The diagonals of a rhombus have lengths of 8 centimeters and 6 centimeters what's the perimeter of the rhombus

Answers

Answer 1

Answer: Diagonal 6cm = 3cm + 3cm = legs of right triangle within rhombus.
Diagonal 8cm = 4cm + 4cm = legs of right triangle within rhombus.
We need to find the side of the rhombus using the Pythagorean Theorem.
After that, we use the formula P = 4s to find your perimeter.
Let s = side of rhombus.
3^2 + 4^2 = s^2

9 + 16 = s^2
25 = s^2
5 = s
Now that we know the side of the rhombus, apply P = 4s.
P = 4(5)
P = 20cm

Answer 2

Answer: 28 is the perimeter to the rhombus.

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What is the factored form of 3c²+24c+48 ?

Answers

1st step factor 3 out of each number in the equation to get:

3(c^2+8c+16)

16 can be rewritten as 4^2 to get:
3(c^2+8c+4^2)

4+4 = 8 ( the middle number)

so the factor would be 3(c+4)^2

I have a triangle with side lengths of 2 cm, 3 cm, and 4 cm. If I have a second triangle that is similar that has a shortest side length of 4 cm, what is the longest side length?

Answers

so 2,3,4
another one is
4,x,y
the shortest is 2 and 4
4/2=2

2 time 2=4

the other triangle sides area obviously twice as large

2 times 2=4
2 times 3=6
2 times 4=8

the longest sides is 8 cm

A container is shaped like a rectangular solid with sides of 3 inches, 3 inches, and 11 inches. What is its approximate capacity, if 1 gallon equals 231 cubic inches?

Answers

It would be about 4/10 of a gallon

5x^3+15x^2+10x please help with this I need to see how its worked out not just the answer I no the answer just don't no how to work out the problem

Answers

hi!

5x^3+15x^2+10x = 0

x(5x^2+15x+10) = 0

=> x=0

5x^2+15x+10=0

5(x^2+3x+2)=0

=> (x+1) (x+2) = 0

x= -1 , x= -2

it has three answers, hope im right :)

Hey i need help please