottle (840 ml - 754 ml) 86 ml = 0.086 l.

The temperature in kelvin will be: 21 + 273 = 294 K

The gas constant is 0.082 l atm / K mol

Then:

P = (1.7 mol · 0.082 l atm/K mol · 294 K)/ 0.086 l

P = 4.8 · 10² atm

The pressure inside the wine bottle at 21 °C is 4.8 · 10² atm

Final answer:

Among He, Ne, Ar, and Kr, krypton (Kr) would be most likely to form a compound with fluorine. It's one of the heavier noble gases, which can form compounds with highly reactive elements like fluorine due to their slightly less firm hold on outermost electrons.

Explanation:

The elements in Group 18 are noble gases: helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). These gases are known for their low reactivity because they have fully filled valence shells. However, the three heaviest noble gases - krypton, xenon, and radon - can react with fluorine to form fluorides, with xenon fluorides being the most well-researched among other noble gas compounds.

Among the options provided (He, Ne, Ar, Kr), krypton (Kr) would be the most likely to form a compound with fluorine. This is due to krypton's bigger size as it descends the periodic table, which slightly decreases the grip on its outermost electrons, making it marginally more likely to react with extremely reactive elements like fluorine.

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Answer:

To determine the number of constitutional isomers of C4H9Br, we can generate different structures by rearranging the atoms. The molecular formula C4H9Br implies a carbon chain with four carbon atoms, and one bromine atom.

Here are the constitutional isomers for C4H9Br:

1. **n-Butyl Bromide**: This is the straight-chain isomer where the bromine atom is attached to the end carbon atom.

2. **Isobutyl Bromide**: This is an isomer with a branched chain. The bromine atom is attached to one of the middle carbon atoms in the chain.

3. **sec-Butyl Bromide**: Another branched isomer where the bromine atom is attached to one of the middle carbon atoms but in a different position compared to isobutyl bromide.

4. **tert-Butyl Bromide**: This isomer has a highly branched structure where the bromine atom is attached to a carbon atom that is part of a tertiary (3°) carbon center.

So, there are four constitutional isomers of C4H9Br. Therefore, the correct answer is (c) Four.