What type of oxygen balance does trinitrotoluene (TNT, C7H5N3O6) have?a. Negative
b. Zero
c. No right choice.

Answers

Answer 1
Answer:

a. Negative

Explanation:

We have to look at its oxidation (burning, explosion) of TNT:

4 C₇H₅N₃O₆ + 21 O₂ → 28 CO₂ + 10 H₂O + 6 N₂ + heat

So trinitrotoluene need more oxygen atoms that is have to be fully oxidized so the oxygen balance will be negative.

An empirical formula with which you calculate the oxygen balance percent (OB %) is:

OB % = (-1600 / molecular wight) × [2X + (Y/2) + M - Z)

were

X =  number of carbon atoms

Y = number of hydrogen atoms

M = number of metal atoms

Z =  number of oxygen atoms

For TNT:

OB % = (-1600 / 227.13) × [2×7 + (5/2) + 0 - 6)

OB % = -73.97 %

So the oxygen balance percent is negative.

Learn more about:

oxidation of TNT

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If air is cooled to the point at which its water vapor condenses, it has reached itsa. dew point.
b. triple point.
c. lambda point.
d. freezing point.

Answers

a. dew point, i surlly :)

Pentane, C5H12, will react as shown below:____C5H12(l) + ____O2 --- ______CO2 +_______ H2O

H20(g)

1. Balance the equation above by putting coefficients into each blank space.

1C5H12+ 8O2----- 5CO2+ 6 H2O (this is what I got)

2. How many atoms of oxygen are in 144 grams of pentane?

step 1: 144g of C5H12*(1mole/72.17)= 1.995moles of C5H12
step 2: 1.995moles of C5H12*(8moles of O2/1mole of C5H12)= 15.962 moles of O2
step 3: 15.962 moles of O2*(6.02*10^23 atoms of O2/1mole of O2)= 9.609*10^24 atoms of O2 (I don't know if I did this right)


3. How many atoms of oxygen are in 192 grams of carbon dioxide gas?

step 1: 192 grams of CO2 *(1mole of CO2/44.01grams of CO2)= 4.363 moles of CO2
step two: 4.36moles of CO2* ( 1 mole of O2/1mole of CO2)=
step 3: 4.363* (6.02*10^23) = 2.627*10^24 atoms of O2 (I don't know if this is correct.


4. A) CIRCLE ONE: True or False:

reactant you begin with fewer grams of is your limiting reactant.

B) If 32 g of oxygen gas and 32 g of pentane are combined, how much water will be produced, in moles? (Use your reaction from the top of the first page)


NEED HELP ASAP THANK YOU!!!

Answers

1) That looks right

2) Step 1: Moles=Mass/Mr, so it's 144/72= 2mol
    Step 2: Stoichiometry means the ratio of oxygen to pentane is 1:8 so moles of       oxygen is moles of pentane times 8. 2*8=16mol of oxygen
    Step 3: 16= 9.6*10^24

3) The ratio of oxygen to carbon in CO2 is 1:2
    so it's 192/3 = 64
    64*2=128g
Moles = Mass/Mr = 128/32 = 4mol = 2.41*10^24 atoms of oxygen
Basically you needed to work out the mass of oxygen using ratios before using a moles equation instead of just working with moles

4) True

5) 1C5H12+ 8O2----- 5CO2+ 6 H2O
      32g        32g

Moles of oxygen = Mass/Mr = 32/32= 1mol so you'd need 0.125mol of pentane to react fully
Moles of pentane= Mass/Mr = 32/72=0.4mol so you'd need 3.2mol of oxygen to react fully

This makes oxygen the limiting factor, because you need more of it to react fully with the pentane, so we use oxygen 

Stoichiometry means for every 8mol of oxygen there's 5mol of CO2
So, 1/8*5=0.635mol of CO2

Suppose the mole number of Ca2+ ions in a 50 mL water sample is quantified as 1.5 × 10−5 mol. What is the concentration of Ca2+ ions in the water sample in ppm CaCO3?

Answers

(1.5x 10^(-5) mol Ca^(2+))/(50ml) ( (1 mol CaC O_(3) )/(1 mol Ca^(2+) ) )( (100,000 ppm)/(1 molCaC O_(3)/L ) ) \n =0.0300234

Answer : The concentration of Ca^(2+) ions in the water sample in ppm is, 12000 ppm

Solution : Given,

Moles of calcium = 1.5* 10^(-5)moles

Molar mass of calcium = 40 g/mole

Volume of solution = 50 ml

First we have to calculate the mass of calcium.

\text{Mass of calcium}=\text{Moles of calcium}* \text{Molar mass of calcium}=(1.5* 10^(-5)moles)* (40g/mole)=60* 10^(-5)g=6000mg

(1 g = 1000 mg)

Now we have to calculate the concentration of calcium.

\text{Concentration of calcium}=\frac{\text{Mass of calcium}* 1000}{\text{Volume of solution}}=(6000mg* 1000)/(50ml)=12000mg/L=12000ppm

(1 ppm = 1 mg/L)

Therefore, the concentration of Ca^(2+) ions in the water sample in ppm is, 12000 ppm

Which of these features was formed by hotspot volcanism?The Grand Canyon
The Big Island of Hawaii
The Appalachian Mountains
The Himalaya Mountain Range

Answers

These feature that was formed by hotspot volcanism is The Big Island of Hawaii. The Hawaiian Islands are actually found at the tip of several volcanoes that has been formed by a series of volcanic eruptions. Today, the Big Island sits on the hotspot, and contains the only active volcanoes of the group of islands.
The Big Island of Hawaii was formed by hotspot volcanism, whereas The Grand Canyon, The Appalachian Mountains, and The Himalaya Mountain Range were not.

Given the potential energy diagram for areaction:
Which intervals are affected by the addition of a
catalyst?
(1) 1 and 2
(2) 1 and 3
(3) 2 and 4
(4) 3 and 4

Answers

Intervals 1 and 3 are most affected by the addition of catalyst. Option 2 is correct.

What are catalysts?

Catalysts are those compounds that reduce the activation energy for the reaction to occur, hence increasing the rate of reaction.

Activation energy is the energy that is required to start a reaction. Here, 1 represents the activation energy and 3 represents activation energy without catalyst.

Therefore, intervals 1 and 3 are most affected by the addition of catalyst.

Learn more about Catalyst:

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Answer: Option (2) is the correct answer.

Explanation:

The minimum amount of energy required by the reactants to undergo a reaction is known as activation energy.

And when we add a catalyst into a reaction then it leads to a decrease in activation energy. As a result, product formation becomes faster.

Therefore, we can conclude that intervals 1 and 3 are affected by the addition of a  catalyst.

How many grams of carbon dioxide (CO2) are found in a 11.9 L container under 1.5 atm and 20.0oC.

Answers

pV=nRT

p = 1,5atm = 1,5*101325 = 151987,5 Pa
V = 11,9l = 0,0119m3
n = ?
R = 8,314 J/mol*K
T = 20°C = 20+273 = 293K

pV=nRT
151987,5*0,0119 = n*8,314*293
1808,6513=n*2436,002  ||:2436,002
0,7425 = n >>> moles of CO2

1 mole of CO2 = 44g

1 mole of CO2--------------44g
0,7425 moles of CO2----------x
x = 32,67g of CO2