A solution of H2SO4(aq) with a molal concentration of 4.80 m has a density of 1.249 g/mL. What is the molar concentration of this solution?

Answers

Answer 1

Answer: Imagine we have mass of solvent 1kg (1000g)
According to that: $molality =n(solute) / m(solvent) =\ \textgreater \ 4.8m = 4.8mole / 1kg$
= 4.8 mole * 98 g/mole = 470g
$m(H2SO4) = n(H2SO4)*Mr(H2SO4) =\ \textgreater \$ $=\ \textgreater \ Molarity = 4.8 mole / 1.2 L = 4 M$ m(H2SO4) which is =470g

m(solution) = m(H2SO4) + m(solvent) = 470 + 1000 = 1470 g
d(solution) = m(solution) / V(solution) =>
=> 1.249 g/mL = 1470 g / V(solution) =>
$Molarity = n(solute) / V(solution) =\ \textgreater \$

Answer 2

Answer:

Answer: 4.078 M

Explanation:

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Answers

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Answers

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Answers

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Answers

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Balance the following equation. Then determine the mole ratio of Ca(OH)2:Al(OH)3.Al2(SO4)3 + Ca(OH)2 Al(OH)3 + CaSO4?
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Answers

Balanced equation:

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Check:
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Answers

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