When looking up at the clouds, you can usually make out different shapes and figures with _. cumulus clouds stratus clouds cirrus clouds altostratus clouds Desert climates can have very hot days and very cold nights. This is because _. there is usually cloud coverage there is usually a clear sky there is usually precipitation there is usually hot or cold wind

Answers

Answer 1

Answer: The answer to the question stated above is cumulus clouds.
When looking up at the clouds, you can usually make out different shapes and figures with cumulus clouds.
Cumulus low-level clouds. They are the puffy, white, cotton-top clouds that look so soft.

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With regard to the pH scale, a solution with a pH A. close to 14 is considered a strong base.
B. lower than 7 is considered basic.
C. higher than 7 is considered an acid.
D. of 6 is considered neutral.

Answers

I believe the correct response is A. A solution with a pH close to 14 is considered a strong base.

Answer:

close to 14 is considered a strong base.

Explanation:

Which of these elements is the most reactive?potassium
calcium
titanium
scandium

Answers

Answer:

Scandium

Explanation:

A solution of salt (molar mass 90 g mol-1) in water has a density of 1.29 g/mL. The concentration of the salt is 35% by mass.a. Calculate the molality of the solution.

b. Calculate the molarity of the solution.

c. Calculate the mole fraction of the salt in the solution.

Answers

The molarity of the solution is 5.018 mol/L and molality of the solution 5.9846 mol/kg.

Assume 100 g of solution the salt concentration- 35 % and water will be 65 %.

So,

mass of salt = 35 g

mass of water = 65 g

Number of moles,

$\bold {moles = \frac {mass} { molar\ mass}}$

So,

moles of salt = 35 g / 90 (g/mol) = 0.389 mole

moles of water = 65 / 18 = 3.6111 mole

Volume of solution,

$\bold {volume =\frac { mass } {density }}$

volume = 100 g / ( 1.29 g/ml)

volume of solution = 77.52 ml = 0.07752 L

$\bold {Molality = \frac {moles\ of \salt} { mass\ of\ water (kg)}}$

molality = 0.389 mol / 0.065 kg

molality = 5.9846 mol/kg

molarity = moles of salt / volume of solution (L)

molarity = 0.389 mol / 0.07752 L

molarity = 5.018 mol/L

mole fraction of salt = moles of salt / total moles

mole fraction of salt = 0.389 mol / ( 0.389 + 3.6111)

mole fraction of salt = 0.09725

To know more about Molarity,

brainly.com/question/12127540

Answer:

a) 5.9846 mol/kg

b) 5.018 mol/L

c)0.09725

Explanation:

consider 100 g of solution

now

since the salt is 35 % , water will be 65 %

now

mass of salt = 35 g

mass of water = 65 g

we know that

moles = mass / molar mass

moles of salt = 35 g / 90 (g/mol) = 0.389 mol

moles of water = 65 / 18 = 3.6111 mol

now

volume of solution = mass of solution / density of solution

volume of solution = 100 g / ( 1.29 g/ml)

volume of solution = 77.52 ml

volume of solution = 0.07752 L

a)molality = moles of salt / mass of water (kg)

molality = 0.389 mol / 0.065 kg

molality = 5.9846 mol/kg

molarity = moles of salt / volume of solution (L)

molarity = 0.389 mol / 0.07752 L

molarity = 5.018 mol/L

now

total moles in the solution = moles of salt + moles of water

total moles in the solution = 0.389 + 3.6111

total moles in the solution = 4 mol

now

mole fraction of salt = moles of salt / total moles

mole fraction of salt = 0.389 mol / 4 mol

mole fraction of salt = 0.09725

Which form of coal is used in explosives

Answers

Answer: Coal Dust

Explanation: Grounded-up coal, coal dust, is used in explosives.

Atomic energy is the energy _____. in the nucleus of an atom of electrons and their shells in chemical bonds of elements and compounds

Answers

The correct statement to fill the blank would be the first option. Atomic energy is the energy in the nucleus of an atom of electrons and their shells. From the word atomic itself, we can say that this energy is energy within and carried by the atoms.

Answer:

in the nucleus of an atom

Explanation:

Jello has a density of 1.14 g/mL. A box of Jello makes 475 mL of Jello and has 13 g of sugar. Determine the % m/m of sugar in the Jello. (Hint: d=m/v)